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# Proof Contest Day 5

Let ABCDE be a regular pentagon, and let F be a point on AB with $$\angle CDF = 55^o$$. Suppose FC and BE meet at G, and select H on the extension of CE past E such that $$\angle DHE = \angle FDG$$. Find the measure of $$\angle GHD$$, in degrees with proof.

Edit: No one else solved this problem here is the solution.

Note by Lakshya Sinha
1 year, 10 months ago

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