I thought up a new approach to the problem about \(\large \sqrt[3]{\sqrt[3]{2} - 1} \) and its simplifications. I know Calvin posted this a while back and I was wondering if any of you had a link so I can answer it.

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

## Comments

Sort by:

TopNewestThanks. Sorry for inconvenience. – Sal Gard · 10 months, 3 weeks ago

Log in to reply

– Pi Han Goh · 10 months, 3 weeks ago

Why apologize? You did nothing wrong? We're here to learn....Log in to reply

Thanks for the solution. I already had this but I was looking for the problem, not the answer. Thanks anyway. – Sal Gard · 10 months, 3 weeks ago

Log in to reply

– Pi Han Goh · 10 months, 3 weeks ago

ARML 1997Log in to reply

Rationalize numerator by multiplying the expression by \( \dfrac{\sqrt[3]{\sqrt[3]{4} + \sqrt[3]{2} + 1}}{\sqrt[3]{\sqrt[3]{4} + \sqrt[3]{2} + 1}} \) then simplify the expression, then multiply it by \( \dfrac{\sqrt[3]{3}}{\sqrt[3]{3}} \), you get \( \dfrac{ \sqrt[3]{3}}{1 + \sqrt[3]{3}} \). Finally, rationalize the denominator to obtain \( \sqrt[3]{\dfrac49} + \sqrt[3]{-\dfrac29} + \sqrt[3]{\dfrac19} \). – Pi Han Goh · 10 months, 3 weeks ago

Log in to reply