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Please help me to solve this geometry problem

\(PQR\) is an isosceles triangle where \(PQ = PR\). \(X\) is a point on the circumcircle of \(\triangle PQR\), such that it being in the opposite region of \(P \) with respect to \(QR\). The normal drawn from the point \(P \) on \(XR\) intersects \(XR\) at point \(Y\). If \(XY = 10 \), then find the value of \(QX + RX\).

Note by Ashraful Mahin
11 months ago

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Ahmad Saad - 5 months, 2 weeks ago

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its easy. extend XR to a point M such that RM=QX. Now try proving that Y is the mid point of XM.

Aditya Kumar - 8 months, 2 weeks ago

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What have you tried?

Have you drawn a diagram? If so, what does it look like?

Calvin Lin Staff - 11 months ago

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