Waste less time on Facebook — follow Brilliant.
×

Polynomials

If b<0,and α,β are roots of the equation 2x^2 + 6x+b=0,and satisfy α/β + β/α<K.the the value of K?

Note by Abhishek Akella
4 years, 5 months ago

No vote yet
0 votes

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

\( \frac{\alpha}{\beta} + \frac{\beta}{\alpha} \\ = \frac{\alpha^2 + \beta^2}{\alpha\beta} \\ = \frac{ (\alpha + \beta)^2 - 2\alpha\beta}{\alpha\beta} \\ = \frac{ (\frac{-6}{2})^2}{\frac{b}{2}} - 2 \\ = \frac{18}{b} - 2 < -2 (as b < 0) \\ \Rightarrow k = \fbox{-2} \)

Kushagraa Aggarwal - 4 years, 5 months ago

Log in to reply

(asb<0) wat does dis mean?

Abhishek Akella - 4 years, 5 months ago

Log in to reply

I meant that \( \frac{18}{b} < 0 \) and hence \( \frac{18}{b} - 2 < -2 \)

Kushagraa Aggarwal - 4 years, 5 months ago

Log in to reply

@Kushagraa Aggarwal kk thnxxx dude!!

Abhishek Akella - 4 years, 5 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...