root value

How to caluclate root of 2

Note by Sai Venkata Raju Nanduri
6 years, 5 months ago

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6 votes

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We can use this method to calculate the root of 2 or any other non-square integer.

http://en.wikipedia.org/wiki/Methodsofcomputingsquareroots

After 5 steps computing using the CASIO fx-500MS calculator, I got 21.414213562 \sqrt{2} \approx 1.414213562

Đức Việt Lê - 6 years, 5 months ago

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u are correct

Vamsi Krishna Appili - 6 years, 5 months ago

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One method I learned was use the binomial theorem. (1+1)^(1/2)

Harrison Lian - 6 years, 5 months ago

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But, how can you calculate 2^(1/2)? I didn't know about that method. Can you tell me please?

Đức Việt Lê - 6 years, 5 months ago

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ask google

Vamsi Krishna Appili - 6 years, 5 months ago

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2122^{\frac {1}{2}} is the same as 22\sqrt[2]{2}, which is the same as 2\sqrt 2. Infact, xn\sqrt[n]{x} is the same as x1nx^{\frac {1}{n}}.

Shourya Pandey - 6 years, 5 months ago

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@Shourya Pandey Yes I knew it before I post. But are there any other methods to calculate a power of 1n \frac{1}{n} with n integer?

Đức Việt Lê - 6 years, 5 months ago

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Yes very good

Justin Wong - 6 years, 5 months ago

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however if you know the basic of number theory and if you know the theorem of "continued infinite fractions" then you could find square root of any integer as a form of continued fraction tending to infinity....

Sayan Chaudhuri - 6 years, 5 months ago

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Le V is correct....

its 1.414

Vamsi Krishna Appili - 6 years, 5 months ago

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take a calculator.the type like this (2)^1/2.then press "=".you will get the answer.

Sreehari Vp - 6 years, 5 months ago

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by using taylor - macloren method

Ahmed Magdy - 6 years, 5 months ago

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around 1.414

Tan Li Xuan - 6 years, 5 months ago

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read NCERT of class 8 chapter 6

Genious Boy - 6 years, 4 months ago

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read NCERT of class 8 chapter 6

Neeraj Kadian - 6 years, 4 months ago

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One of my favorite ways is to solve the diophantine equation x^2-2y^2=1 for positive integers x and y. The larger the integers, the better x/y approximates the square root of 2. You can find solutions using Brahmagupta's chakravala (cyclic) method, which is an elegant algorithm for finding solutions to Pell equations.

Jason Martin - 6 years, 4 months ago

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you are 17...so well by ur standard, Let x be the nearest perefct square near it, i.e. 1... f(x) = x, i.e. 1; so f'(x) = nx^(n-1) putting n=1/2, f'(x) = (x^(-1/2))/2 = 1/(sqrt{1}) now f(x+delta(x)) = f(x) + f'(x)delta(x) = 1 + 1/21 = 1 + .5 = 1.5(approx) but to find the actual value, use the division method as u did in the earlier classes VII or VIII but for the larger no. such as 345 or 234, this method is quite awesome...

Shubham Sharma - 6 years, 5 months ago

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Use scientific calculator.

Gil Deon Basa - 6 years, 5 months ago

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