# So what do you think 2?

From a point in the interior of an equilateral triangle,perpendiculars to the three sides are $$8cm.$$,$$10cm.$$ and$$11cm.$$ Find the area of the triangle to nearest $$cm.^2$$

Note by Rohit Udaiwal
2 years, 9 months ago

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## Comments

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- 2 years, 9 months ago

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Can you briefly explain the solution?

- 2 years, 9 months ago

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You're given $$h_a, h_b,h_c$$ right? Now you can find $$h_a^{-1},h_b^{-1},h_c^{-1}$$ and $$H$$. So you can find $$A$$.

- 2 years, 9 months ago

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Where it is given (height ) as heights are equal in eq.triangle?

- 2 years, 9 months ago

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Oh. I interpreted this question wrongly. See this.

- 2 years, 9 months ago

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Thanks.that was helpful $$\ddot\smile$$

- 2 years, 9 months ago

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