Waste less time on Facebook — follow Brilliant.
×

Problem from IMO

ABCD is a rhombus in which the altitude from d bisects AB. AE=EB. Therefore, angle A and angle B respectively are (of how many degrees).

Note by Neha Adepu
4 years, 1 month ago

No vote yet
3 votes

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

I don't think this is from IMO (International Mathematical Olympiad).

Zi Song Yeoh - 4 years, 1 month ago

Log in to reply

This is from an exam conducted here in India by a private company.

Vikram Waradpande - 4 years, 1 month ago

Log in to reply

Oh, I see. Indian Mathematical Olympiad?

Zi Song Yeoh - 4 years, 1 month ago

Log in to reply

@Zi Song Yeoh No way, I doubt they ask such easy questions. As Vikram said, it must be a contest by some private organisation.

If the private organisations use names such as "IMO" and mislead the students, then its a very bad tactic to promote themselves.

Pranav Arora - 4 years, 1 month ago

Log in to reply

@Pranav Arora its called international mathematics olympiad conducted by SOF

Jun Das - 4 years ago

Log in to reply

@Zi Song Yeoh Nope. Its a basic level contest conducted by a company.

Vikram Waradpande - 4 years, 1 month ago

Log in to reply

Hey guys,I think she is talking of SOF IMO and not the Great and the one you all are thinking IMO!!!!

Kishan K - 4 years, 1 month ago

Log in to reply

YOU,RE RIGHT!. It is a problem from the work book.

Neha Adepu - 4 years, 1 month ago

Log in to reply

Consider the sides of the rhombus to be of length \(x\), i.e., \(AD=x\). So, \(AE= \frac{x}{2}\).

Let \(\angle A= \theta\). So, \(cos \theta = \frac{AE}{AD} =\frac{1}{2}\)

\(\implies \theta =60^o\) \(\implies \angle A=60^o\) and \(\angle B=180^o-60^o=120^o\)(As they are interior opposite angles)

Maharnab Mitra - 4 years, 1 month ago

Log in to reply

ANGLE A=60 ANGLE B=120

Avishkar Rajeshirke - 4 years, 1 month ago

Log in to reply

Consider- \(DA = x\)

\(AE = x/2\)

\(EB = x/2\)

\(DE = x^{2} - (x/2)^{2}\) \(= \sqrt{3}x/2\)

\(DB = x\) (Pythagoras Theorem)

\(DA = x , DB = x , AB = x\)

\(ADB\) is an Equilateral triangle

Thus, \(A = 60°\) \(B = 120°\)

Rashmi B K - 4 years, 1 month ago

Log in to reply

THANK YOU!!!

Neha Adepu - 4 years, 1 month ago

Log in to reply

I think is 180 degrees

Yen Loong - 4 years, 1 month ago

Log in to reply

This que is not from IMO !

Rashmi B K - 4 years, 1 month ago

Log in to reply

If this problem is from IMO, please tell me what year and what question.

Anton Than Trong - 4 years, 1 month ago

Log in to reply

Thats Indian Maths Olympiad

Avishkar Rajeshirke - 4 years, 1 month ago

Log in to reply

this problem is not from the main exam, it is from the workbook

Neha Adepu - 4 years, 1 month ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...