×

# Figuring out the remainder

The remainder of the division of a polynomial $$P(x)$$ by $$x-1$$ is 6, and the remainder of the division of $$P (x)$$ by $$x + 2$$ is 4.Then the remainder of the division of $$P (x)$$ by $$(x-1 ) (x + 2)$$ is:

(a): $$R (x) = 2x / 3 + 16/3$$.

(b): $$R (x) = 2x / 3 - 16/3$$.

(c): $$R (x) = 2x / 3 + 8/3$$.

Note by Lucas Nascimento
3 months, 2 weeks ago

## Comments

Sort by:

Top Newest

Consder P(x)=(x-1)(x+2)Q(x)+ax+b;P(1)=6=>a+b=6;P(-2)=4=>-2a+b=4.solve for a,b giving option (a) as remainder. · 3 months, 2 weeks ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...