\( CP \parallel AB, BC = CQ \Rightarrow AP = PQ \) (midpoint theorem).
Considering congruences, we get \(CP = PD \).
Then \( [ADP] = [BPC] = [CPQ] = [DPQ] \) by properties of the median, considering parallel lines and common bases.
–
Ameya Daigavane
·
5 months, 3 weeks ago

## Comments

Sort by:

TopNewest\( CP \parallel AB, BC = CQ \Rightarrow AP = PQ \) (midpoint theorem).

Considering congruences, we get \(CP = PD \).

Then \( [ADP] = [BPC] = [CPQ] = [DPQ] \) by properties of the median, considering parallel lines and common bases. – Ameya Daigavane · 5 months, 3 weeks ago

Log in to reply

– Vishwathiga Jayasankar · 5 months, 2 weeks ago

ThankyouLog in to reply