** ****Take Note

Solving Systems of Equations
1) Substitution method
2)Elimination Method
3) Graphing Method
** ****Take Note

Substitution Method Steps: a. Solve for x an y of one equation b. Substitute the answer of step a to the other equation and solve further for the other variable c. Substitute the answer of step b to the equation used in step a

Examples: Given: 2x+y=-3 2x-y=-5 a. to find the y, we should first isolate it. To do that, we will transpose any variable with it which 2x. (I chose the first equation to solve.) This would be the equation after transposing it: y=-2x-3 Which is the end of step a.

b. we will substitute the equation of y to the second equation which is from 2x-y=-5 to 2x-(-2x-3)=-5. Distribute the y to the equation...Negative multiplied to another negative? Positive!! So from 2x-(-2x-3)=-5, simplify, is equal to 2x+2x+3=-5. Simply it again to 4x+3=-5. Now, we isolate the x. Transpose 3 to the other side 4x=-5-3 to 4x=-8. Divide both sides by 4 (since the variable x has a constant of 4, in order to remove the 4, we divide it to both sides ;) ) Now its now x=-2 :D Which is the end of step b

c. So now we replace the x in the y's equation which is y=-2x-3 To y=-2(-2)-3. Simplify, y=4-3 to y=1. End of the last step, step c. :D

Final answers are: x=-2 y=1

To check if its correct, just replace both final answers to ANY equation. So, using the first equation, 2x+y=-3 Substitute, 2(-2)+1=3 -4+1+3 3=3

Easy Peasy right? Hahahaha hope this helps! :D

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