Some bizarre questions that need urgent attention?!!

Can anyone help with these easy, medium and hard questions?

(1) How many ways are there of placing a single \( 3 \times 1 \) rectangle on this grid so that it completely covers 3 grid squares?

(2) A number is a palindrome if it reads the same as forwards as backwards. The number 131131 is a palindrome; also its first pair of digits, middle and the last pair are prime numbers. How many such 6-digit palindromes are there?

(3) I have a large number of toy soldiers, which I can arrange into a rectangle array consisting of rows and a number of columns. I notice that if I remove 100 toy soldiers, then I can arrange the remaining ones into a rectangle with 5 fewer rows and 5 more columns.

How many toy soldiers would I have to remove from the original configuration to be able to arrange the remaining ones into a rectangular array with 11 fewer rows and 11 more columns?

(4) How many 3 digit numbers are there such that it is equal to the sum of its digits multiplied by 13?

(5) 1 Googol is \(G = 10^{100}\) whereas 1 Googleplex is \( 10^G\). Let \(n\) be the largest whole number for which \(n^n < 10^G.\) How many digits does \( n\) have?

(6) There is a square tabletop filled with small square-shaped tiles. The sum of the squares that form the 2 diagonals is 25. Find the area of the tabletop.

(7) I have a cube which has a surface area of \(X\). I slice it into 2 to get 2 (different or same) prisms. (The diagram shows how it has been cut). If one of the prism's surface area is \(\dfrac{1}{2} \) of \(X\), then find the surface area of the other prism in relation to \(X\).

(8) This is a right-angled triangle. Find the ratio between the unshaded region to the shaded region using the letters in all cases. \(a, b,c\). Note the blue colour shaded is a square.

(9) A quadrilateral has two parallel sides measuring 25 cm and 37 cm. What is the distance in centimetres, between the midpoints of the diagonals?

That's all for today, folks!


I also wanted to make note of Q5; I myself tried it and came till here; if anyone can help so tell me in the comments.

We know:

\(G = 10^{100}\) and 1 Googlepex is = \(10^G = 10^{10^{100}}\) .

To find the number of digits of \(n\), we have to find an exponential representation of \(n\). Then we can use the theorem:

For any positive integer \(n\), the number of digits in \(n\) is \(\left\lfloor \log_{10} n \right\rfloor + 1\). (It can be found on this wiki )

So, I tried to use the inequality: \(\large n^n < 10^{10^{100}} \)

First I converted into an equation: \( n^n = 10^{10^{100}} \) and then I didn't understand how to subject \(n\).

These are what I attempted: \[ \log_n 10^{10^{100}} = n \implies G \log_n 10 = n\]

But I didn't receive any help. Please help me.


I might be adding some more problems in this note this week only so please be updated. I hope to get answers with extremely clear language and makes notes of all theorems used in solving with each method presented carefully and neatly. Please make use of Latex in your answers. I thank everyone who tried.

Note by Syed Hamza Khalid
3 weeks, 2 days ago

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  Easy Math Editor

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7.Let the area of each face of the cube be \(x\), so \(X=6x\).

If we slice it into two, then the surface area will increase by \(2x\), so it will become \(8x\).

One of the prism has surface area of \(3x\), because it has half the surface area of the original cube.

So, the other prism has surface area of \(8x-3x=5x\)

X X - 2 weeks, 6 days ago

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Q.5 \((10^a)^{(10^a)}=10^{a\times10^a}\), so \(a\times10^a\) need to be close to \(10^{100}\). We have \(98\times10^{98}<10^{100}<99\times10^{99}\) , so \(10^{98}<n<10^{99}\)

X X - 3 weeks, 2 days ago

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Can u give some explanation, why? when? how? to use something?

Syed Hamza Khalid - 3 weeks, 2 days ago

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I let \(n=10^a\) because if I find the \(a\) then i will know the number of digits of \(n\).

X X - 3 weeks, 1 day ago

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@X X Oh okay you should have mentioned that because I was shocked to see \( a \) [I had no idea what it was]

Syed Hamza Khalid - 3 weeks, 1 day ago

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@Syed Hamza Khalid Sorry, I forgot to say that. Thanks for pointing out!

X X - 3 weeks ago

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@X X Welcome

Syed Hamza Khalid - 3 weeks ago

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So what's the final answer? You have not exactly responded to the question { we have to find the number of digits in \( n \)}

Syed Hamza Khalid - 3 weeks, 2 days ago

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If \(10^{98}<n<10^{99}\), then it is easy to know the number of digits in \(n\)

X X - 3 weeks, 1 day ago

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@X X Is the answer between 99 and 100? However, for this question, only integers are allowed!

Syed Hamza Khalid - 2 weeks, 6 days ago

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@Syed Hamza Khalid Actually, the answer will simply come out to be 99!!!

Aaghaz Mahajan - 2 weeks, 6 days ago

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@X X Yep I got that!

Syed Hamza Khalid - 3 weeks, 1 day ago

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Q.1 7(4-2)+4(7-2)=34

X X - 3 weeks, 2 days ago

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How? Is there some kind of theorem, formula or something?

Syed Hamza Khalid - 3 weeks, 2 days ago

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You can try to place the 1x3 on the 4x7 grid, and you will know what the expression means.

X X - 3 weeks, 1 day ago

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@X X Please tell. I have a contest tomorrow! PLEASE!

Syed Hamza Khalid - 3 weeks ago

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@Syed Hamza Khalid Consider it as two kinds. One is to put the 1x3 horizontally, and the other is to put it vertically.

X X - 3 weeks ago

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@X X Put it horizontally makes it 20 possibilities, and vertically makes it 14 possibilities.

X X - 3 weeks ago

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@X X yeah got it thanks

Syed Hamza Khalid - 2 weeks, 6 days ago

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@Syed Hamza Khalid Can u help for other problems?

Syed Hamza Khalid - 2 weeks, 6 days ago

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@X X Please tell how?

Syed Hamza Khalid - 3 weeks ago

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@X X Actually, I didn't get it yet. can u give a slightly detailed answer, please?

Syed Hamza Khalid - 3 weeks, 1 day ago

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8.Let the side length of the square be \(x\). There are some triangle that are similar(Sorry, I'm lazy to draw a picture for this), so \((b-x):x=b:a, ab-ax=bx,x=\frac{ab}{a+b}\).

The area of the square is \(\frac{a^2b^2}{(a+b)^2}\), and the area of the big triangle is \(\frac{ab}2\).

So, the ratio between the square and the triangle is \(2ab:(a+b)^2\),

and the ratio between the colored region and the white region is \(2ab:(a^2+b^2+2ab-2ab)=2ab:(a^2+b^2)\).

X X - 2 weeks, 6 days ago

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Thanks for your effort. I had the AMC and I screwed up some easy questions :(

I will try again next year and hope for a score > 100.

Syed Hamza Khalid - 2 weeks, 2 days ago

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Wait,how about \(c\)?You missed \(c\)!

Gia Hoàng Phạm - 2 weeks, 4 days ago

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Oh, you probably means \(2ab:c^2\).

X X - 2 weeks, 4 days ago

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Q.2

let \(abcdef\) represent a six-digit number and each letter represent one digit. For \(abcdef\) to be a palindrome, it must be the same forwards and backwards. Therefore, as long as \(a=f\), \(b=e\), and \(c=d\), there are \(9\times 10\times 10=900\) six digit palindromes.

Hana Wehbi - 3 weeks, 2 days ago

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how? in addition to that it should be prime?

Syed Hamza Khalid - 3 weeks, 2 days ago

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We are taking here all the possibilities.

Hana Wehbi - 3 weeks ago

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@Hana Wehbi But that is not the question...

Syed Hamza Khalid - 2 weeks, 6 days ago

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Q.4 The answer is 3 such numbers....viz 117,156 and 195

Aaghaz Mahajan - 3 weeks, 2 days ago

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How do you know that these are the only no.s

Syed Hamza Khalid - 3 weeks, 2 days ago

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How did u find it

Syed Hamza Khalid - 3 weeks, 2 days ago

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Well Let the number be abc.......
Now, according to the question,
87a = 3b +12c i.e.
29a = b +4c
Now observe that a can only be equal to one..........I think you can solve it now

Aaghaz Mahajan - 3 weeks ago

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Q.3 \(ab-100=(a+5)(b-5),15=a-b\), so \(ab-(a+11)(b-11)=11a-11b+121=11\times15+121=286\)

X X - 3 weeks, 2 days ago

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Can you tell the method with reasoning? please for ur answers

Syed Hamza Khalid - 3 weeks, 2 days ago

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Let there are a columns and b rows. The other parts are algebra.

X X - 3 weeks, 1 day ago

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@X X Thanks! Got it; but at the end what did you do? 121 = 44? I don't get that.

Shouldn't it be like \(\implies 11a - 11b + 121 = 11(a - b) +121 = (11 \times 15) +121 = \boxed{ 286 } \)

Syed Hamza Khalid - 3 weeks, 1 day ago

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@Syed Hamza Khalid Sorry, two typos(such a big mistake!).

X X - 3 weeks ago

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@X X Its okay; we all are humans! Can u help me for the Q1 method with reasoning?

Syed Hamza Khalid - 3 weeks ago

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