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Proof proof

In the given figure ABCD is a parllelogram.

Prove that ar(BCP)= ar(DPQ) if BC=CQ.

Note by Vishwathiga Jayasankar
11 months, 3 weeks ago

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\( CP \parallel AB, BC = CQ \Rightarrow AP = PQ \) (midpoint theorem).
Considering congruences, we get \(CP = PD \).
Then \( [ADP] = [BPC] = [CPQ] = [DPQ] \) by properties of the median, considering parallel lines and common bases. Ameya Daigavane · 11 months, 3 weeks ago

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@Ameya Daigavane Thankyou Vishwathiga Jayasankar · 11 months, 2 weeks ago

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