If real numbers $a, b, c, d, e$ satisfy

$a + 1 = b + 2 = c + 3 = d + 4 = e + 5 = a + b + c + d + e + 3,$

what is the value of $a^2 + b^2 + c^2 + d^2 + e^2$?

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## Comments

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TopNewestSolving the equations a=2,b=1,c=o,d=-1,e=-2.Thus the answer is 10.

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But their square is 0

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let this all be equal to k a=k-1 ,b=k-2 ,c=k-3, d=k-4 ,e=k-5 now substituting these values in last equation we get a,b,c,d,e

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I did this sum by solving each part individually i.e I obtained every part in terms of $d$ and then I solved the equation to get the answer as 10.

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10

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$\color{red}{\boxed{10}}$

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10

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10 😊

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let this all be equal to k a=k-1 ,b=k-2 ,c=k-3, d=k-4 ,e=k-5 now substituting these values in last equation we get a,b,c,d,e

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10

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10

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the answer is 10..

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Equate everything to k and substitute accordingly.The answer is 10.

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10

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10

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