This is a totally wide open, undefined question, but I'll answer it anyway! Let's say that "tendency to change" is some function of some parameter, \(f\left(x\right)\). If, for some value \(x\), there is a symmetry about it, i.e.,\(f\left( x-\Delta x \right) =f\left( x+\Delta x \right) \), then it's a extremum, and so it could either be a point of stability or instability. Like a bowl, which could be inverted. Even when it's inverted, it doesn't necessarily mean it'll move---it first has to be knocked off center. The point is, at the extremum, there is no "tendency to change".
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Michael Mendrin
·
1 year ago

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TopNewestThis is a totally wide open, undefined question, but I'll answer it anyway! Let's say that "tendency to change" is some function of some parameter, \(f\left(x\right)\). If, for some value \(x\), there is a symmetry about it, i.e.,\(f\left( x-\Delta x \right) =f\left( x+\Delta x \right) \), then it's a extremum, and so it could either be a point of stability or instability. Like a bowl, which could be inverted. Even when it's inverted, it doesn't necessarily mean it'll move---it first has to be knocked off center. The point is, at the extremum, there is no "tendency to change". – Michael Mendrin · 1 year ago

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Thank u guys – Rithik Sharma · 1 year ago

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Where? In what situation? Unless you give us some more detail, any answers will probably be too general to be useful. – Raj Magesh · 1 year ago

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– Michael Mendrin · 1 year ago

Sure. Think of a boat in water. Boats are usually symmetrical along the center vertical plane.Log in to reply