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Sum of n cubes

From what I understand the sum of n cubes is \({ \left( \frac { n(n+1) }{ 2 } \right) }^{ 2 }\). Could someone prove this? I tried it with different values of n, and it always worked, but I am looking for a proof. Thanks.

Note by Shashank Rammoorthy
2 years, 7 months ago

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telescopic sums by writing in this format -

(x+1)^4 - x^4 Nihar Mahajan · 2 years, 7 months ago

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Did you try using induction? :) Mursalin Habib · 2 years, 7 months ago

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@Mursalin Habib You are right..it worked with induction. Thanks. Shashank Rammoorthy · 2 years, 6 months ago

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