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$$PQR$$ is an isosceles triangle where $$PQ = PR$$. $$X$$ is a point on the circumcircle of $$\triangle PQR$$, such that it being in the opposite region of $$P$$ with respect to $$QR$$. The normal drawn from the point $$P$$ on $$XR$$ intersects $$XR$$ at point $$Y$$. If $$XY = 10$$, then find the value of $$QX + RX$$.

Note by Ashraful Mahin
1 week, 2 days ago

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Have you drawn a diagram? If so, what does it look like? Staff · 6 days, 5 hours ago