From a point in the interior of an equilateral triangle,perpendiculars to the three sides are \(8cm.\),\(10cm.\) and\(11cm.\) Find the area of the triangle to nearest \(cm.^2\)

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Can you briefly explain the solution?

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You're given \(h_a, h_b,h_c \) right? Now you can find \(h_a^{-1},h_b^{-1},h_c^{-1} \) and \(H\). So you can find \(A\).

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See this.

Oh. I interpreted this question wrongly.Log in to reply

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