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Proof Contest Day 5

Let ABCDE be a regular pentagon, and let F be a point on AB with \(\angle CDF = 55^o\). Suppose FC and BE meet at G, and select H on the extension of CE past E such that \( \angle DHE = \angle FDG\). Find the measure of \(\angle GHD\), in degrees with proof.


Edit: No one else solved this problem here is the solution.

Note by Lakshya Sinha
8 months, 3 weeks ago

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