Hi, I need help solving this problem - any help would be appreciated :)

\(P\) and \(Q\) are points on the bisector of the exterior angle \(A\) of triangle \(ABC\) with A between \(P\) and \(Q\), and \(PB\) is parallel to \(QC\). Point \(D\) is on BC such that \(DP=DQ\). Prove that \(AB\) is parallel to \(DQ\).

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TopNewestI have drawn a sketch for the problem , but according to your statements DQ is part of PQ,which passes through point A. so far, as DQ & AB , both of them passes through point A , that means , they intersect at point A . therefore they can not be parllel. because they intersect. – Aziz Alasha · 2 months, 2 weeks ago

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