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Note by Mohammed Shams
4 years, 6 months ago

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2 votes

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

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if any one can help me i would really appreciate it

Mohammed Shams - 4 years, 6 months ago

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Solution by observation: \(x=3\). That makes our equation \(3=1+\omega^{3}+\omega^{6}\) which is true.

Vikram Waradpande - 4 years, 6 months ago

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Thanks i have already knew that but actually i was trying to find a more mathematical or algebric proof , you know something probably includes the logarithms and using only variables instead of this logic proof so i would be grateful if u can help me :)

Mohammed Shams - 4 years, 6 months ago

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Solve x = 1 + w^x + w^(2*x) , where 1 , w , w^2 are the roots of unity

Mohammed Shams - 4 years, 6 months ago

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