Waste less time on Facebook — follow Brilliant.
×

Figuring out the remainder

The remainder of the division of a polynomial \(P(x)\) by \(x-1\) is 6, and the remainder of the division of \( P (x)\) by \(x + 2\) is 4.Then the remainder of the division of \( P (x)\) by \((x-1 ) (x + 2)\) is:

(a): \(R (x) = 2x / 3 + 16/3\).

(b): \(R (x) = 2x / 3 - 16/3\).

(c): \(R (x) = 2x / 3 + 8/3\).

Note by Lucas Nascimento
1 month, 1 week ago

No vote yet
1 vote

Comments

Sort by:

Top Newest

Consder P(x)=(x-1)(x+2)Q(x)+ax+b;P(1)=6=>a+b=6;P(-2)=4=>-2a+b=4.solve for a,b giving option (a) as remainder. Deepak Kumar · 1 month, 1 week ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...