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power proof

hey,guys,i'm practicing proofs .so, i'll be writing some proofs for the community to point out flaws, and many others to learn\[\] this are all about the golden ratios. often written as\( \phi \quad or\quad\varphi=\dfrac{1+\sqrt{5}}{2}\) first is the power proof, i.e \[\phi^n=F_{n}\phi+F_{n-1}\] where\(F_{n}\) is the nth Fibonacci number, which is defined as \[F_n=\begin{cases} 1,& n=1\\1,&n=2\\F_{n-1}+F_{n-2},&n\geq 3\end{cases}\] \[the\quad proof\] we see that it is satisfied at n=1,2. we know that \[\phi^2=\phi+1\longrightarrow \phi^n=\phi^{n-1}+\phi^{n-2}\] since \(\phi^{n-1}=F_{n-1}\phi+F_{n-2}, \phi^{n-2}=F_{n-2}\phi+F_{n-3}\), \[\begin{array} &\phi^n=\phi^{n-1}+\phi^{n-2}\\ \phi^n=F_{n-1}\phi+F_{n-2}+F_{n-2}\phi+F_{n-3}\\ \phi^n=(F_{n-1}+F_{n-2})\phi+(F_{n-2}+F_{n-3})\\ \phi^n=F_{n}\phi+F_{n-1} \end{array}\] since it satisfies all three at n,n-1,n-2.it must satisfy for all number. induction, hence proved.

Note by Aareyan Manzoor
2 years, 10 months ago

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Hello Aareyan,

Your proof is perfectly okay and completely free of any flaw.

You might also want to check out the articles we have on induction and its variants.

Good luck to you in your quest of proving things!

Mursalin Habib - 2 years, 10 months ago

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thanks,sir. i was worried about 2 cases.

Aareyan Manzoor - 2 years, 10 months ago

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You are using a variant called 'Strong induction' that uses more statements in the inductive hypothesis.

And 'sir' sounds really formal. You can call me Mursalin if you want.

Mursalin Habib - 2 years, 10 months ago

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@Mursalin Habib thanks,sir. learned something new, and sir, i learned English through formal speaking.,so it is an habit.

Aareyan Manzoor - 2 years, 10 months ago

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