Waste less time on Facebook — follow Brilliant.
×

Sum of permutations!

I just found that sum of \(n\) permutations with \(i\) equals \(e\Gamma(n+1, 1)\). In other words,

\(P(n,0) + P(n,1) + P(n, 2) + .... P(n,n) = e\Gamma(n+1, 1)\). [where \(\Gamma(x,y)\) is the incomplete gamma function].

Can anyone give a proof of this?

Note by Kartik Sharma
1 year, 11 months ago

No vote yet
1 vote

Comments

Sort by:

Top Newest

Hi Kartik Sharma , see this or the solution to this question .

But if you aren't familiar with Gamma function , see the link I provided or see it here .

Hope I was useful !!! Azhaghu Roopesh M · 1 year, 11 months ago

Log in to reply

@Azhaghu Roopesh M Thanks, that was helpful. You are quite good, solves almost all the problems. Kartik Sharma · 1 year, 11 months ago

Log in to reply

@Kartik Sharma You are welcome. Azhaghu Roopesh M · 1 year, 11 months ago

Log in to reply

@Azhaghu Roopesh M Then, can you help me here too? *If only you have time. Kartik Sharma · 1 year, 11 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...