\(sin 53^ \circ \) is \( \frac{4}{5}\) not \(sin 63^ \circ \)
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Nishanth Hegde
·
4 years, 5 months ago

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They are approximate. Generally we come across the 3-4-5 right angles, so that we need the angles of the triangle, and actually sin 37 = 0.601..... , which is nearly 0.6=3/5. So (sin 37)^2 +(sin 63)^2=1, so that sin 63=4/5.
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Shourya Pandey
·
4 years, 5 months ago

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TopNewest\(sin 53^ \circ \) is \( \frac{4}{5}\) not \(sin 63^ \circ \) – Nishanth Hegde · 4 years, 5 months ago

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They are approximate. Generally we come across the 3-4-5 right angles, so that we need the angles of the triangle, and actually sin 37 = 0.601..... , which is nearly 0.6=3/5. So (sin 37)^2 +(sin 63)^2=1, so that sin 63=4/5. – Shourya Pandey · 4 years, 5 months ago

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