IOQM Discussion

This discussion is mainly for the Pre-Regional Mathematics Olympiad held in India. However, anyone who wants to practice good Math questions, you are welcome! Also, I'll be mentioning some great teachers, who are known for their excellent problems!

Edit : IOQM instead of PRMO

The rules are:

  • Post problems related to PRMO.

  • Don't post repeated problems(I mean if someone has posted it already, don't post again).

  • You may check out the level of problems from Zakir Husain Sir's A Pre-RMO question (whole series!).

  • Some sample questions can also be found here.

  • Past year problems are also welcome.

  • Don't post comments not related to any problem.

  • Don't write the answers in the comments.

  • If you are not posting a problem yourself, and find a good problem in the Community(old or new), please post it here.

  • If you learnt any new concept, do share it with us!

  • Let's together do Math!

Note by Vin_Math 91
10 months, 3 weeks ago

No vote yet
1 vote

  Easy Math Editor

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Here, I learnt a great concept. Do check it out, Holder's Inequality. It is used to solve many PRMO and RMO problems.

Aryan Sanghi - 10 months, 3 weeks ago

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Nice! But it involves integrals, I have not studied them. I only know differentiation.

Vin_Math 91 - 10 months, 3 weeks ago

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I am unable to understand its proof.:-(

A Former Brilliant Member - 10 months, 2 weeks ago

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A Former Brilliant Member - 10 months, 3 weeks ago

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These question are not of prmo level. They might be of nmtc level.

A Former Brilliant Member - 10 months, 2 weeks ago

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I am not a liar :( BTW, what is ntmc?

Vin_Math 91 - 10 months, 2 weeks ago

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@Vin_Math 91 Ok,you are not.

A Former Brilliant Member - 10 months, 2 weeks ago

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Google says: National Telecommunication Monitoring Centre

Vin_Math 91 - 10 months, 2 weeks ago

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@Vin_Math 91 National mathematical contest test. It is slightly less harder than prmo.

A Former Brilliant Member - 10 months, 2 weeks ago

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@A Former Brilliant Member Oh, I searched ntmc, you wrote nmtc. I will search it. Thanks for telling!

Vin_Math 91 - 10 months, 2 weeks ago

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@A Former Brilliant Member The paper looks hard to me, though.

Vin_Math 91 - 10 months, 2 weeks ago

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@Vin_Math 91 Do you know co-ordinate geometry and locus???

A Former Brilliant Member - 10 months, 2 weeks ago

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@A Former Brilliant Member No, it is xxth chapter and I have reached x3x-3th chapter in my book. Also, I haven't studied Math from many days, I was doing my school work, which is still less than half done.

Vin_Math 91 - 10 months, 2 weeks ago

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@Vin_Math 91 That's why you find it difficult.

A Former Brilliant Member - 10 months, 2 weeks ago

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@A Former Brilliant Member National Mathematical Talent Contest, not National mathematical contest test @Kriti Kamal - Even though this is something Indian, and you will know better, I know I'm right because Google says so :)

A Former Brilliant Member - 10 months, 2 weeks ago

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@A Former Brilliant Member Yes,you are right.

A Former Brilliant Member - 10 months, 2 weeks ago

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I'm preparing for PRMO too!

Atij Jain - 10 months, 3 weeks ago

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Nice! Do share any good problems you find!

Vin_Math 91 - 10 months, 3 weeks ago

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Well, my mother is Indian, so I can wish you all good luck!

Yajat Shamji - 10 months, 3 weeks ago

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A pre rmo problem

A Former Brilliant Member - 10 months, 3 weeks ago

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I couldn't solve it, please post a solution.

Vin_Math 91 - 10 months, 3 weeks ago

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I am a bit busy now.but, i will post it before 9pm.@Siddharth Chakravarty,please if you are free then post the answer.

A Former Brilliant Member - 10 months, 3 weeks ago

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I have posted a solution. :-) @Vinayak Srivastava.

A Former Brilliant Member - 10 months, 2 weeks ago

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Check this problem, I have deleted the other one

link

Vin_Math 91 - 10 months, 3 weeks ago

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Check this problem out!

Vin_Math 91 - 10 months, 2 weeks ago

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@Vinayak Srivastava,i will post mainly geometry problems.

A Former Brilliant Member - 10 months, 2 weeks ago

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No problem!

Vin_Math 91 - 10 months, 2 weeks ago

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Do you know ceva's theorem?

A Former Brilliant Member - 10 months, 2 weeks ago

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@A Former Brilliant Member No, I'll Google it now.

Vin_Math 91 - 10 months, 2 weeks ago

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new problem

A Former Brilliant Member - 10 months, 2 weeks ago

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I answered it, good that I told you the previous question was wrong otherwise a lot of people who have got it wrong.

Siddharth Chakravarty - 10 months, 2 weeks ago

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@Siddharth Chakravarty Is anyone else getting a Brilliant glitch like thing? My notifications have disappeared and I'm only checking gmail for notifications. @Siddharth Chakravarty, @Vinayak Srivastava, @Kriti Kamal

A Former Brilliant Member - 10 months, 2 weeks ago

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@A Former Brilliant Member No, but I hate this new UI.

Siddharth Chakravarty - 10 months, 2 weeks ago

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@A Former Brilliant Member Yes, something similar is happening to my UI as well. It's full screen and I can't see any notifications as well. The solutions are also aligned to left and not in centre. Definitely something weird is happening, maybe an update?

Mahdi Raza - 10 months, 2 weeks ago

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@A Former Brilliant Member I just clicked on "View full site" in the top menu, it is as it was.

Vin_Math 91 - 10 months, 2 weeks ago

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@A Former Brilliant Member I got no other change, just that it was changed to mobile site, I changed back to full site. Are you all seeing other changes I can't?

Vin_Math 91 - 10 months, 2 weeks ago

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@Vin_Math 91 You are awesome! It worked! Turns out I was somehow in mobile site mode. LOL Thanks!

A Former Brilliant Member - 10 months, 2 weeks ago

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@A Former Brilliant Member Guys do what Vinayak said, and click View Full Site, it worked for me. @Siddharth Chakravarty, @Mahdi Raza

A Former Brilliant Member - 10 months, 2 weeks ago

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@A Former Brilliant Member Please elaborate how i can do it. This view is Very frustrating

Mahdi Raza - 10 months, 2 weeks ago

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@Mahdi Raza Ok nevermind, I got it. Thanks!!!

Mahdi Raza - 10 months, 2 weeks ago

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@Mahdi Raza The menu where you open notifications, below them, there are many buttons, click on vie full site.

Vin_Math 91 - 10 months, 2 weeks ago

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Answer to life, universe and everything: ππ×ln(π)\Large{\left \lceil{{\pi}^{\pi} \times \ln(\pi)}\right \rceil}

Vin_Math 91 - 10 months, 2 weeks ago

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Close, but not quite - 41.739323805 :)

A Former Brilliant Member - 10 months, 2 weeks ago

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I have already put the Ceiling function :)

Vin_Math 91 - 10 months, 2 weeks ago

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@Vin_Math 91 Oh! Didn't notice that :)

A Former Brilliant Member - 10 months, 2 weeks ago

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He has included ceiling function, it will be 42

Mahdi Raza - 10 months, 2 weeks ago

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@Mahdi Raza Oh! Didn't notice that :)

A Former Brilliant Member - 10 months, 2 weeks ago

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The actual answer is 101010    42101010 \implies 42 in binary

A Former Brilliant Member - 10 months, 2 weeks ago

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You mean 42 in decimal, because binary is only using 1's and 0's

Navvye Anand - 7 months, 2 weeks ago

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@Navvye Anand No, I meant that 101010 is 42 but in binary format

A Former Brilliant Member - 7 months, 2 weeks ago

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eiπ+1=0\Large e^{i \pi} + 1 = 0

This is still better than that in my opinion :)

A Former Brilliant Member - 10 months, 2 weeks ago

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We can make notes on these famous and beautiful equations LOL

A Former Brilliant Member - 10 months, 2 weeks ago

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in which grade are you

SRIJAN Singh - 10 months, 2 weeks ago

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9th grade.

Vin_Math 91 - 10 months, 2 weeks ago

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is it 42?

Navvye Anand - 7 months, 2 weeks ago

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Try this problem Future of 2020?

Aryan Sanghi - 10 months, 2 weeks ago

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okay

SRIJAN Singh - 10 months, 2 weeks ago

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@Vinayak Srivastava,@Aryan Sanghi. do this question https://brilliant.org/problems/problem-is-for-testing-skills/?ref_id=1599194

SRIJAN Singh - 10 months, 2 weeks ago

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All Indians, check out the NAEST test. Registrations last date is tomorrow 7th August.

Siddharth Chakravarty - 10 months, 2 weeks ago

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@Vinayak Srivastava @Aryan Sanghi @Kriti Kamal @Mahdi Raza क्या सभी ने इसे देखा और रजिस्टर किया?

Siddharth Chakravarty - 10 months, 2 weeks ago

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Yes, but didn't get some confirmation email except for an OTP email

Mahdi Raza - 10 months, 2 weeks ago

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@Mahdi Raza Yes, I also.

Vin_Math 91 - 10 months, 2 weeks ago

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@Vin_Math 91 The first test is on 9th August, maybe they will send prior to the test.

Siddharth Chakravarty - 10 months, 2 weeks ago

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@Aryan Sanghi,@Mahdi Raza,@Vinayak Srivastava,@Siddharth Chakravarty hey everyone do you know about some international olympiad a 8th grader especially for math or science

SRIJAN Singh - 10 months, 2 weeks ago

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Try out NSEJS and PRMO. They are meant for 8th and 9th graders. :)

Aryan Sanghi - 10 months, 2 weeks ago

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@Aryan Sanghi,Yeah in FIITJEE there are exams conducted, that you are telling..thanks

SRIJAN Singh - 10 months, 2 weeks ago

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You can try nmtc too.

A Former Brilliant Member - 10 months, 2 weeks ago

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@Kriti Kamal.thanks for your suggestion

SRIJAN Singh - 10 months, 2 weeks ago

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Try out this question by me. Infinite Geometric Geometry series!!

Aryan Sanghi - 10 months, 2 weeks ago

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This problem is not mine, but I found it good. Click Here!

Vin_Math 91 - 10 months, 2 weeks ago

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Is it 16?

Anush Rao - 5 months ago

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@Aryan Sanghi,@Vinayak Srivastava,@Mahdi Raza lookProblem 3

SRIJAN Singh - 10 months, 2 weeks ago

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@Percy Jackson hey do My first physics probb yeah

SRIJAN Singh - 10 months, 2 weeks ago

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@SRIJAN Singh, it is good that you are posting nice problems of Physics, but please give the links, as it is difficult for some people who are unfamiliar with the interface to get to it.

The procedure of giving link is quite simple:

Just use [[ and ]] brackets and in between write the link text, then open the (( bracket, paste the link, and then ))

I am giving the links for your first 2 problems, please remember this for later problems.

Problem 1

Problem 2

Keep posting good problems, keep learning!

Vin_Math 91 - 10 months, 2 weeks ago

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Thanks for your suggestion me in class 7 try my problem I posted it now

SRIJAN Singh - 10 months, 2 weeks ago

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I haven't studied circular motion. I'll try it, but I don't know the concepts.

Vin_Math 91 - 10 months, 2 weeks ago

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@Vin_Math 91 How to paste the link can you explain again

SRIJAN Singh - 10 months, 2 weeks ago

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@Srijan Singh Just open the tab and copy the url, that's it.

Vin_Math 91 - 10 months, 2 weeks ago

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@Vin_Math 91 No that i know, but how that like you have written like Problem 1

SRIJAN Singh - 10 months, 2 weeks ago

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@Srijan Singh Open the [ bracket, then type inside, and then close it ]

1
[Problem 1](https://brilliant.org/problems/my-first-physics-probb-yeah/?ref_id=1599518)

Vin_Math 91 - 10 months, 2 weeks ago

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@Vin_Math 91 Hey there I learnt look down

SRIJAN Singh - 10 months, 2 weeks ago

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@Aryan Sanghi , @Mahdi Raza,@Percy Jackson . Bore na try this

SRIJAN Singh - 10 months, 2 weeks ago

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Try more practice makes man perfect try this

SRIJAN Singh - 10 months, 2 weeks ago

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@Vinayak Srivastava try this

SRIJAN Singh - 10 months, 2 weeks ago

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@Pranshu Garba, try this

SRIJAN Singh - 10 months, 2 weeks ago

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I was going through my old notes, and found this very easy problem which 100% will get right, LOL :D

If, 1=5

2=10

3=15

4=20

5=?

Now don't comment like 2 is not equal to 10, this is a logic problem but the meaning of the 'equal to' = symbol remains the same. :D

Siddharth Chakravarty - 10 months, 2 weeks ago

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25

SRIJAN Singh - 10 months, 2 weeks ago

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Wrong 🙃

Siddharth Chakravarty - 10 months, 2 weeks ago

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5 = 1, because in the first line 1 = 5, so 5 = 1 @Siddharth Chakravarty :)

A Former Brilliant Member - 10 months, 2 weeks ago

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ah! so silly

SRIJAN Singh - 10 months, 2 weeks ago

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@Srijan Singh Ikr but I still like this problem, because it leaves everyone dumbfounded LOL

A Former Brilliant Member - 10 months, 2 weeks ago

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@A Former Brilliant Member ah! you are online

SRIJAN Singh - 10 months, 2 weeks ago

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@Srijan Singh hey @Percy Jackson do my problem

SRIJAN Singh - 10 months, 2 weeks ago

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@Srijan Singh Got all of them correct :) @SRIJAN Singh

A Former Brilliant Member - 10 months, 2 weeks ago

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@A Former Brilliant Member @Percy Jackson.show the solution:)

SRIJAN Singh - 10 months, 2 weeks ago

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@Srijan Singh I didn't post it, because someone already posted solution before me, so no use of repeating the solution @SRIJAN Singh :)

A Former Brilliant Member - 10 months, 2 weeks ago

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@A Former Brilliant Member please give me problem for doing @Percy Jackson

SRIJAN Singh - 10 months, 2 weeks ago

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@Srijan Singh Check my profile then :)

A Former Brilliant Member - 10 months, 2 weeks ago

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@A Former Brilliant Member @Percy Jackson i have done your first ten problems and got one incorrect

SRIJAN Singh - 10 months, 2 weeks ago

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Good ☺️

Siddharth Chakravarty - 10 months, 2 weeks ago

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@Siddharth Chakravarty Mine is better:    \begin{aligned} &~~~\LARGE{\cdot \cdot} \\ &\Huge{\smile} \\ \end{aligned}

Vin_Math 91 - 10 months, 2 weeks ago

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@Vin_Math 91 @Vinayak Srivastava what was your answer

SRIJAN Singh - 10 months, 2 weeks ago

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@Srijan Singh I had seen it before, so I did not answer.

Vin_Math 91 - 10 months, 2 weeks ago

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@Vin_Math 91 ah! hey can you post a good problem for me or everyone .i want to do some math practice

SRIJAN Singh - 10 months, 2 weeks ago

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@Srijan Singh @Vinayak Srivastava. pls give reply

SRIJAN Singh - 10 months, 2 weeks ago

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@Srijan Singh @SRIJAN Singh - Click Community and search for problems there, there are many interesting problems. Not everyone is online always so please be patient or search in the community. Thanks!

A Former Brilliant Member - 10 months, 2 weeks ago

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@A Former Brilliant Member i had tried many problems from community but some are not of my level

SRIJAN Singh - 10 months, 2 weeks ago

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@Srijan Singh Well, we also post problems of that level.

A Former Brilliant Member - 10 months, 2 weeks ago

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@A Former Brilliant Member ookkaayy

SRIJAN Singh - 10 months, 2 weeks ago

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@Srijan Singh hey i solved many problems from community section please give me more problems @Vinayak Srivastava,@Aryan Sanghi,@Percy Jackson,@Siddharth Chakravarty

SRIJAN Singh - 10 months, 2 weeks ago

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@Srijan Singh Dude, please stop it. It is irritating because when you mention us, 2 notifications come. @SRIJAN Singh

A Former Brilliant Member - 10 months, 2 weeks ago

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@A Former Brilliant Member hey i'm not irritating you .i'm love with maths that's why i want to do further more problems

SRIJAN Singh - 10 months, 2 weeks ago

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@Srijan Singh First thing, whether you irritate me or not is my decision, and I think you are irritating. If you love math, just make problems by searching the internet and stop mentioning me. At least ask if it is ok to mention continuously. Also, Brilliant isn't the only place to do math.

This will keep you occupied :)

A Former Brilliant Member - 10 months, 2 weeks ago

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1

Navvye Anand - 8 months ago

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What one?

SRIJAN Singh - 8 months ago

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@Srijan Singh I think he is answering Siddharth's problem, as it is clearly a reply to that. Use your brain sometimes Sing...

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@A Former Brilliant Member ... no point telling him he will probably ask what" or something like that

NSCS 747 - 8 months ago

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@Nscs 747 true lol...

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@A Former Brilliant Member He didn't replied to that to siddharth comment so how i can say?

SRIJAN Singh - 8 months ago

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@Srijan Singh Gods, don't you have a brain, coz he clearly replied that as an answer to siddharth's comment.

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@Vinayak Srivastava,@Mahdi Raza,@Aryan Sanghi,@Foolish Learner do very interesting

SRIJAN Singh - 10 months, 2 weeks ago

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@Vinayak Srivastava,@Mahdi Raza,@Aryan Sanghi,@Foolish Learner do very interesting

SRIJAN Singh - 10 months, 2 weeks ago

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first of all @Vinayak Srivastava,@Aryan Sanghi,@Siddharth Chakravarty,@Mahdi Raza,@Percy Jackson are my best friend because they give me support THANK YOU all for supporting me .

SRIJAN Singh - 10 months, 2 weeks ago

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i don't think they are your best friends... maybe friends maybe?

NSCS 747 - 8 months ago

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I am not asking you ? Idiot

SRIJAN Singh - 8 months ago

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@Srijan Singh

  1. He never replied to your comment as a an answer to a question, so he can comment that, and there is nothing wrong with it.

  2. If anyone's an idiot here, its you

  3. What he has said, is also true. At least, I am not your best friend, I don't know about the others, but best friend is kinda too far, because we hardly know each other. You might be a friend to the others, to me you're just an annoying brat.

  4. Don't reply to this. Get this in your head that unless you post one useful comment, you are doing the same thing Lam did in Nathan's Latex note. Your reply's are irritating enough already, Kat was right to call you a prick.

@SRIJAN Singh

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@A Former Brilliant Member i regret telling kat off for calling him that

NSCS 747 - 8 months ago

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@Nscs 747 lol yeah

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@A Former Brilliant Member should i drop a nuke on him?

NSCS 747 - 8 months ago

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@Nscs 747 Sure, I wouldn't mind :)

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@A Former Brilliant Member well its not your average nuke but it is just as deadly and annoying can i test it on you to see if it works? it is still a prototype i will send u a small one

NSCS 747 - 8 months ago

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@Vinayak Srivastava if you are online see this

SRIJAN Singh - 10 months, 1 week ago

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New problem @Vinayak Srivastava,@Percy Jackson.

A Former Brilliant Member - 10 months, 1 week ago

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Try this problem by me A Unique function

Aryan Sanghi - 10 months, 1 week ago

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Try out my new problem: Are all numbers good?

Vin_Math 91 - 10 months ago

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@Vinayak Srivastava.do my new problem

SRIJAN Singh - 10 months ago

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Try this problem Co-Normal Parabolic Centroid

Aryan Sanghi - 9 months, 4 weeks ago

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Try this problem Triangle of Reflection

Aryan Sanghi - 9 months, 2 weeks ago

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done

SRIJAN Singh - 9 months, 2 weeks ago

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I am shown no solvers?

Aryan Sanghi - 9 months, 2 weeks ago

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@Aryan Sanghi but got wrong

SRIJAN Singh - 9 months, 2 weeks ago

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Try this problem Areal Parabolic Centroid

Aryan Sanghi - 9 months, 1 week ago

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I found this easy logic problem.However,you need to know the rules of cricket.

A Former Brilliant Member - 9 months, 1 week ago

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Wow! I calculated wrong! I knew the answer though.

Vin_Math 91 - 9 months, 1 week ago

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@Vinayak Srivastava,I have seen in your profile that cricket is one of your interests.

A Former Brilliant Member - 9 months, 1 week ago

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Yes, but I added wrong, I knew that rule.

Vin_Math 91 - 9 months, 1 week ago

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Extension: Answer should be 33n+333n + 3 runs for nn overs

Mahdi Raza - 9 months, 1 week ago

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Oh yes, I forgot, but I once saw a debate, where it was asking if 5 runs is possible or not.

Vin_Math 91 - 9 months, 1 week ago

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@Vin_Math 91 I don't think so. It shouldn't be allowed. "All exceptions to be avoided" should be written in the question, but I guess it is assumed in the rules of cricket


If that is allowed through (shouldn't be, but anyway), then the total would be

35(n1)+36=35n+135(n-1) + 36 = 35n + 1

Mahdi Raza - 9 months, 1 week ago

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@Mahdi Raza And if 5 is allowed, then even 7 should be. That is possibly why 5 is not counted as well

Mahdi Raza - 9 months, 1 week ago

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@Vin_Math 91 I do think it is allowed in cricket.However,it is only possible when fielders are like me or ball is lost .:-P

A Former Brilliant Member - 9 months, 1 week ago

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Do you mean 33(n-1)+36 :-)

A Former Brilliant Member - 9 months, 1 week ago

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@A Former Brilliant Member Yes, exactly. for each of the first (n1)(n-1) overs, the batsman will take 33 runs. But in the last over he need not change the strike so he can hit all sixes which is 36 runs

Total =33(n1)+36=33n33+36=33n+3\begin{aligned} \text{Total } &= 33(n-1) + 36 \\ &= 33n - 33 + 36 \\ &= \boxed{33n + 3} \end{aligned}

Which is what I wrote above

Mahdi Raza - 9 months, 1 week ago

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@Mahdi Raza Ok

A Former Brilliant Member - 9 months, 1 week ago

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The problem becomes easy once you know the rules of Cricket, I had to google the rules of cricket for this.

Siddharth Chakravarty - 9 months, 1 week ago

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so you cheated, or referred after getting it wrong? @Siddharth Chakravarty

A Former Brilliant Member - 9 months, 1 week ago

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@A Former Brilliant Member Well I referred it before attempting, and then I read a whole wiki on a sport that doesn't interest me, and then got the question correct. I guess it is not cheating, as it is like knowing about a theorem to solve a problem :)

Siddharth Chakravarty - 9 months, 1 week ago

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@Siddharth Chakravarty I was only interested in the 'sport that doesn't interest me' part. LOL Finally someone who doesn't think cricket is a big deal. The way Mahdi and Kriti talk about cricket makes me think that you need a degree in cricket to get into MIT and both of them passed the cricket exam with full marks lol XD

A Former Brilliant Member - 9 months, 1 week ago

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@A Former Brilliant Member In India, Cricket has a huge fanbase, I mean really huge, so you could expect majority of people to love it :) I'm more into racket games like badminton and swimming.

Siddharth Chakravarty - 9 months, 1 week ago

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@Siddharth Chakravarty Swimming, I'ma son of Poseidon. More into that :)

A Former Brilliant Member - 9 months, 1 week ago

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@A Former Brilliant Member Actually,I am not interested in any sports.But,if you are Indian,then it is like common knowledge.You may not interested in cricket but,when your all friends are talking about cricket whole the day.Then, it's quite reasonable that you will know all about it without even playing it :)

A Former Brilliant Member - 9 months, 1 week ago

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@A Former Brilliant Member lol XD, if you see my bio it is written get into MIT that means I need a degree in cricket.

SRIJAN Singh - 9 months, 1 week ago

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Try this problem Highly Elliptical Area!!

Aryan Sanghi - 9 months, 1 week ago

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Hi, I think I am new to the group, I found this geometry Problem which uses the properties of circles, rectangles and even triangles(based on your method)

Pankaj Kumar - 9 months, 1 week ago

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Thanks! Beautiful geometry problems or even problems that have an elegant solution are always a pleasure to solve. Very few problems are being shared in this discussion/page. I expected a lot, but nevermind :(

Mahdi Raza - 9 months, 1 week ago

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@Mahdi Raza It was the least I could do! I hope that more people find and join this discussion and share some incredible problems.

Pankaj Kumar - 9 months, 1 week ago

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Try this problem Ellipse's Circumscribed perimeter!

Aryan Sanghi - 9 months ago

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Check out this easy limit problem: Limiting till the degree 5, @Aryan Sanghi I was talking about this.

Siddharth Chakravarty - 9 months ago

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It's easy I solved first! Check this! out

SRIJAN Singh - 9 months ago

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Please post a solution if you want, and I am still learning coding so I cannot help much maybe :)

Siddharth Chakravarty - 9 months ago

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@Siddharth Chakravarty Which type of language are you learning? ,I'll post the solution whenever I'll get time

SRIJAN Singh - 9 months ago

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@Srijan Singh Python

Siddharth Chakravarty - 9 months ago

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@Siddharth Chakravarty Nice,Me also Python btw what are you learning in that

SRIJAN Singh - 9 months ago

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Solved it. :) @Siddharth Chakravarty

Aryan Sanghi - 9 months ago

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simplest problem

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Done!

SRIJAN Singh - 9 months ago

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Seriously serrated series

Vin_Math 91 - 8 months, 4 weeks ago

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@Vinayak Srivastava,@Percy Jackson,@Mahdi Raza,@Kriti Kamal,@Siddharth Chakravarty,@Aryan Sanghi,I wish you will like this problem

SRIJAN Singh - 8 months, 4 weeks ago

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Solved it, thanks for sharing @SRIJAN Singh

A Former Brilliant Member - 8 months, 4 weeks ago

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Nice,Your welcome

SRIJAN Singh - 8 months, 4 weeks ago

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Its not my problem, but its pretty good

A Former Brilliant Member - 8 months, 4 weeks ago

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Nice one But I have not studied calculus yet

SRIJAN Singh - 8 months, 4 weeks ago

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@Percy Jackson .I am first to solve your problem...wait I'm posting the solution

SRIJAN Singh - 8 months, 4 weeks ago

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ok, I am also posting solution

A Former Brilliant Member - 8 months, 4 weeks ago

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Yes post it Btw how did you use limit function,I don't know how to use latex.Is there any wiki that can teach me how to use latex

SRIJAN Singh - 8 months, 4 weeks ago

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@Srijan Singh Pall Marton's Latex Guide

A Former Brilliant Member - 8 months, 4 weeks ago

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@A Former Brilliant Member Okay

SRIJAN Singh - 8 months, 4 weeks ago

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@Srijan Singh PLS comment on my chatbot one

SRIJAN Singh - 8 months, 4 weeks ago

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N's the Limit

A Former Brilliant Member - 8 months, 4 weeks ago

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Try this problem Ellipse's circular tangents!!

Aryan Sanghi - 8 months, 3 weeks ago

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Try this problem A Real Equation!!

Aryan Sanghi - 8 months, 2 weeks ago

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Try this problem Functional Complex Trignometry!!

Aryan Sanghi - 8 months ago

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Try this problem Cardinality of Inequations!!

Aryan Sanghi - 8 months ago

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Try this problem Highly Upvoted!!

Aryan Sanghi - 6 months ago

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It is deleted (-_-)

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Yes, that's why in next comment I said-try this one instead. :)

Aryan Sanghi - 6 months ago

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Try this problem by me instead High Summation!!

Aryan Sanghi - 6 months ago

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All the best to everyone giving IOQM and/or IOQJS tomorrow!

Vin_Math 91 - 5 months ago

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Thanks

SRIJAN Singh - 5 months ago

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Can someone please tell me the working in this problem:

If a+b+2c=4,a>0,b>0,c>0a+b+2c=4, a>0,b>0,c>0, then find minimum value of 1a+1b+2c\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{2}{c}

Vin_Math 91 - 5 months ago

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Jason Gomez - 4 months, 2 weeks ago

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Nice! Thanks! What was the motivation to write it as a+b+c+ca+b+c+c?

Vin_Math 91 - 4 months, 2 weeks ago

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@Vin_Math 91 If u see the harmonic seq u see a 2c\frac{2}{c} so the only ways to make it in the AM was to either use c2\frac{c}{2} or use cc twice but since we don’t know what a+b+c2a+b+\frac{c}{2} I had to use the other one

Jason Gomez - 4 months, 2 weeks ago

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@Vin_Math 91 There are some questions you can see and find that you have to use ( if u want to do the question easily ) the QM-AM-GM-HM inequality. Once this set in your head that you have to use it, you will see how to split the variables to get the best results

Jason Gomez - 4 months, 2 weeks ago

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@Jason Gomez But yeah this comes with some practice

Jason Gomez - 4 months, 2 weeks ago

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@Jason Gomez Yeah, I just recalled that I have used this myself once here. I forget things quite fast! Anyway, thanks for your insight! But I don't think I have practised more than 1 or 2 this kind of problem.

Vin_Math 91 - 4 months, 2 weeks ago

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@Vin_Math 91 There is one last way to find out which I don’t use at all, when minimised all the terms in the expression separately will be equal ( here 1a,1b,1c,1c\frac{1}{a} , \frac{1}{b},\frac{1}{c},\frac{1}{c}), this can be useful for easier direct questions ( like this one ) but not for the ones which involve sums or products of inequalities

Jason Gomez - 4 months, 2 weeks ago

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@Jason Gomez LOL this is THE method I use most. Maybe I never encountered any hard problems which can't be solved by making all terms equal. :)

Vin_Math 91 - 4 months, 2 weeks ago

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@Vin_Math 91 U could try proving the nesbitt inequality ab+c+bc+a+ca+b\frac{a}{b+c}+ \frac{b}{c+a}+ \frac{c}{a+b} is greater than 32\frac{3}{2} using AM-HM ( there are other ways too, I never found it when I had first tried using AM-HM, I had to resort to rearrangement :) )

Jason Gomez - 4 months, 2 weeks ago

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Very silly of me, but I have missed a four in the first step so the answer is actually 14\frac{1}{4}

Jason Gomez - 4 months, 2 weeks ago

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It should be 4 not 1/4. Also in your solution you wrote it as 1/2c rather 2/c.

Siddharth Chakravarty - 4 months, 2 weeks ago

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@Siddharth Chakravarty Nice a mistake while correcting a mistake , I have edited the solution

Jason Gomez - 4 months, 2 weeks ago

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@Jason Gomez Do u mean u made a mistake while correcting ur mistake or did I say something wrong? 🤔

Siddharth Chakravarty - 4 months, 2 weeks ago

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@Siddharth Chakravarty No no I mean the mistake is on me, twice

Jason Gomez - 4 months, 2 weeks ago

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@Jason Gomez No problem with it, I got the trick, that is all the help which was required. Thanks.

Vin_Math 91 - 4 months, 2 weeks ago

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I think this is a nice problem in community: Generate this!

Vin_Math 91 - 4 months, 3 weeks ago

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Can someone please explain this?

Vin_Math 91 - 4 months, 3 weeks ago

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The answer is wrong because if all the coefficients leaving the first one are 0, and the first coefficient is any 3 digit perfect square then the answer is yes. First coefficient is the one with x0{x}^{0}.

Siddharth Chakravarty - 4 months, 3 weeks ago

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Yes, I also thought the same. Maybe we should report it.

Vin_Math 91 - 4 months, 3 weeks ago

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can u provide a proof that polynomial will have to be constant polynomial? I mean if yes,then we are done here. P(x)= a three digit number

And for any value of x,p(x) won't be zero.

Krity Kamal - 4 months, 3 weeks ago

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@Krity Kamal I didn't understand what you meant.

Siddharth Chakravarty - 4 months, 3 weeks ago

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@Siddharth Chakravarty Chat on telegram

Krity Kamal - 4 months, 3 weeks ago

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I'm not sure about this problem.If you find any ambiguity,then please report it or can comment here.

Krity Kamal - 4 months, 1 week ago

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Could u send a screenshot of the problem here,the link you have sent just won’t load

Jason Gomez - 4 months, 1 week ago

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Thank you! but I got it. The problem got deleted

Krity Kamal - 4 months, 1 week ago

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Do you think score of 30 qualify for INMO this year?

Ambica Jain - 4 months, 1 week ago

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Try this problem by me Two Points And A Circle Of Life

Aryan Sanghi - 3 months, 3 weeks ago

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Anyone calculated their marks? I am getting 23, did a lot of silly mistakes :(