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Stirling's formula

Using \(N! = \displaystyle \int_0^{\infty} x^N e^{-x} dx\) (which you can prove by induction), derive Stirling's formula,

\[N! \approx N^N e^{-N} \sqrt {2 \pi N}.\]

Note by Sharky Kesa
2 years, 10 months ago

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Wikipedia page on Laplace's method has an answer. Haroun Meghaichi · 2 years, 10 months ago

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