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\[ e^{i \pi } + 1 = 0 \]

is the great equation given by “EULER”.

Note by Hemanth Koundinya 9 months ago

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Complex number can be exponentially expressed as e^ix =cosx+isinx

Therefore e^ipi=cos(pi)+i sin(pi)

Since sin(pi)=0 Cos(pi)=-1

the above equation

e^i(pi)+1. => -1+1. => 0 – Hemanth Koundinya · 9 months ago

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Can you prove it? – Isaac Buckley · 9 months ago

@Isaac Buckley – You can see the brilliant wiki on this. – Satyajit Ghosh · 8 months, 4 weeks ago

@Satyajit Ghosh – Please provide a link . – Raven Herd · 8 months, 3 weeks ago

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TopNewestComplex number can be exponentially expressed as e^ix =cosx+isinx

Therefore

e^ipi=cos(pi)+i sin(pi)

Since sin(pi)=0 Cos(pi)=-1

the above equation

e^i(pi)+1. => -1+1. => 0 – Hemanth Koundinya · 9 months ago

Log in to reply

Can you prove it? – Isaac Buckley · 9 months ago

Log in to reply

– Satyajit Ghosh · 8 months, 4 weeks ago

You can see the brilliant wiki on this.Log in to reply

– Raven Herd · 8 months, 3 weeks ago

Please provide a link .Log in to reply