I've just realised I completely misunderstood the meaning of this week's "Touch me not" problem (Geometry and Combinatorics). Instead of finding the probability that the three sectors have a point in common (other than the centre), I tried to find the probability that at least two sectors have a point in common. I'd like to propose this modified version of the problem for discussion to see how other people would approach it. (I couldn't find a nice elementary solution: I had to compute some definite integrals)

I'll report the modified text here: "Three sectors are chosen at random from circle \(C\), having angles \(\frac{\pi}{10},\frac{2 \pi}{10}, \frac{3\pi}{10}\) respectively. What is the probability that at least two of these three sectors have a point in common other than the center of the circle.

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TopNewestIn either version of the problem, using indefinite integral makes the calculation pretty nasty.

Check out Geometric Probability to transform the question into one about volume (of if you're good, area).

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