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# Sum of n cubes

From what I understand the sum of n cubes is $${ \left( \frac { n(n+1) }{ 2 } \right) }^{ 2 }$$. Could someone prove this? I tried it with different values of n, and it always worked, but I am looking for a proof. Thanks.

Note by Shashank Rammoorthy
2 years, 9 months ago

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telescopic sums by writing in this format -

(x+1)^4 - x^4

- 2 years, 9 months ago

Did you try using induction? :)

- 2 years, 9 months ago

You are right..it worked with induction. Thanks.

- 2 years, 9 months ago