Let S be the sum of all the six-digit numbers formed by 1, 2, 2, 3, 3, 3. Then the sum of the digits of S is
(a) 25
(b)30
(c)32
(d)35
I am getting the answer as 36. Please help me out

Is the answer 30?
I'm getting answer as 30, i.e. sum as 15555540. Total Nos. Are 60. So for one digit, 1, 2, 3 appear 10, 20, 30 times respectively. So sum of one digit is 140. Thus S = 111111*140. Which is 15555540.

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TopNewestIs the answer 30? I'm getting answer as 30, i.e. sum as 15555540. Total Nos. Are 60. So for one digit, 1, 2, 3 appear 10, 20, 30 times respectively. So sum of one digit is 140. Thus S = 111111*140. Which is 15555540.

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