# Rational by rational always rational?

Here's a statement that I've come across in the app. It reads: "Dividing a rational number by a rational number will always produce a rational number." I immediately chose True, but apparently this was not the correct answer.

I thought that you cannot get an irrational number by dividing two rational numbers. I'm obviously missing something. Can you give me a couple of concrete examples when this is not the case?

Note by Hold the door Hodor
1 year, 11 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

Divide $$7$$ by $$0$$, both are separately rational but the result which comes on division is not even a real number( and hence not rational). Indeed you could choose both zero and we very well know $$\frac{0}0$$ is an undetermined form.

- 1 year, 11 months ago