From a point in the interior of an equilateral triangle,perpendiculars to the three sides are \(8cm.\),\(10cm.\) and\(11cm.\) Find the area of the triangle to nearest \(cm.^2\)

No vote yet

1 vote

×

Problem Loading...

Note Loading...

Set Loading...

## Comments

Sort by:

TopNewestSee this. – Pi Han Goh · 1 year, 10 months ago

Log in to reply

– Rohit Udaiwal · 1 year, 10 months ago

Can you briefly explain the solution?Log in to reply

– Pi Han Goh · 1 year, 10 months ago

You're given \(h_a, h_b,h_c \) right? Now you can find \(h_a^{-1},h_b^{-1},h_c^{-1} \) and \(H\). So you can find \(A\).Log in to reply

– Rohit Udaiwal · 1 year, 10 months ago

Where it is given (height ) as heights are equal in eq.triangle?Log in to reply

See this. – Pi Han Goh · 1 year, 10 months ago

Oh. I interpreted this question wrongly.Log in to reply

– Rohit Udaiwal · 1 year, 10 months ago

Thanks.that was helpful \(\ddot\smile\)Log in to reply