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# Prove the following inequality

$\dfrac{a}{b+2c+3d} + \dfrac{b}{c+2d+3a} + \dfrac{c}{d+2a+3b} + \dfrac{d}{a+2b+3c} > \dfrac{2}{3}$

If a,b,c,d are distinct positive reals, prove the above inequality.

Note by Raushan Sharma
1 year ago

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Have u given the inmo mock test of fiitjee yesterday · 1 year ago

No, one of my friends gave that, and yeah, it's a question I gave from there only... Did you give that test?? How was it? · 1 year ago

Yes I gave the test and it was really difficult....this was the only question I could completely solve....I would post the complete paper soon. · 1 year ago

Ya, I have the complete paper, but can you give the solution to this inequality, I mean how you solved, I was trying it with Tittu's Lemma, but couldn't complete · 1 year ago

Use titu lemma and then cauchy schwarz on $$sqrt (a), sqrt (b), sqrt (c), sqrt (d) and 1,1,1,1$$ it would give the direct result · 1 year ago

Oh, yeah, I did it today, after I commented that. It was quite easy. Actually first I was not expanding $$(a+b+c+d)^2$$. I first applied Tittu's lemma and then AM-GM · 1 year ago

Can you please post the complete solution including explanation for this question?? · 10 months, 3 weeks ago

Yes, I can, but for that can you please tell me, how can we add an image in the comment?? · 10 months, 3 weeks ago