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Please remember euler

\[ e^{i \pi } + 1 = 0 \]

is the great equation given by “EULER”.

Note by Hemanth Koundinya
1 year, 10 months ago

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Complex number can be exponentially expressed as e^ix =cosx+isinx

Therefore
e^ipi=cos(pi)+i sin(pi)

Since sin(pi)=0 Cos(pi)=-1

the above equation

e^i(pi)+1. => -1+1. => 0

Hemanth Koundinya - 1 year, 10 months ago

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Can you prove it?

Isaac Buckley - 1 year, 10 months ago

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You can see the brilliant wiki on this.

Satyajit Ghosh - 1 year, 10 months ago

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Please provide a link .

Raven Herd - 1 year, 10 months ago

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