This value is different for different values of \(n\). I'm not sure if this is what you want, although \((n-3)(n-4)\) is clearly a positive integer for positive integer values of \(n\). Please clarify further. Thanks!
–
Victor Loh
·
1 year, 3 months ago

Log in to reply

@Victor Loh
–
Yes n value is positive integer.Really thanks @Victor Loh I got it completely Now :) Thumps up for u Cheers :)
–
Mehdi Balti
·
1 year, 3 months ago

Log in to reply

@Victor Loh
–
If I would not given the value but say that it's positive integer then how would you solve this ?Answer should be in positive integer.
–
Mehdi Balti
·
1 year, 3 months ago

## Comments

Sort by:

TopNewestLog in to reply

– Mehdi Balti · 1 year, 3 months ago

Can you explain it :)Log in to reply

@Mehdi Balti, could you please clarify what the problem is? Thanks. – Victor Loh · 1 year, 3 months ago

Log in to reply

It's factorial and the answer will be in positive integer.Not in decimal (n-3)(n-4)!/(n-5)(n-6)!=? – Mehdi Balti · 1 year, 3 months ago

Log in to reply

\[x = \frac{(n-4)!(n-3)}{(n-6)!(n-5)},\]

where \(x\) is a positive integer.

Note that

\[\begin{align} x &= \frac{(n-4)!(n-3)}{(n-6)!(n-5)} \nonumber \\ &= \frac{(n-3)[(n-4)(n-5)(n-6)\cdots(3)(2)(1)]}{(n-5)[(n-6)(n-7)(n-8)\cdots(3)(2)(1)]} \nonumber \\ &= \frac{(n-3)(n-4)(n-5)!}{(n-5)!} \nonumber \\ &= (n-3)(n-4) \nonumber \end{align}\]

This value is different for different values of \(n\). I'm not sure if this is what you want, although \((n-3)(n-4)\) is clearly a positive integer for positive integer values of \(n\). Please clarify further. Thanks! – Victor Loh · 1 year, 3 months ago

Log in to reply

@Victor Loh I got it completely Now :) Thumps up for u Cheers :) – Mehdi Balti · 1 year, 3 months ago

Yes n value is positive integer.Really thanksLog in to reply

– Mehdi Balti · 1 year, 3 months ago

If I would not given the value but say that it's positive integer then how would you solve this ?Answer should be in positive integer.Log in to reply