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$Please\quad tell\quad me\quad the\quad solution\quad of\quad the\quad \\ following\quad question:\\ \\ In\quad \triangle ABC,\quad D\quad is\quad the\quad midpoint\quad of\quad \\ side\quad BC.\quad \angle ACB\quad =\quad { 30 }^{ \circ }.\quad \angle ADB\quad =\quad 45\\ Find\quad \angle BAD.\quad$ I know how to solve it using trigo. But tell me a different method. P.S it's an eighth class question.

Note by Rajdeep Dhingra
3 years, 2 months ago

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DO YOU WANT FULL SOLUTION OR JUST HINT , IF HINT , THEN TRY BY CONSTRUCTION.

- 3 years, 2 months ago

FULL SOLUTION

- 3 years, 2 months ago

- 3 years, 2 months ago

No,it's 30.

- 3 years, 2 months ago

- 3 years, 2 months ago

I believe that this is an NMTC problem. You can view the solution discusssion in this problem. One approach just uses sine rule, while another approach gets more creative.

Staff - 3 years, 2 months ago

- 3 years, 2 months ago