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# Simplification of the above method.

We had the step $$\dfrac{2\times 9}{3\times4}.$$ If there are common factors between the numerator and denominator, cancel them before multiplying the terms in numerator and denominator. Thus$$\dfrac{2\times9}{3\times4}=\dfrac{1*(2)\times3*(3)}{1*(3)\times2*(2)}.~\\ \dfrac{(2)\times(3)}{(3)\times(2)}=1.~~~~\\ \therefore ~\dfrac{1*(2)\times3*(3)}{1*(3)\times2*(2)}= \dfrac{1\times3}{1\times2}=\dfrac{3}{2}.$$

Note by Niranjan Khanderia
2 years, 5 months ago

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@Niranjan Khanderia Why are you making it so complex. You can do it fast by directly cancelling. · 2 years, 4 months ago