Waste less time on Facebook — follow Brilliant.
×

Solve this!

Look Closely...it's a quadratic equation. Now find the number of solutions it has.

Note by Diksha Verma
4 years, 3 months ago

No vote yet
3 votes

Comments

Sort by:

Top Newest

take L.H.S=f(x), and it is easy to show that f'(x)=0; for all x. ie, f(x)= k = f(-a)= 1, so for all x f(x)=1; Nidhin Kurian · 4 years, 3 months ago

Log in to reply

@Nidhin Kurian That is a good observation. A simpler approach would be to make common denominator and consider the quadratic polynomial in \(x\), and easily see that the quadratic coefficient and linear coefficient are both 0. Calvin Lin Staff · 4 years, 3 months ago

Log in to reply

If the L.H.S=f(x) (if none of the a,b,c's are equal to each other) then f(x)=1 for all x in R. So f(x)-1=0 for all x in R. Thus f(x)-1=p(x) is the zero polynomial and not a quadratic. Samuel Queen · 4 years, 3 months ago

Log in to reply

yes, my answer of -a, -b, -c is not correct as indeed it is an identity function the equation is satisfied for all x belonging to R. Nidhin Kurian · 4 years, 3 months ago

Log in to reply

its, not a quadratic equation as such because it has 3 real roots Nidhin Kurian · 4 years, 3 months ago

Log in to reply

@Nidhin Kurian yah! u r right its an identity............ just for confusion. Diksha Verma · 4 years, 3 months ago

Log in to reply

I wonder. Did you get this from Praveen Tyagi's FB profile? Parth Kohli · 4 years, 3 months ago

Log in to reply

@Parth Kohli ?? Diksha Verma · 4 years, 3 months ago

Log in to reply

@Diksha Verma Look, you just liked my comment. lol Parth Kohli · 4 years, 3 months ago

Log in to reply

yes Nidhin Kurian · 4 years, 3 months ago

Log in to reply

@Nidhin Kurian can u write the solution plsss.... Riya Gupta · 4 years, 3 months ago

Log in to reply

the roots are -a,-b,-c, assuming a, b, c are distinct real numbers Nidhin Kurian · 4 years, 3 months ago

Log in to reply

@Nidhin Kurian how did you got the answer? plzzz explain....i'm not able to solve! :| Riya Gupta · 4 years, 3 months ago

Log in to reply

@Riya Gupta You got 1 on both sides? Aditya Parson · 4 years, 3 months ago

Log in to reply

@Aditya Parson i am not getting a clear solution Riya Gupta · 4 years, 3 months ago

Log in to reply

@Riya Gupta Because if you take lcm of the denominators and expand, and do some algebra there is no x left, infact u get 1=1 Aditya Parson · 4 years, 3 months ago

Log in to reply

@Aditya Parson arey.....i took the denominator on the r.h.s. and got 0=0

but m wondering how to get solutions......

this equation is forming an identity i guess Riya Gupta · 4 years, 3 months ago

Log in to reply

@Riya Gupta 1=1 implies 1-1=0 so 0=0 :P right? Aditya Parson · 4 years, 3 months ago

Log in to reply

@Aditya Parson very funny.......ha! :/ Riya Gupta · 4 years, 3 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...