Find all the integral solutions of \({ x }^{ 4 }+{ y }^{ 4 }+{ z }^{ 4 }-{ w }^{ 4 }=1995\).

Please help me with the problem, Thanks!

Find all the integral solutions of \({ x }^{ 4 }+{ y }^{ 4 }+{ z }^{ 4 }-{ w }^{ 4 }=1995\).

Please help me with the problem, Thanks!

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

## Comments

Sort by:

TopNewestWe know that \(a^4 \equiv 0,1 \pmod {16} \quad \forall \ a \in \mathbb Z \).

We can have:

\[x^4 + y^4 + z^4 - w^4 \equiv -1,0,1,2,3 \pmod {16}\]

or

\[x^4 + y^4 + z^4 - w^4 \equiv 0,1,2,3,15 \pmod {16}\]

But \(1995 \equiv 11 \pmod {16} \). So no integral solutions exist!

@Swapnil Das - I'd say it's a Number Theory Problem! – Satyajit Mohanty · 1 year, 7 months ago

Log in to reply

@Satyajit Mohanty – Mehul Arora · 1 year, 7 months ago

Solution master:Log in to reply

@Satyajit Mohanty :) – Mehul Arora · 1 year, 7 months ago

Yeah! It is! Great solutionLog in to reply

– Dev Sharma · 1 year, 7 months ago

why did you work with mod16? why not other numbers? is there any rule?Log in to reply

– Satyajit Mohanty · 1 year, 7 months ago

I worked with mod 16 because fourth powers have an interesting property as they are equivalent to only 0 or 1 modulo 16. I don't have any idea about other modulos for 16th powers. Well, one can try further.Log in to reply