\[Please\quad tell\quad me\quad the\quad solution\quad of\quad the\quad \\ following\quad question:\\ \\ In\quad \triangle ABC,\quad D\quad is\quad the\quad midpoint\quad of\quad \\ side\quad BC.\quad \angle ACB\quad =\quad { 30 }^{ \circ }.\quad \angle ADB\quad =\quad 45\\ Find\quad \angle BAD.\quad \] I know how to solve it using trigo. But tell me a different method. P.S it's an eighth class question.

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TopNewestDO YOU WANT FULL SOLUTION OR JUST HINT , IF HINT , THEN TRY BY CONSTRUCTION. – Ashay Wakode · 2 years, 2 months ago

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– Rajdeep Dhingra · 2 years, 2 months ago

FULL SOLUTIONLog in to reply

– Shivam Hinduja · 2 years, 2 months ago

What's your answer, is it 120 ?Log in to reply

– Ashay Wakode · 2 years, 2 months ago

No,it's 30.Log in to reply

– Rajdeep Dhingra · 2 years, 2 months ago

Your answer is correctLog in to reply

I believe that this is an NMTC problem. You can view the solution discusssion in this problem. One approach just uses sine rule, while another approach gets more creative. – Calvin Lin Staff · 2 years, 2 months ago

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@Sandeep Bhardwaj @Calvin Lin @Steven Zheng @David Mattingly Please help – Rajdeep Dhingra · 2 years, 2 months ago

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@ashay wakode Please help – Rajdeep Dhingra · 2 years, 2 months ago

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