0.6666...+0.77777...+0.88888....+.33333... yields the result:

a-2(3/10)

b-2(2/3)

c-2.353535...

d-5(3/10)

a-2(3/10)

b-2(2/3)

c-2.353535...

d-5(3/10)

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## Comments

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TopNewest\(0.\dot{6} + 0.\dot{7} + 0.\dot{8} + 0.\dot{3} = \dfrac{6}{9} + \dfrac{7}{9} + \dfrac{8}{9} + \dfrac{3}{9} = \dfrac{6+7+8+3}{9} = \dfrac{24}{9} = \dfrac{8}{3} = 2\frac{2}{3}\) – Chew-Seong Cheong · 2 years ago

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– Mehdi Balti · 2 years ago

Thanks buddy :)Log in to reply

0.666...+0.777...+0.888...+0.3333...

let x=0.888..

100x=88.888..

minus the first two values

99x=88

x=(88/ 99 } =8/8

repeat steps for all values and you get

(2/3)+(7/9)+(8/9)+(1/3)

=(8/3)

=2(2/3)

Sorry don't know how to use LaTeX! – Raghav Arora · 2 years ago

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– Mehdi Balti · 2 years ago

Thank you :)Log in to reply

b – Mrinmay Dhar · 2 years ago

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– Raghav Arora · 2 years ago

Brilliant solution, couldn't have thought of a better way to solve it.Log in to reply

– Mrinmay Dhar · 2 years ago

What you did there, I see it.Log in to reply

– Mehdi Balti · 2 years ago

Yeap got it well :)Thanks all of youLog in to reply

– Mehdi Balti · 2 years ago

Thanks dear :*Log in to reply