the same paper came for south bihar as well. ( i am in 10th)
i solved q.1,2,3 and 6 correctly. in 3 i took all the cases but just missed to mention 2 of the 8 solutions. and for the combi question(q.5) i wrote 32c3 - 16*30 - (something i don't remember) + 64 = some big number as result of a calculation mistake. what can be my marks.
–
Akash Deep
·
1 year ago

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@Akash Deep
–
Aakash did you gave the tallentex exam 2015 from B D public school ? I think we both were sitting together .
–
Wasif Jawad Hussain
·
12 months ago

@Akash Deep
–
In the combi question I too missed the answer by 32. I subtracted 16x28 instead of 16x26....
–
Ankit Kumar Jain
·
12 months ago

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How many of your answers were correct
–
Prakher Gaushal
·
1 year ago

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@Prakher Gaushal
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I attempted 5 and in which 2 are perfectly correct and 2 with little mistakes and the other one I am expecting it to be correct.
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Easha Manideep D
·
1 year ago

Hi,I am also from U.P(Varanasi). I did 2 questions correct but missed one case in ques.3 ,got only 1 answer in ques.6(there are 5) and doubtful about ques.4 How much did you solve:)
–
Siddharth Singh
·
1 year ago

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Even Rajasthan RMO had same paper.
–
Akshat Sharda
·
1 year ago

Answer to question 6.
Let \[a=m+\frac{b}{c}\] where \(m\) is any integer and \[0<b<c\] .
Then \[a(a-3{a})=( m+\frac{b}{c})( m-2\frac{b}{c}) \]
\[m^{2}-\frac{bm}{c}+\frac{2b^{2}}{c^{2}}\].
\[m^{2}-\frac{2b^{2}-bcm}{c^{2}}\]
Now, \(m\) is an integer . Let's consider \[ \frac{2b^{2}-bcm}{c^{2}}=k\] where \(k\) is an integer .
After solving we get \[\frac{b}{c}=\frac{m+_{-}\sqrt{m^{2}+8k}}{4}\].....(I)
But \[\frac{b}{c}<1\]....(II)
Now putting value of \(\frac{b}{c}\) from (I) to (II).
We get \[m+k<2\]
Therefore there are infinitely many integers \(m,k\) such that \[m+k<2\].
Hence proved.
–
Shivam Jadhav
·
1 year ago

## Comments

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TopNewestthe same paper came for south bihar as well. ( i am in 10th) i solved q.1,2,3 and 6 correctly. in 3 i took all the cases but just missed to mention 2 of the 8 solutions. and for the combi question(q.5) i wrote 32c3 - 16*30 - (something i don't remember) + 64 = some big number as result of a calculation mistake. what can be my marks. – Akash Deep · 1 year ago

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– Wasif Jawad Hussain · 12 months ago

Aakash did you gave the tallentex exam 2015 from B D public school ? I think we both were sitting together .Log in to reply

– Akash Deep · 12 months ago

yes i gave it, i recall u r also a fitjeeanLog in to reply

– Wasif Jawad Hussain · 12 months ago

Yes you are rightLog in to reply

– Ankit Kumar Jain · 12 months ago

In the combi question I too missed the answer by 32. I subtracted 16x28 instead of 16x26....Log in to reply

How many of your answers were correct – Prakher Gaushal · 1 year ago

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– Easha Manideep D · 1 year ago

I attempted 5 and in which 2 are perfectly correct and 2 with little mistakes and the other one I am expecting it to be correct.Log in to reply

– Swapnil Das · 1 year ago

I attempted 3.5, and am expecting 42-46.Log in to reply

– Raven Herd · 1 year ago

Same here .Log in to reply

Even my state Jharkhand had the same paper... – Ankit Kumar Jain · 1 year ago

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– Gyanendra Prakash · 3 months, 2 weeks ago

no it didn't have the same oneLog in to reply

– Raven Herd · 1 year ago

Rajasthan also had the same .Log in to reply

Answer to question no.4

Initially count the number of ways you can select 3 objects from 32. - 32C3

Then subtract the ways in which diametrically opposite pairs exist none of them are adjacent - 16.26

Then subtract the ways in which adjacent pairs exist none of which are diametrically opposite. - 32.28

Then also subtract which are both diametrically opp and adjacent - 16.4

Hence totally 32.31.5 - 16.26 - 32.28 - 16.4 – Easha Manideep D · 1 year ago

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Well I am in class 11 – Prakher Gaushal · 1 year ago

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Approximately 55 – Prakher Gaushal · 1 year ago

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– Swapnil Das · 1 year ago

It is said to be 34 here in class 9.Log in to reply

– Swapnil Das · 1 year ago

Huh..Strange. Does it vary with region and class of the candidate?Log in to reply

What do you think will be the cutoff? – Swapnil Das · 1 year ago

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What was the answer of Q.4? – Prakher Gaushal · 1 year ago

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Hi,I am also from U.P(Varanasi). I did 2 questions correct but missed one case in ques.3 ,got only 1 answer in ques.6(there are 5) and doubtful about ques.4 How much did you solve:) – Siddharth Singh · 1 year ago

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Even Rajasthan RMO had same paper. – Akshat Sharda · 1 year ago

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– Vaibhav Prasad · 1 year ago

chhattisgarh also had the same paperLog in to reply

Answer to question 6. Let \[a=m+\frac{b}{c}\] where \(m\) is any integer and \[0<b<c\] . Then \[a(a-3{a})=( m+\frac{b}{c})( m-2\frac{b}{c}) \] \[m^{2}-\frac{bm}{c}+\frac{2b^{2}}{c^{2}}\]. \[m^{2}-\frac{2b^{2}-bcm}{c^{2}}\] Now, \(m\) is an integer . Let's consider \[ \frac{2b^{2}-bcm}{c^{2}}=k\] where \(k\) is an integer . After solving we get \[\frac{b}{c}=\frac{m+_{-}\sqrt{m^{2}+8k}}{4}\].....(I) But \[\frac{b}{c}<1\]....(II) Now putting value of \(\frac{b}{c}\) from (I) to (II). We get \[m+k<2\] Therefore there are infinitely many integers \(m,k\) such that \[m+k<2\]. Hence proved. – Shivam Jadhav · 1 year ago

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– Akshat Sharda · 1 year ago

Don't you think \(m\) must be equal to \(4\).Log in to reply

– Rishik Jain · 1 year ago

m should equal 4Log in to reply

– Swapnil Das · 1 year ago

Hey when will cutoff be declared?Log in to reply