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# Figuring out the remainder

The remainder of the division of a polynomial $$P(x)$$ by $$x-1$$ is 6, and the remainder of the division of $$P (x)$$ by $$x + 2$$ is 4.Then the remainder of the division of $$P (x)$$ by $$(x-1 ) (x + 2)$$ is:

(a): $$R (x) = 2x / 3 + 16/3$$.

(b): $$R (x) = 2x / 3 - 16/3$$.

(c): $$R (x) = 2x / 3 + 8/3$$.

Note by Lucas Nascimento
1 year, 7 months ago

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Consder P(x)=(x-1)(x+2)Q(x)+ax+b;P(1)=6=>a+b=6;P(-2)=4=>-2a+b=4.solve for a,b giving option (a) as remainder.

- 1 year, 7 months ago