This note is part of the set Select a number. Check out the rules here.

Here are the simple statistics for the \(10\) rounds of Select a number.

Total Points :

\(1\) Yash Singhal \(304.5\)

\(2\) Math Man \(292.04\)

\(3\) Tan Li Xuan \(290.17\)

However, as there are significantly less people in the last round, the points obtained are quite high (outliers). So, the top \(3\) for the first \(9\) rounds are worth pointing out too.

\(1\) Mursalin Habib \(236.78\)

\(2\) Anuj Shikarkhane \(234.26\)

\(3\) Yash Singhal \(221.78\)

Kudos for Yash Singhal for being in the top \(3\) for both all rounds and Rounds \(1 - 9\) despite only participating in a total of \(8\) rounds!

Next, we have a look at the mean.

Technically, the \(3\) highest mean scorers would be Sai Prasanth Pao, Ayush Vardhan Sinha and Pang Robin. (with a huge lead)

However, since they only participated in only one round, so the mean might not be accurate (especially only Round \(10\))

So, we list only those who participated in at least \(3\) rounds as a general law :

\(1\) Krishna Sharma \(49.23\)

\(2\) Utkarsh Dwivedi \(44.9\)

\(3\) Yash Singhal \(38.06\)

Also, since the last round is quite an outlier, we'll list the top for the first \(9\) rounds.

\(1\) Dhruv Bhasin \(31.7\)

\(2\) Yash Singhal \(31.68\)

\(3\) Kinshuk Singh \(31.155\)

Also, we also list those who participated in all rounds :

Tan Li Xuan

Math Man

Thanks for all other participants for your support so that Select a number can run successfully. Thanks!

## Comments

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TopNewestInteresting Game ......Alas! I missed it – Somoy Subandhu · 2 years ago

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I can't believe I forgot to submit in the last round! – Mursalin Habib · 2 years ago

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– Zi Song Yeoh · 2 years ago

Ya, if you did, I think you'll definitely get #1 as the last round was a serious outlier. Still, you are still #1 most of the time and after 9 rounds. :)Log in to reply

I participated only in 3 :( – Krishna Sharma · 2 years ago

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– Zi Song Yeoh · 2 years ago

But you have the highest mean overall! Congrats!Log in to reply