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# square root of complex number

Note by Abhimanyu Manu
3 years, 1 month ago

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if you are asking about the square root of a complex number in standard form ie $$a+ib$$ the method is simple.

Let $$\sqrt{a+ib} = x+iy \Rightarrow a+ib = (x+iy)^{2}$$

simplifying we get $$a+ib = x^{2}-y^{2}+2xyi \Rightarrow a = x^{2}-y^{2}$$ and $$b = 2xy$$ · 3 years, 1 month ago

Convert your complex number into polar form, and remember that $$\sqrt{z} = z^{\frac{1}{2}}$$ · 3 years, 1 month ago

find sq. root of complex no.z=1-i · 3 years, 1 month ago

The question is ambiguous. Which square root should we give? · 3 years, 1 month ago