# Simplification of the above method.

We had the step $$\dfrac{2\times 9}{3\times4}.$$ If there are common factors between the numerator and denominator, cancel them before multiplying the terms in numerator and denominator. Thus$$\dfrac{2\times9}{3\times4}=\dfrac{1*(2)\times3*(3)}{1*(3)\times2*(2)}.~\\ \dfrac{(2)\times(3)}{(3)\times(2)}=1.~~~~\\ \therefore ~\dfrac{1*(2)\times3*(3)}{1*(3)\times2*(2)}= \dfrac{1\times3}{1\times2}=\dfrac{3}{2}.$$

Note by Niranjan Khanderia
3 years, 8 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

@Niranjan Khanderia Why are you making it so complex. You can do it fast by directly cancelling.

- 3 years, 7 months ago

You are right. However for those who can not do that. I have come across beginners that need this.

- 3 years, 7 months ago