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Why we write sin37=3/5&sin63=45 Expect proof...

Note by Parag Mundhada 5 years, 4 months ago

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\(sin 53^ \circ \) is \( \frac{4}{5}\) not \(sin 63^ \circ \)

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They are approximate. Generally we come across the 3-4-5 right angles, so that we need the angles of the triangle, and actually sin 37 = 0.601..... , which is nearly 0.6=3/5. So (sin 37)^2 +(sin 63)^2=1, so that sin 63=4/5.

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`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

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TopNewest\(sin 53^ \circ \) is \( \frac{4}{5}\) not \(sin 63^ \circ \)

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They are approximate. Generally we come across the 3-4-5 right angles, so that we need the angles of the triangle, and actually sin 37 = 0.601..... , which is nearly 0.6=3/5. So (sin 37)^2 +(sin 63)^2=1, so that sin 63=4/5.

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