Find the potential drop across capacitor \(C_1\)

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Find the potential drop across capacitor \(C_1\)

[hide=Try it!] Interesting Problem![/hide]

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TopNewest\( \frac{C_{2}(E_{1} +E_{2})}{C_{1} + C_{2}} \) – Jatin Yadav · 4 years ago

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Swap the positions of E2 and C2. You now have a simple voltage divider. – Jimmy Kariznov · 4 years ago

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can you please explain a bit more? – Hemang Sarkar · 4 years ago

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In steady state, charges stored in the capacitors must be same. Then, we just have to apply Kirchoff's Law. – Sambit Senapati · 4 years ago

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– Jatin Yadav · 4 years ago

Not only at steady state , but at all time instants charges stored in capacitors would be same.Log in to reply

– Advitiya Brijesh · 4 years ago

how? can you explain a bit more?Log in to reply

– Jatin Yadav · 4 years ago

\( q_{cap.} = \int\limits_0^ti_{cap.}(t) dt \). Since , \( i_{cap.}(t) \) is same for both capacitors ( as the circuit is complete ) , \(q_{cap.}\) would also be same for both at any instant .I have assumed that initial charges of both capacitors is zero. (else the question would have been tidious and answer would have been a function of time.)Log in to reply

– Sambit Senapati · 4 years ago

yes, of course.Log in to reply

nice writing :D – Rafael Muzzi · 4 years ago

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