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Pythagorean Theorem Formula?

Okay, I had this in my head for a while, and I just now decided to post it.

Let's say you have a side, \[a\].

If it's odd, the second side is \(\frac{a^{ 2 } - 1}{2} = b\)

else the second side is \(\frac{a^{ 2 } - 4}{4} = b\)

The third side is \[\sqrt{(a^{2} + b^{2})}\]

I've personally found nothing to disprove this, please post anything if you have disproved it. ((No negative numbers or zero guys, even though the formulas won't break if you do it.))

Note by Zaid Baig
3 years, 5 months ago

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