I just found that sum of \(n\) permutations with \(i\) equals \(e\Gamma(n+1, 1)\). In other words,

\(P(n,0) + P(n,1) + P(n, 2) + .... P(n,n) = e\Gamma(n+1, 1)\). [where \(\Gamma(x,y)\) is the incomplete gamma function].

Can anyone give a proof of this?

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TopNewestHi Kartik Sharma , see this or the solution to this question .

But if you aren't familiar with Gamma function , see the link I provided or see it here .

Hope I was useful !!! – Azhaghu Roopesh M · 2 years, 3 months ago

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– Kartik Sharma · 2 years, 3 months ago

Thanks, that was helpful. You are quite good, solves almost all the problems.Log in to reply

– Azhaghu Roopesh M · 2 years, 3 months ago

You are welcome.Log in to reply

here too? *If only you have time. – Kartik Sharma · 2 years, 3 months ago

Then, can you help meLog in to reply