# Figuring out the remainder

The remainder of the division of a polynomial $$P(x)$$ by $$x-1$$ is 6, and the remainder of the division of $$P (x)$$ by $$x + 2$$ is 4.Then the remainder of the division of $$P (x)$$ by $$(x-1 ) (x + 2)$$ is:

(a): $$R (x) = 2x / 3 + 16/3$$.

(b): $$R (x) = 2x / 3 - 16/3$$.

(c): $$R (x) = 2x / 3 + 8/3$$.

Note by Lucas Nascimento
1 year, 11 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

Consder P(x)=(x-1)(x+2)Q(x)+ax+b;P(1)=6=>a+b=6;P(-2)=4=>-2a+b=4.solve for a,b giving option (a) as remainder.

- 1 year, 11 months ago