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In rational exponents, i don't understand what is \right\left] etc. means. Can any1 help ?

Note by শামিন আশফাক
3 years, 6 months ago

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If you want to type brackets (and other stuff) which are large enough to enclose a display formula, you can do a variety of things.

You can specify how big the brackets are by typing things like

 \big(  ,  \Big[   ,  \Huge|   ,  \small \lfloor  , \tiny\}


These commands look like this (though there is not much call for the last one!): $\big( \qquad \Big[ \qquad \Huge| \qquad \small \lfloor \qquad \tiny\}$

You can let LaTeX choose the right (most of the time) size by using "\left" and "\right" in pairs. The size of the bracket will depend on what you put inside it. So

\left(\frac{13}{8}\right)     \left\lfloor \int_0^\infty \frac{x}{(x^2+1)^2}\,dx\right\rfloor


come out like: $\left(\frac{13}{8}\right) \qquad \left\lfloor \int_0^\infty \frac{x}{(x^2+1)^2}\,dx\right\rfloor$

You need to be careful to make sure that each time you start a bracket pair with a "\left" command, you finish it with a "\right" command. Otherwise LaTeX will not be able to display your formula.

There is one special case, if you want to typeset a multioption formula. The code

|x| \;=\;   \left\{ \begin{array}{lcl} x & x \ge 0 \\ -x & x < 0 \end{array} \right.


uses the special case "\right." to end the opening "\left$$\backslash$${" bracket, giving

$|x| \;=\; \left\{ \begin{array}{lcl} x & x \ge 0 \\ -x & x < 0 \end{array} \right.$ · 3 years, 6 months ago