New user? Sign up

Existing user? Log in

0.6666...+0.77777...+0.88888....+.33333... yields the result: a-2(3/10) b-2(2/3) c-2.353535... d-5(3/10)

Note by Mehdi Balti 4 years, 1 month ago

$</code> ... <code>$</code>...<code>."> Easy Math Editor

*italics*

_italics_

**bold**

__bold__

- bulleted- list

1. numbered2. list

paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)

> This is a quote

This is a quote

# I indented these lines # 4 spaces, and now they show # up as a code block. print "hello world"

2 \times 3

2^{34}

a_{i-1}

\frac{2}{3}

\sqrt{2}

\sum_{i=1}^3

\sin \theta

\boxed{123}

Sort by:

$0.\dot{6} + 0.\dot{7} + 0.\dot{8} + 0.\dot{3} = \dfrac{6}{9} + \dfrac{7}{9} + \dfrac{8}{9} + \dfrac{3}{9} = \dfrac{6+7+8+3}{9} = \dfrac{24}{9} = \dfrac{8}{3} = 2\frac{2}{3}$

Log in to reply

Thanks buddy :)

0.666...+0.777...+0.888...+0.3333...

let x=0.888..

100x=88.888..

minus the first two values

99x=88

x=(88/ 99 } =8/8

repeat steps for all values and you get

(2/3)+(7/9)+(8/9)+(1/3)

=(8/3)

=2(2/3)

Sorry don't know how to use LaTeX!

Thank you :)

b

Brilliant solution, couldn't have thought of a better way to solve it.

Yeap got it well :)Thanks all of you

What you did there, I see it.

Thanks dear :*

Problem Loading...

Note Loading...

Set Loading...

$</code> ... <code>$</code>...<code>."> Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in $</span> ... <span>$ or $</span> ... <span>$ to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewest$0.\dot{6} + 0.\dot{7} + 0.\dot{8} + 0.\dot{3} = \dfrac{6}{9} + \dfrac{7}{9} + \dfrac{8}{9} + \dfrac{3}{9} = \dfrac{6+7+8+3}{9} = \dfrac{24}{9} = \dfrac{8}{3} = 2\frac{2}{3}$

Log in to reply

Thanks buddy :)

Log in to reply

0.666...+0.777...+0.888...+0.3333...

let x=0.888..

100x=88.888..

minus the first two values

99x=88

x=(88/ 99 } =8/8

repeat steps for all values and you get

(2/3)+(7/9)+(8/9)+(1/3)

=(8/3)

=2(2/3)

Sorry don't know how to use LaTeX!

Log in to reply

Thank you :)

Log in to reply

b

Log in to reply

Brilliant solution, couldn't have thought of a better way to solve it.

Log in to reply

Yeap got it well :)Thanks all of you

Log in to reply

What you did there, I see it.

Log in to reply

Thanks dear :*

Log in to reply