Prove that k^7/7 + k^5/5 + 2 k^3/3 - k/105 is an integer for every positive integer k.

Prove that k^7/7 + k^5/5 + 2 k^3/3 - k/105 is an integer for every positive integer k.

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TopNewestare you asking how you would do it?

If so then show that it is true for k+1, then show that it is true for k=1. You will then be able to conclude that it is true for all k >0 – Danny He · 4 years, 4 months ago

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