\( \sum_{i=1}^\infty (-1)^i \) * \( \frac {1}{i} \)

I encountered this problem while doing a physics sum of magnetic fields..Please reply soon and Yeah..Thanks for your answers..

\( \sum_{i=1}^\infty (-1)^i \) * \( \frac {1}{i} \)

I encountered this problem while doing a physics sum of magnetic fields..Please reply soon and Yeah..Thanks for your answers..

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TopNewest\( \displaystyle \sum_{i=1}^{\infty} \dfrac{(-1)^i}{i} = -\log{2}\) – Gopinath No · 3 years, 10 months ago

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– Rushi Rokad · 3 years, 10 months ago

can you please explain ?Log in to reply

Looks familiar? – Pranav Arora · 3 years, 10 months ago

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– Rushi Rokad · 3 years, 10 months ago

Thanks.Log in to reply

by taylor series we have -log(1+y)= - y + (y^2)/2 + (y^3)/3........ which generates the above pattern by putting y=1 hence the answer for this is -log2 which would be around -0.30103 .. :) – Ramesh Goenka · 3 years, 10 months ago

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– Rushi Rokad · 3 years, 10 months ago

Thanks.Log in to reply