Please help with this YDSE problem.

The figure shows a YDSE set-up. The source S of wavelength λ=4000A\lambda = 4000 A^{\circ} oscillates along the y-axis according to the equation y=sin(πt)y = \sin(\pi t) where yy is in millimetres and tt is in seconds. The distance between the two slits is 0.5 mm0.5 \text{ mm}. Answer the following questions:

Q. The instant at which maximum intensity occurs at PP for the first time is:

  • 1πarcsin(59160)\dfrac{1}{\pi} \arcsin \left( \dfrac{59}{160} \right)

  • 1πarcsin(5980)\dfrac{1}{\pi} \arcsin \left( \dfrac{59}{80} \right)

  • 1πarcsin(27160)\dfrac{1}{\pi} \arcsin \left( \dfrac{27}{160} \right)

  • 1πarcsin(2780)\dfrac{1}{\pi} \arcsin \left( \dfrac{27}{80} \right)

Q. The instant at which minimum intensity occurs at PP for the first time is:

  • 1πarcsin(59160)\dfrac{1}{\pi} \arcsin \left( \dfrac{59}{160} \right)

  • 1πarcsin(5980)\dfrac{1}{\pi} \arcsin \left( \dfrac{59}{80} \right)

  • 1πarcsin(27160)\dfrac{1}{\pi} \arcsin \left( \dfrac{27}{160} \right)

  • 1πarcsin(2780)\dfrac{1}{\pi} \arcsin \left( \dfrac{27}{80} \right)

Note by Tapas Mazumdar
1 year, 5 months ago

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@Steven Chase @Mark Hennings @Md Zuhair Please help.

Tapas Mazumdar - 1 year, 5 months ago

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Question 1- (B)?

Sahil Silare - 1 year, 5 months ago

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Question 2-(D)?

Sahil Silare - 1 year, 5 months ago

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@Sahil Silare can u write the solution

A Former Brilliant Member - 1 year, 5 months ago

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I'm bad with latex but what I did was adding up the path difference from source to slits and slits to screen and then it will be equal to n(lambda) for maximum.

Sahil Silare - 1 year, 5 months ago

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