Well... since everybody is making their messageboards, I thought I should make one too.

If anyone wants to talk to me, or know more about me, they can leave a comment here.

P.S - I don't think that anybody's gonna comment here anyway. Haha..

Well... since everybody is making their messageboards, I thought I should make one too.

If anyone wants to talk to me, or know more about me, they can leave a comment here.

P.S - I don't think that anybody's gonna comment here anyway. Haha..

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TopNewestHmm, I am commenting here. :P......A few questions for you. Why do you feel that Math doesn't love you? What would you call your "claim to fame"? Why is your stance on most issues a "controversial" one? (To say, the LGBT one)What do you aspire to become in the future? and the final , 5th one:- "Do you like carrots" XD .... HAVE A GREAT TIME ANSWERING THESE. – Krishna Ar · 2 years ago

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2) Achieving a Fields medal someday. \([\)Probability of this event \(=P=\displaystyle \lim_{x\to \infty} \dfrac{1}{x}]\)

3) Because I love pissing people off. In fact, that's what I do most of the time on Facebook or 9GAG or Omegle :3

4) Future? What's that? A new Pokemon that I haven't heard of?

5) Yeah... I can eat almost anything that's edible, given that it's cooked properly. – Prasun Biswas · 2 years ago

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– Krishna Ar · 2 years ago

Awesome. I loved the answers to #1) and #4). Your answer to #2) doesn't make any sense because "claim to fame" refers to something which you have already achieved! My question was what would you call as your claim to fame, and not what would you want to be called as your claim to fame.Log in to reply

– Prasun Biswas · 2 years ago

Ooh, sorry for that. Damn my poor sense of English! Anyway, the answer to your question #2 would then be, "Absolutely nothing, because I haven't done anything worthwhile in my entire life till now."Log in to reply

– Krishna Ar · 2 years ago

XD. I would've answered the same too :PLog in to reply

There are exceptions you know... for them there's a idiom in Hindi

"Apne muh miya miththu" :D

And that's the base reason why most people don't like to praise themselves or their achievements. :) – Rishabh Tripathi · 1 year, 10 months ago

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– Satvik Golechha · 2 years ago

Oh Really?!Log in to reply

– Krishna Ar · 2 years ago

Yes.Log in to reply

– Prasun Biswas · 2 years ago

Answering that second question of yours took a lot of time. The rest took only a few minutes. xDLog in to reply

Hi Prasun , I'm AA from slack. In case you want to know how me psoting the problem with the hyperqueens again went know that the staff or rather Calvin was smart enough to ban me as immediate as i went online on slack haha.

Of course i posted the problem pretty much with the same text as yesterday which was clear enough as you said. Nonetheless clarity or reason doesn't seem to be anything which I can attribute to Calvin so I suppose he will not agree but that wouldn't really matter since I am right about that problem anyway. Therefore there is no problem with me being banned by idiots. The fact that I am right and anybody would approve is enough to say so to me anyway. – A A · 3 months, 2 weeks ago

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How's life? – Chinmay Sangawadekar · 1 year, 6 months ago

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Have you ever attempted RMO? Have you qualified for it? – Swapnil Das · 1 year, 6 months ago

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In any case, I'm not good with olympiads and stuff. I'm not good with exams. Time limits scare me. :|

It's a good thing I never did attempt for RMO. I probably wouldn't have qualified for it anyway. – Prasun Biswas · 1 year, 6 months ago

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– Swapnil Das · 1 year, 6 months ago

So you want to become a mathematician?Log in to reply

– Prasun Biswas · 1 year, 6 months ago

Sure, I'd like that to happen in the near future. But, to be honest, I wonder whether I'll get that opportunity (i.e., to go into research). It's hard to do that in India, given the current socio-economic conditions of the country. Mathematical research isn't well funded here compared to most of the other countries (in my opinion).Log in to reply

– Chinmay Sangawadekar · 1 year, 6 months ago

Swapnil I think you have great interest in Physics right ?Log in to reply

– Swapnil Das · 1 year, 6 months ago

Yes! You are right! But maths too!Log in to reply

– Chinmay Sangawadekar · 1 year, 6 months ago

So Swapnil do you have interest in black holes and quantum physics and also string theory?Log in to reply

– Swapnil Das · 1 year, 6 months ago

Yes, in future I want to specialize in string theory and build the theory of everything.Log in to reply

Hi , I know that it's not in tomorrow's test but can you tell me how do you memorise the different values of \(\sin^{-1} ( sinx)\) ? – Azhaghu Roopesh M · 1 year, 10 months ago

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Now, coming onto your question, why would anyone memorize the values of \(\arcsin(\sin x)\) ? There is a nice way to calculate the values. You simply need to understand 2 things first: (1) the function \(g(x)=\arcsin(x)\) is the inverse function of \(f(x)=\sin(x)\) and, (2) Since invertible functions are bijections, the domain and range are set in such a way that the domains and ranges are continuous as well as they form bijections.

Following identities will help you:

\[\bullet\quad\arcsin(\sin x)=x~,~\textrm{iff } x\in \left[-\frac{\pi}{2},\frac{\pi}{2}\right]\\ \bullet\quad\sin(\pi-x)=\sin x\\ \bullet\quad\sin(-x)=-\sin(x)\]

There is a trick to remembering some of these identities. Just remember the following form (\(x\) is acute and \(n\) be a positive integer):

\[\sin\left(n\cdot\frac{\pi}{2}\pm x\right)=\begin{cases}\sin x~,~\textrm{if } n\textrm{ is even and the total angle in the parameter falls on 1st or 2nd quadrants}\\ -\sin x~,~\textrm{if } n\textrm{ is even and the total angle in the parameter falls on 3rd or 4th quadrants}\\ \cos x~,~\textrm{if } n\textrm{ is odd and the total angle in the parameter falls on 1st or 2nd quadrants}\\ -\cos x~,~\textrm{if } n\textrm{ is odd and the total angle in the parameter falls on 3rd or 4th quadrants}\end{cases}\]

A question naturally comes to find. Why \(\left[-\frac{\pi}{2},\frac{\pi}{2}\right]\) ? Why not any other interval? The answer is simple. We need a continuous domain for \(f(x)=\sin x\) or (say) a continuous range for \(f(x)=\arcsin(x)\) that can produce all possible values that repeat over the entire reals. Simply observing the graph of \(f(x)=\sin x\) shows that the selected interval is the best. Some may say, why not \(\left[\frac{\pi}{2},\frac{3\pi}{2}\right]\) ? It produces the same result too. The answer for that is also simple and straightforward. We try to find ranges for trigonometric functions within the principal range \([-\pi,\pi]\) so as to keep it simple.

If you say, I can provide some worked out examples later, but I won't be much active for the next few days till my internet connection is up and running again. – Prasun Biswas · 1 year, 10 months ago

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Also I do feel bad for you since you have to go to a Cyber Cafe! Btw I'm too in the same boat as you , it's just a few hours ago that I utilised 90% speed of my Internet connection . – Azhaghu Roopesh M · 1 year, 10 months ago

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this? (This is one of my best problems) – Rajdeep Dhingra · 1 year, 10 months ago

Can you solveLog in to reply

– Rajdeep Dhingra · 1 year, 10 months ago

Is this some kind of joke ?Log in to reply

Ofc , this is not a joke . I just wanted to know if there are any other interesting ways to memorise those values (currently I use the Graph to memorise it) . – Azhaghu Roopesh M · 1 year, 10 months ago

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– Rajdeep Dhingra · 1 year, 10 months ago

You use graphs to memorize values of \(\arcsin(\sin{x}) = x\)Log in to reply

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– Anurag Pandey · 1 year, 8 months ago

Is that a photo of some booklet of some iit coaching class ? Seems soLog in to reply

– Azhaghu Roopesh M · 1 year, 8 months ago

yes .Log in to reply

– Anurag Pandey · 1 year, 8 months ago

PACE?Log in to reply

Those guys have a long history of copying things off other institutes's books . – Azhaghu Roopesh M · 1 year, 8 months ago

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– Rajdeep Dhingra · 1 year, 10 months ago

Does \(\sin^{-1}\) mean \(\arcsin{x}\)Log in to reply

– Azhaghu Roopesh M · 1 year, 10 months ago

YesLog in to reply

I can't believe I wasn't able to solve this.

A person picked up 13 cards from 52 cards. Find Probability that he has no ace , Probability that he has exactly one ace ?

Please solve this \(\ddot\smile\) – Rajdeep Dhingra · 1 year, 10 months ago

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– Prasun Biswas · 1 year, 10 months ago

Are the cards drawn with replacement, i.e., are the cards refilled after each draw?Log in to reply

– Rajdeep Dhingra · 1 year, 10 months ago

NO.Log in to reply

https://brilliant.org/problems/inclined-string-on-an-incline-plane/?group=wKzP6vIjZN6D&ref_id=662387

Can you take a look at this problem. I resolved the force and got the answer as \(98 \times \cos45 \times cos25\) but in reality it was \(\frac{98 \times \cos45}{\cos25}\)

I'm still not getting how is it so. – Rishabh Tripathi · 1 year, 10 months ago

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– Rajdeep Dhingra · 1 year, 10 months ago

Its very easy. I will tell you it later on. Busy right now.Log in to reply

– Rishabh Tripathi · 1 year, 10 months ago

oh..kLog in to reply

here.

The solution isIf in future doubts comment there. – Rajdeep Dhingra · 1 year, 10 months ago

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– Rishabh Tripathi · 1 year, 10 months ago

Got it brother.Log in to reply

out!

Check thisDo re-share and participate. – Rajdeep Dhingra · 1 year, 10 months ago

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Please tell me are you really 16 ??

And besides, in which standard do you read brother.... ??

And yes, I'm asking this just because I'm of your age and unable to understand many of your solutions.. I've not even studied them yet. I'm just curious about your knowledge attainment. :) – Rishabh Tripathi · 1 year, 10 months ago

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Second of all, are you being sarcastic? Because I don't think I have any knowledge whatsoever. I just implement methods which I learnt by scouring the Internet for resources, etc in solving problems. Almost anyone who puts even a bit of self-effort into learning stuff can do that.

And finally, which solutions of mine are you unable to understand? If you can't understand a part, I expect you to make a comment there. The members of this community (including me) are always there to help others. :) – Prasun Biswas · 1 year, 10 months ago

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And apology accepted brother. In reality I was thinking that you're not gonna reply 'cause I didn't get any notification for two days.

Plus, I'm not being sarcastic man. I was really amused that if you're of my age and studying in same standard then it is an exceptional case that you can solve Level 4 and 5 questions.

I'm working to get through the problems which I'm facing. I too scour the internet and I'm trying to learn some new concepts including calculus.

Last thing, you have knowledge dude. You were the first person I followed on Brilliant.org and I've even given my fellows your example of how you despite being of our age group have a far better knowledge. – Rishabh Tripathi · 1 year, 10 months ago

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Anyway, you can mention the solutions you didn't understand here. I'll try my best to make it clear. Also, always keep in mind that your age and class doesn't determine how good you are at problem solving. Just practice as much as possible and enjoy math!

Interesting fact, when I was in class 11, I wasn't even half as smart as you are currently. – Prasun Biswas · 1 year, 10 months ago

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I get some problem in Combinatorics and Number Theory. I've leaned much in these topics after joining this site but still I want some sets of problems so that I can practice particular type of problems together and hence I'll be in a habit of solving those problems.

I write any new thing which I learn, but you know that's not enough. Without solving a good deal of questions we cannot learn something. – Rishabh Tripathi · 1 year, 10 months ago

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I noticed that your message boards empty , don't worry dude , I'll help you fill it up like I did it with my friend Deepanshu Gupta 's message board ! – Azhaghu Roopesh M · 1 year, 10 months ago

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– Prasun Biswas · 1 year, 10 months ago

Haha, don't bother. I don't really care about my messageboard. I made it just because everybody else were making one for themselves. I spend most of my time in Facebook and so I mostly chat with my friends there. I rarely check this messageboard anyway.Log in to reply

– Rajdeep Dhingra · 1 year, 10 months ago

Could you help me fill up my contest with many participants.Log in to reply

– Azhaghu Roopesh M · 1 year, 10 months ago

I just reshared it , I'll do it again tomorrow . You see finding people to participate is difficult , since I can't force them to do so . I'll keep on resharing your note , that's the only thing that I can do right now :)Log in to reply

Please Please

– Rajdeep Dhingra · 1 year, 10 months agoLog in to reply

– Azhaghu Roopesh M · 1 year, 10 months ago

I have done it :)Log in to reply

– Rajdeep Dhingra · 1 year, 10 months ago

Thanks a lot !Log in to reply

– Azhaghu Roopesh M · 1 year, 10 months ago

:)Log in to reply

Check tis out!

Please participate and reshare. – Rajdeep Dhingra · 1 year, 10 months ago

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@Prasun Biswas Pls help in the unawersed questions and check my solution in which i have tagged you. Go on my question board. – Rajdeep Dhingra · 1 year, 11 months ago

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– Prasun Biswas · 1 year, 11 months ago

I'll try to help as much as I can. But I may not be much active here for a while because my board exams are nearing.Log in to reply

hey!do you like S.S.T? – Adarsh Kumar · 2 years ago

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– Prasun Biswas · 2 years ago

S.S.T? Do you mean "Social Studies"?Log in to reply

– Adarsh Kumar · 2 years ago

yep!Log in to reply

If you'd like that in binary, then here goes: 01001000 01000101 01001100 01001100 01010011 00100000 01001110 01000001 01010111 – Prasun Biswas · 2 years ago

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– Adarsh Kumar · 2 years ago

I don't like it either!Log in to reply

– Prasun Biswas · 2 years ago

Glad to hear that! :)Log in to reply

What drives you to do Math? – Anup Navin · 2 years ago

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– Prasun Biswas · 2 years ago

Well, I do math just because I love doing it. There's no other reason whatsoever!Log in to reply

Question – Anurag Pandey · 1 year, 8 months ago

Could you please check up this problem and give me the solution.Log in to reply

– Prasun Biswas · 1 year, 8 months ago

Well, first of all, that isn't your posted problem. Secondly, I can see you haven't solved it yourself. If I gave you a solution here, wouldn't that be cheating?Log in to reply

– Anurag Pandey · 1 year, 8 months ago

When did i say i posted that question.. ? post your solution on that question itself then it wont be a cheatin ryt?Log in to reply

– Prasun Biswas · 1 year, 8 months ago

But there's already a solution posted there.Log in to reply

– Anurag Pandey · 1 year, 8 months ago

Is it ryt? Please check and tell na?Log in to reply

Please solve all my doubts on this – Rajdeep Dhingra · 1 year, 10 months ago

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