Prove the following just by drawing a single line:

```
5 + 5 + 5 = 550 [You cannot use the line on equality.]
```

THE EASY ONE - Use a number 3 times and addition sign(s) to get the number 60. You cannot use 20.

Another EASY ONE - Use the following only once to make an equation-

2, 3, 4, 5, = , +.

## Comments

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TopNewestQuestion 1\(5 + 545 = 550\)

Question 2\(5 + 55 = 60\)

Question 3\(4 + 5 = 3^2\)

Am I right? – Sharky Kesa · 2 years, 12 months ago

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otherwise you are absolutely correct!!!

You cannot use even "+" sign more than once!!! – Kartik Sharma · 2 years, 12 months ago

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– Sharky Kesa · 2 years, 12 months ago

Oh, then what you said.Log in to reply

– Kartik Sharma · 2 years, 12 months ago

sorry?Log in to reply

Question 3:

4+5=3²

Question 1: Is this possible?

5 + 5 4 5 = 550 (draw a line through the plus sign to make it a four) – Prakriti Bansal · 3 years ago

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– Kartik Sharma · 3 years ago

Yeah, that's correct!!!Log in to reply

– Mathh Mathh · 3 years ago

or \(2+5=3+4\)Log in to reply

– Prakriti Bansal · 3 years ago

But I think that you can only use the addition sign once.Log in to reply

– Mathh Mathh · 3 years ago

yeah. sorry, missed where he said 'only once'.Log in to reply

Not sure if they the correct answer,

Question 2 :, using \(5\) three times, \[.\] \[55+5=60\] \[.\]\[.\]Question 1 :draw the line on the equal sign, consequently the equation becomes an inequality \[.\] \[5+5+5\neq550\] – Tasmeem Reza · 3 years agoLog in to reply

– Kartik Sharma · 3 years ago

by the way, solution to Q2 is correct!!!Log in to reply

– Kartik Sharma · 3 years ago

oh, didn't I say that you cannot use that inequality sign?Log in to reply

– Mathh Mathh · 3 years ago

You said nothing, you only told us to draw some line and he drew the line on the equality sign. There's nothing wrong with that, so if you don't like this solution, you'll have to change the problem a bit (add some constraints, e.g. 'you can't use the line on the equality sign').Log in to reply

– Kartik Sharma · 3 years ago

I have added. Thanks!Log in to reply

Answers will be posted on 1st August!! – Kartik Sharma · 3 years ago

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– Kartik Sharma · 2 years, 12 months ago

Ah! You solved them all. So, no answers I can post today!! ;)Log in to reply