Proof for the focus of a parabola/parebola :3

In this note I'll prove that the distance of the focus from the vertex \((p)\) of a parabola has the equation \(4p(y-k)=(x-h)^2\) where the parabola has the vertex (h,k).

I would also love feed back on this note. If you look at most of my other notes, I go very far into detail about each step I do to avoid any confusion and to make the note understandable to as many people as possible. However, for the more skilled reader, it may seem a bit long, so this note I'll skip a few simple explanations (no details will be skipped). Tell me what you think in the comments below :) thanks!

Begin with the standard equation of a parabola \(y=ax^2+bx+c\).

Finding the vertex coordinates using \(x=\frac{-b}{2a}\)



Our vertex has coordinates


Thus \(h=\dfrac{-b}{2a}\) and \(k=\dfrac{-b^2}{4a}+c\)

A parabola is the set of points equidistant from the focus and directrix. Thus there is a point (call it m) distance 2p from the focus and distance 2p from the directrix. Therefore, if we draw a line parallel to the directrix from the focus, it will perpendicularly bisect the line from the directrix to m. (Can someone explain why, I can't explain this for some reason, I know why, but I can't put it into words). This is what is depicted in the picture above.

Now, this means there exists a point on our graph distance 2p to the right of our vertex and distance p above. Thus the point has the coordinates \(\left(\dfrac{-b}{2a}+2p,\dfrac{-b^2}{4a}+c+p\right)\). Plugging in for x and y


Bash bash bash


Going back to our first equation \(\left(\frac{1}{a}\right)y=x^2+\left(\frac{1}{a}\right)bx+\left(\frac{1}{a}\right)c\)


This part is a little tricky so I'll show all the steps. Add \(4p^2b^2\) to both sides.


Resubstituting \(p=\dfrac{1}{4a}\) EVERYWHERE BUT THE FIRST P.



Remember, \(h=\dfrac{-b}{2a}\) and \(k=\dfrac{-b^2}{4a}+c\)


And we are done.

Remember, please leave feed back on how you liked/disliked the writing style/comprehensiveness of this note.

Note by Trevor Arashiro
3 years, 10 months ago

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