×

So what do you think 2?

From a point in the interior of an equilateral triangle,perpendiculars to the three sides are $$8cm.$$,$$10cm.$$ and$$11cm.$$ Find the area of the triangle to nearest $$cm.^2$$

Note by Rohit Udaiwal
1 year, 1 month ago

Comments

Sort by:

Top Newest

See this. · 1 year, 1 month ago

Log in to reply

Can you briefly explain the solution? · 1 year, 1 month ago

Log in to reply

You're given $$h_a, h_b,h_c$$ right? Now you can find $$h_a^{-1},h_b^{-1},h_c^{-1}$$ and $$H$$. So you can find $$A$$. · 1 year, 1 month ago

Log in to reply

Where it is given (height ) as heights are equal in eq.triangle? · 1 year, 1 month ago

Log in to reply

Oh. I interpreted this question wrongly. See this. · 1 year, 1 month ago

Log in to reply

Thanks.that was helpful $$\ddot\smile$$ · 1 year, 1 month ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...