\( CP \parallel AB, BC = CQ \Rightarrow AP = PQ \) (midpoint theorem).
Considering congruences, we get \(CP = PD \).
Then \( [ADP] = [BPC] = [CPQ] = [DPQ] \) by properties of the median, considering parallel lines and common bases.
–
Ameya Daigavane
·
8 months ago

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TopNewest\( CP \parallel AB, BC = CQ \Rightarrow AP = PQ \) (midpoint theorem).

Considering congruences, we get \(CP = PD \).

Then \( [ADP] = [BPC] = [CPQ] = [DPQ] \) by properties of the median, considering parallel lines and common bases. – Ameya Daigavane · 8 months ago

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– Vishwathiga Jayasankar · 8 months ago

ThankyouLog in to reply