Waste less time on Facebook — follow Brilliant.
×

So what do you think 2?

From a point in the interior of an equilateral triangle,perpendiculars to the three sides are \(8cm.\),\(10cm.\) and\(11cm.\) Find the area of the triangle to nearest \(cm.^2\)

Note by Rohit Udaiwal
2 years, 1 month ago

No vote yet
1 vote

Comments

Sort by:

Top Newest

See this.

Pi Han Goh - 2 years, 1 month ago

Log in to reply

Can you briefly explain the solution?

Rohit Udaiwal - 2 years, 1 month ago

Log in to reply

You're given \(h_a, h_b,h_c \) right? Now you can find \(h_a^{-1},h_b^{-1},h_c^{-1} \) and \(H\). So you can find \(A\).

Pi Han Goh - 2 years, 1 month ago

Log in to reply

@Pi Han Goh Where it is given (height ) as heights are equal in eq.triangle?

Rohit Udaiwal - 2 years, 1 month ago

Log in to reply

@Rohit Udaiwal Oh. I interpreted this question wrongly. See this.

Pi Han Goh - 2 years, 1 month ago

Log in to reply

@Pi Han Goh Thanks.that was helpful \(\ddot\smile\)

Rohit Udaiwal - 2 years, 1 month ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...