# solve this

X = 2 + 2^(2/(3 ))+ 2^(1/3) So, x^3-6 x^2+6= ???

Note by Napier Jn
4 years, 7 months ago

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Given $$x = 2+\sqrt{2}+\sqrt[2]{2}\Rightarrow (x-2)^3 = \left(\sqrt{2}+\sqrt[2]{2}\right)^3$$

We Get $$x^3 -8-6x(x-2) = 2+2^2+3\times 2 \left(\sqrt{2}+\sqrt[2]{2}\right) = 6+6x$$

Now Solve after that....

- 4 years, 7 months ago

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