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# Psyched up!

In the theory of learning in psychology, probabilities t and p and a constant b are related by: t = (1-b)p

Show that this equation may be written as: 1-t = (1-b)(1-p) + b

How?

Note by Xavier Fernandez
1 year, 11 months ago

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$$1 -t = 1-(1-b)p$$

$$=1-(1-b)\left(1-(1-p)\right)$$

$$=1-(1-b)+(1-b)(1-p)=b+(1-b)(1-p)$$

Hence, proved. · 1 year, 11 months ago