Solve this....

The sum of 5 different positive integers is 90. What can be the 2nd largest number of the 5 at most?

These were the options qiven when I tried the question:

\(1)\)82

\(2)\)43

\(3)\)34

\(4)\)73

I got \(41\) as the answer but didn't found them in options so was confused. Let me know what answer do you guys get.

PLEASE give it a try.

Thanks.

Note by Akshat Sharda
3 years, 1 month ago

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1 vote

  Easy Math Editor

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41

Kushagra Sahni - 3 years, 1 month ago

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Tried it, and got 41. So maybe it's a mistake and someone accidentally put 43 instead of 41?

Tytan Le Nguyen - 3 years, 1 month ago

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I think it has considered zero to be a +ve integer as well. That way the answer would be 43.

But considering zero is neither +ve nor -ve, the correct answer should definitely be 41.

Tapas Mazumdar - 3 years, 1 month ago

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41

Aditya Chauhan - 3 years, 1 month ago

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I got the same.

Akshat Sharda - 3 years, 1 month ago

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If we consider 0 then it comes to be 43 but in other case we have 42+41+4+2+1.

Keshav Bassi - 3 years, 1 month ago

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