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If b<0,and α,β are roots of the equation 2x^2 + 6x+b=0,and satisfy α/β + β/α<K.the the value of K?

Note by Abhishek Akella 4 years, 5 months ago

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\( \frac{\alpha}{\beta} + \frac{\beta}{\alpha} \\ = \frac{\alpha^2 + \beta^2}{\alpha\beta} \\ = \frac{ (\alpha + \beta)^2 - 2\alpha\beta}{\alpha\beta} \\ = \frac{ (\frac{-6}{2})^2}{\frac{b}{2}} - 2 \\ = \frac{18}{b} - 2 < -2 (as b < 0) \\ \Rightarrow k = \fbox{-2} \)

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(asb<0) wat does dis mean?

I meant that \( \frac{18}{b} < 0 \) and hence \( \frac{18}{b} - 2 < -2 \)

@Kushagraa Aggarwal – kk thnxxx dude!!

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Easy Math Editor

`*italics*`

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`\sin \theta`

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TopNewest\( \frac{\alpha}{\beta} + \frac{\beta}{\alpha} \\ = \frac{\alpha^2 + \beta^2}{\alpha\beta} \\ = \frac{ (\alpha + \beta)^2 - 2\alpha\beta}{\alpha\beta} \\ = \frac{ (\frac{-6}{2})^2}{\frac{b}{2}} - 2 \\ = \frac{18}{b} - 2 < -2 (as b < 0) \\ \Rightarrow k = \fbox{-2} \)

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(asb<0) wat does dis mean?

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I meant that \( \frac{18}{b} < 0 \) and hence \( \frac{18}{b} - 2 < -2 \)

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