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X = 2 + 2^(2/(3 ))+ 2^(1/3) So, x^3-6 x^2+6= ???

Note by Napier Jn 4 years, 7 months ago

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Given \(x = 2+\sqrt{2}+\sqrt[2]{2}\Rightarrow (x-2)^3 = \left(\sqrt{2}+\sqrt[2]{2}\right)^3\)

We Get \(x^3 -8-6x(x-2) = 2+2^2+3\times 2 \left(\sqrt{2}+\sqrt[2]{2}\right) = 6+6x\)

Now Solve after that....

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Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

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Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

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TopNewestGiven \(x = 2+\sqrt{2}+\sqrt[2]{2}\Rightarrow (x-2)^3 = \left(\sqrt{2}+\sqrt[2]{2}\right)^3\)

We Get \(x^3 -8-6x(x-2) = 2+2^2+3\times 2 \left(\sqrt{2}+\sqrt[2]{2}\right) = 6+6x\)

Now Solve after that....

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