×

# Solve this....

The sum of 5 different positive integers is 90. What can be the 2nd largest number of the 5 at most?

These were the options qiven when I tried the question:

$$1)$$82

$$2)$$43

$$3)$$34

$$4)$$73

I got $$41$$ as the answer but didn't found them in options so was confused. Let me know what answer do you guys get.

Thanks.

Note by Akshat Sharda
2 years, 5 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

41

- 2 years, 5 months ago

Tried it, and got 41. So maybe it's a mistake and someone accidentally put 43 instead of 41?

- 2 years, 5 months ago

I think it has considered zero to be a +ve integer as well. That way the answer would be 43.

But considering zero is neither +ve nor -ve, the correct answer should definitely be 41.

- 2 years, 5 months ago

41

- 2 years, 5 months ago

I got the same.

- 2 years, 5 months ago

If we consider 0 then it comes to be 43 but in other case we have 42+41+4+2+1.

- 2 years, 5 months ago