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# Target IIT-JEE (Chat Room)

Since we have to compete in jee in an all India level , it is quite obvious that we want the views of others , we want to know about our competitors.

So I have created this as a Communication platform for all those preparing for IIT - JEE.

• You can talk to the ones personally by mentioning their link. And giving them the time when you will be online .

• you can ask general questions.

• you can keep your communication personal by deleting it after your work is over.

• Anyone can join this chat room and can even invite his friends . For joining just save this note with you (optional).

• You can even ask your doubts. In any chapter(Restriction :you cannot discuss solution to Brilliant questions here , but you can share the link and ask them to come there )

• I see ,we don't always get a reply to our question , but if we all be at a single chat room we would definitely get a reply

Since this one is becoming bulkier , here is the continuation Click here

Note by Aniket Sanghi
1 year, 7 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

## Comments

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Doubt:

Please give a hint.

A uniform rid of length L lies on a smooth horizontal table.A particle moving on the table strikes the rod perpendicularly at one end and stops. Find the distance travelled by the center of rod by the time it turns through a right angle.

- 1 year, 7 months ago

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Use the following equations to find $$\omega$$:

1. Conservation of linear momentum

2. Conservation of angular momentum (about a point just above the COM of the rod, in the air, so that the point taken is stationary wrt ground and there is no angular impulse)

Then use $$\theta = \omega t$$ to get the time taken by it to rotate through $$\theta$$

And finally, $$S = v t$$, where $$v$$ is the velocity of the COM of the rod after collision, to find the distance travelled

- 1 year, 7 months ago

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Ohk got it!

Thanks a ton.

- 1 year, 7 months ago

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RM is tough right? :( I hardly solve few fully independently.

- 1 year, 7 months ago

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Same here :(

Noatter how hard I try, I can't do physics independently without any aid.

- 1 year, 7 months ago

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No problem. Glad to help.

- 1 year, 7 months ago

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What is the exam pattern of JEE 2017?

- 1 year, 7 months ago

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you never know jee pattern even 1 day before JEE exam (adv. obviously!)

- 1 year, 7 months ago

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Yes you are right. No one expected last year's pattern.

- 1 year, 7 months ago

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What is the exam pattern of JEE 2020? :P

- 1 year, 7 months ago

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What is the exam pattern of JEE 2018?

- 1 year, 7 months ago

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General question:

We all are usually confused whether the book we are referring is nice or not.........especially in the critical month before jee advanced.........let's here share the books we prefer along with a reason why we prefer it

- 1 year, 7 months ago

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Maths - cengage (lot of q to practice along with solutions)

Physics - cengage (lot of q to practice along with their solutions, nice theory )

Chemistry-

Physical- P bahadur (Everything in few pages)

Inorganic - NCERT ( Best explanation)

Organic - Cengage ( Authentic theory)

- 1 year, 7 months ago

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Physics- HC Verma (Most Authentic Theory and No errors at all and best theoretical Problems are framed from It Only) DC Pandey (Practice Nice questions with solutions)

Chemistry- RC Mukherjee (Physical- Has Almost all the variety of problems and important concepts)

Solomon's And fryhle (Organic- Detailed Explanantion and nice subjective problems)

Inorganic- its none of my buisness ! :P (but still i like ncert)

Maths- I dont get time to solve problems of maths from books (my coaching sheets, packages and archive are more than enough i think)

But still i refer to TMH For algebra for some mind bending problems and arihant for calculus for good explanation of concepts

- 1 year, 7 months ago

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@Prakhar Bindal what is the color of the cover page of soloman and fryle

- 1 year, 7 months ago

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Green

This book

http://www.amazon.in/Solomons-Fryhles-Organic-Chemistry-Advanced/dp/8126541814?tag=googinhydr18418-21

- 1 year, 7 months ago

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What about the red one?

- 1 year, 7 months ago

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My teacher Suggested to use this as original solomon's has some portion out of JEE Syllabus. Also he gave us a option between Solomon and Morrison And Boyd. My friends are using Morrison and they are finding that useful. I Also saw the book and seemed nice. Also Similar to solomon morrison has a lot of portion not in our syllabus so our teacher recommended to use solomon only but if not available then he said to go for morrison and boyd

http://www.flipkart.com/organic-chemistry-english-7th/p/itmdmyjz99fnszs6 ]\

- 1 year, 7 months ago

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What is your position in your class and what is your confidence level in organic

- 1 year, 7 months ago

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@Prakhar Bindal I have found a mistake in HC Verma.

- 1 year, 7 months ago

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Can you tell where? ( My Sir told that HC Verma Is 99.9% Authentic)

- 1 year, 7 months ago

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One is in the capacitor chapter .The other is in the SHM chapter,the question where two wheels are rotating and a rod is placed on it,the direction of rotation is given wrong (this question was copied wrongly from irodov.)

- 1 year, 7 months ago

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can you tell, which one in capacitor is wrong, i agree with the second one , i solved it from irodov.

- 1 year, 2 months ago

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@Prakhar Bindal Bhaiya, What about theory of Physical Chemistry? RC Mukherjee has little theory, will it be sufficient with my coaching packages and NCERT?

- 1 year, 7 months ago

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Well I Never needed any book for theory in physical. NCERT Is nice. If you want some more theory then i would Suggest to go for OP Tandon Or P Bahadur (OP Tandon's physical is nice DONT Ever buy its organic book it would make your head go round!! )

- 1 year, 7 months ago

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P bahadur would be nice for theory

- 1 year, 7 months ago

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same here but I prefer Ms Chauhan for organic

- 1 year, 7 months ago

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Physics- HC Verma , i.e irodov (sometimes) ,arithant publication by d.b. singh (head of science centre kota) vidyamandir modules, past 37 year iit jee questions, NCERT chemistry- i'm very poor at it, i don't really care but sometimes read my modules. NCERT maths- vidyamandir modules, past 37 year papers , TMH ,NCERT higher algebra (hall and knight) i'm not that much of a studious kid :)

- 1 year, 2 months ago

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I would say,

Maths-Cengage(JEE type questions)

Physics-Resnick Halliday,Feynman(awesome concepts),HC Verma(conceptual questions),DC Pandey(JEE type),Irodov,Krotov(for high thinking)

Physical Chemistry-P Bahadur(many problems)

Inorganic Chemistry-JD Lee(concepts),OP Tandon(mostly for facts)

Organic Chemistry-Solomons(concept),Himanshu Pandey(many JEE type questions)

To be honest, for physics, every book copies from Irodov,Krotov,Resnick Halliday(including HC Verma,DC Pandey) so I would suggest to solve many questions from these books even if they are difficult.

- 1 year, 7 months ago

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@Aniket Sanghi @Prakhar Bindal Thank you both :D

- 1 year, 7 months ago

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Doubt : Please suggest some method to proceed-

First excitation potential of a hydrogen like species is 15eV. How can i possibly calculate energy if im given potential?Can someone let me know how to calculate energy of second orbit using this data ?

- 4 months, 3 weeks ago

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I guess you know that energy of the n(th) Bohr orbit Is given by,$$E=-13.6(z/n)^2 eV=E(1)/n^2$$.Where $$E(1)$$ is the energy of the ground state.Hence $$E(2)=E(1)/4$$.and Thus $$E(2)-E(1)=15$$.Hence $$E(2)=-5eV$$

- 4 months, 3 weeks ago

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I know that already and you cant take z=1 as its not specified.Secondly,i have to convert potential to energy.Tell me how that is done.Dont just post answers for the sake of it.

- 4 months, 3 weeks ago

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Comment deleted 4 months ago

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bro, talking about manners , sad to say , you're making yourself look bad .

- 4 months, 3 weeks ago

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I am extremely sorry.I took your message as a command rather than a humble request......So sorry.

- 4 months, 3 weeks ago

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Doubt: A small object is at rest on the edge of a horizontal table. it is pushed in such a way that it falls off the other side of the table, which is 1 m wide, after 2 s. Does the object have wheels?

- 8 months, 1 week ago

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Average speed = total distance/total time. Therefore the average speed of the object is 1m/2s = 0.5 ms-1. We assume that the frictional force is constant such that the object decelerates uniformly, so we can say that 'average v = 1/2(initial v + final v)' From here, we can see that the initial speed cannot be greater than 1 ms-1, because 'final v' is more than or equal to 0 ms-1.

'Acceleration = (final v - initial v)/t', thus the magnitude of the object's acceleration is at most 0.5 ms-2. Frictional force = uN = umg, so frictional acceleration = F/m = ug, which is at most 0.5 ms-2 in this case. This means that 'u' cannot be greater 0.5/9.81 = 0.05. This is much smaller than the coefficients of friction between ordinary materials, and therefore it is very likely that the object does not slide, but that it has wheels and rolls. [adapted answer from source]

I also came across this question once this was the solution I found

- 8 months, 1 week ago

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A good mechanics problem :

A weightless rod of length $$l$$ with a small load of mass m at the end is hinged at point as shown in the figure and occupies a strictly vertical position, touching a body of mass M. A light jerk sets the system in motion. For what mass ratio M/m will the rod form an angle $$x = 30 ^{\circ}$$ with the horizontal at the moment of the separation from the body?What will be the velocity u of the body at this moment? Friction should be neglected.

Please help me with this problem.

- 1 year, 1 month ago

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M/m = 4 v = (1/2)(gl/2)^0.5

- 1 year, 1 month ago

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why don't u come over slack ?

- 1 year, 1 month ago

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Comment deleted Sep 27, 2016

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Oh thanks for your solution!

Sry I didn't knew that this prob was already posted on b'llant.

- 1 year, 1 month ago

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can u give link to prob plz

- 1 year, 1 month ago

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I can't do that ! As that would be cheating ;)

- 1 year, 1 month ago

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just the link?

- 1 year, 1 month ago

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1st tell me , why do u want that?

- 1 year, 1 month ago

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to solve it myself

- 1 year, 1 month ago

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Salute to the person who got the idea to Cretate this chat room . please can anyone tell the person who created this chat room . a wonderful idea . thank-you this chat room helped me a lot

- 1 year, 7 months ago

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Thanks! I hope it will be helpful to all :)

- 1 year, 7 months ago

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I want to clear a doubt in this question

please read my comment and tell where i am going wrong.

Thanks.

- 1 year, 7 months ago

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Is there any PDF or eBook which can help me improve my Coordinate Geometry for JEE Advanced? Since it's right around the corner and is generally where I lose marks in Maths, I'm wondering if there is any such resource or even a good question bank or something of the sort which can help me make it my strong point (most people say it's the easiest part of Maths).

- 1 year, 7 months ago

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Hey guys ....Get short notes / formula cheat sheets / previous years advance QUESTIONS / and much more exciting at jeetayyari.blogspot.com

- 3 months, 4 weeks ago

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Doubt- a container of larger uniform cross sectional area A is resting on a horizontal surface,holds two immiscible liquids of densities d and 2d,each of height H/2.A homogeneous cylinder of length L(L<H/2), cross sectional area A/5 is immersed such that it floats with its axis vertical at liquid-liquid interface with length L/4 in the denser liquid.determine density D of the solid.(answer is in terms of d)

- 8 months, 4 weeks ago

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Just write equation for static equilibrium is total weight is equal to buoyant forces by the two liquids .

- 8 months, 4 weeks ago

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I guess i am getting wrong equation.what will be correct equation

- 8 months, 4 weeks ago

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mg = V1(d)(3l/4)+ V2(2d)(l/4)

Where v1 and v2 are volumes immersed inside the liquid.

- 8 months, 4 weeks ago

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Are you sure ? Check out the dimensions to get your mistake! : )

- 8 months, 4 weeks ago

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Lol yeah I was sleepy so wrote wrong,instead of (3l/4) and (l/4) , g shud come :P

- 8 months, 4 weeks ago

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I understand :P

- 8 months, 3 weeks ago

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I think the correct equation should be like ADL/5=d(3AL/20+2AL/20)

- 8 months, 4 weeks ago

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Thank you Bhaiya

- 8 months, 4 weeks ago

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@aniket Sanghi - How to prepare for RMO.which books to refer?would I need any extra tuition also except fiitjee

- 9 months, 2 weeks ago

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If you u dont mind I can help you although this question was not meant for me.basically your mathematical insight should be good enough.the q in rmo need only a little of creative thinking,and sometimes smartness.but a rigorous idea and practice is needed for the subsequent stages.you can referefer to-1)challenge and thrill of pre college maths.2)excursion in mathematics.3)problem solving strategies-Arthur Engel.4)mathematical circles or coxeter for geometry.I do know some more as I was involved in olympiad maths but that's of inmo level.you don't need all but doing some suffices.also love maths and have a quest of problem solving.thanx.

- 9 months, 2 weeks ago

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Thanks spandan where do you live

- 9 months, 2 weeks ago

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Bhubaneswar.

- 9 months, 2 weeks ago

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I was not knowing about RMO so never gave it.... i cant help i guess .... also you can question or answer me by just clicking the reply button in any of my comment , that will automatically send me the message , to reply click on the lower white of the comment , there you will find that a hidden reply button suddenly appear...click it..

- 9 months, 2 weeks ago

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What is a slack which you all talk about

- 9 months, 2 weeks ago

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Its like a social media but of your choice . There you have to make a team or get added to one through invitation in email. You can add members to team through there emails. Thats it ... Its not like other social sites where the max world is with you...here you can have only the ones who are in your team.

- 9 months, 2 weeks ago

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it is a site just like fb to chat , you can talk to girls( if u can find them :P) and have a settlement :)

- 9 months, 2 weeks ago

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@shubham dhull- Which class you are in

- 9 months, 2 weeks ago

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@Aniket Sanghi- Thanks Bhaiya for your suggestions.Will you suggest me something about how to do well in Fiitjee tests too

- 9 months, 2 weeks ago

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Always Welcome! :)

Study for yourself .... The thing is you should know how to solve questionso not just scoring ... Automatically you will see your Rank increasing . Try to use max time possible in lower classes so that you relief yourself a bit for higher classes.

- 9 months, 2 weeks ago

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How relief myself in higher classes should I read any books if yes then which

- 9 months, 1 week ago

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First read NCERT of class 11th . For PHY in 9th and 10th , link it with 11th and 12th and learn. For maths you can start learning differenciation and integration if you want . They will support you in PHY.

These were my suggestions , you should follow the ones those are compatible.

- 9 months, 1 week ago

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Will you suggest me something to do well in JEE pl. ? i'm just expecting 150 in mains :(

- 9 months, 2 weeks ago

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Make your base strong ... work on the chapters where you pillars are not erect ... erect them first , then move on to perfection .

- 9 months, 2 weeks ago

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just a last time bothering you , i hear everybody say me " make base strong " , how to do that , nobody told me that , pl. tell something bro :) , i will believe anything you tell me pl. :) and can i doo it now ?

- 9 months, 2 weeks ago

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Like I give my example to explain - I was not quite strong in heat conduction and Radiation , so I started it from Cengage a few days back and completed from it and then from brilliant until I got satisfaction that it is done! ... In one line - " Work Until Satisfaction ".

Yeah you can! ... At least you can improve many chapters which will increase your rank a lot!

- 9 months, 2 weeks ago

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thank you bro

- 9 months, 2 weeks ago

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give some advice to me too :) for ntse

- 9 months, 2 weeks ago

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to kyon NTSE ke advice mang rha hai?

- 9 months, 2 weeks ago

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because i wanna clr it too :)

- 9 months, 2 weeks ago

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10th class mein de sakte hai ntse naki 12th

- 9 months, 2 weeks ago

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i thought i could give it now too :( can't i give it now seriously ? please tell bhai :\

- 9 months, 2 weeks ago

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Nope . maine 2 saal pehele clear kra tha !

- 9 months, 2 weeks ago

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you r great of-course ,is there any exam which i can give now ? by the way is there a age limit or something like that for NTSE ?

- 9 months, 2 weeks ago

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ha ha i am not great . .....

Yes there is class limit in NTSE ..

- 9 months, 2 weeks ago

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is there any exam which i can give now ?

- 9 months, 2 weeks ago

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such as NTSE or kvpy , i didn't give them , please tell :\

- 9 months, 2 weeks ago

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Now , nothing left except entrance exams.....(I guess)

- 9 months, 2 weeks ago

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too bad for me :( , thx for telling :) is my age over for KVPY too ?

- 9 months, 2 weeks ago

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I guess , not yet , you can give it next year too I guess .... ( I was talking about this year that everything over)

- 9 months, 2 weeks ago

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@Aniket Sanghi- I go to Fiitjee as well are the study packages and compendiums sufficient for Bio too or I need any other book

- 9 months, 2 weeks ago

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I guess compendium are more than enough

- 9 months, 2 weeks ago

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I live in Bhilai and I study at DPS Bhilai

- 9 months, 2 weeks ago

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I am in class 9 now and will appear NTSE in 2017-18. Will somebody help me by giving me tips.

- 9 months, 2 weeks ago

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For SST go with NCERT , work hard for MAT (you can use Reasoning book) , and go with your coaching materials for PCM

- 9 months, 2 weeks ago

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If i advice someone for NTSE or kvpy i feel that yeah i have done something in life :P :P .

- 9 months, 2 weeks ago

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give some advice to me too :) for ntse

- 9 months, 2 weeks ago

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Yeah! :)

- 9 months, 2 weeks ago

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me too , i'm gonn34130.092018967002103929669877572 give it too , i w34130.092018967002103929669877572nt some tips too

- 9 months, 2 weeks ago

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So, nobody is gonna add me , OK, fine by me !

- 1 year ago

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How do I increase my problem solving speed?

- 1 year ago

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Comment deleted 9 months ago

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Kudos!

- 1 year ago

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Thanx motivation baba !

- 1 year ago

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Give me your email ID

- 1 year ago

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Comment deleted Nov 07, 2016

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It's showing me , that sending invites failed for this email id and in the bottom written email id, I sent the invite Which one is right email?

- 1 year ago

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Comment deleted Nov 07, 2016

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@Swapnil Das , you add him . I am not able to send him the invite

- 1 year ago

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I'm on tab, can't send now.

- 1 year ago

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man..... then when ??

- 1 year ago

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10 days.

- 1 year ago

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what the heck ?? ca't you do something about it??

- 1 year ago

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@Swapnil Das you there ?? plz reply i'll have to go now !

- 1 year ago

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Comment deleted Nov 08, 2016

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there is a guy whose name is i form of a email id anytime i write my id his name spoils it all ! ( he gets marked !! )

- 1 year ago

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To me it is showing , sending invites failed !

- 1 year ago

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@Aniket Sanghi @shubham dhull @Prakhar Bindal Can i also join your chat room?

If yes, then please tell me how?

- 1 year ago

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i have deleted my account there as i thought i am not doing justice to myself, watching po** every time and the spending time, chatting with people, whenever i was not doing that "thing mentioned above" . i feel pity when i think where i have fallen from a state science Olympiad topper to my current state . sorry for saying it here but i think you r my friends and i can let all my feeling with you ! :(

- 1 year ago

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It is not too late, you can mend yourself, i have seen many people mending their ways and being back on track.May God be with you !

- 1 year ago

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thnx bro...... word like these give me some motivation (eve though i think the ditch in which i have fallen is too deep to come out of :(

- 1 year ago

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Be with good,motivated company.Change yourself now!Or else regret rest of your life!

Consult your parents if needed.See you can come out of the dictch, since if you could not come out, then you might have not regretted.

But you are regretting and that's a positive sign and it means that you can recover back to your normal studies! :)

You just need to be in discipline for 1 week and then you will automatically be normal.

Its is never too late.

Be engaged in fruitful activities all day.

Thanks for reading this LONG post :P

Cheers!!

(I may sound an old teacher but i like to spread motivation, my freinds call me motivator baba :P)

- 1 year ago

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Comment deleted Nov 07, 2016

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That's your problem, you need to be strict on yourself.

- 1 year ago

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Tujhe maine kitni baar kaha hai ek test tera fait decide nahi kar sakta!

- 1 year ago

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Hey Prakhar bhaiya, any last moment advice for KVPY?

Please give some tips on how to solve paper?

Thanks!

- 1 year ago

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It gives you a feeling of proudness when someone seeks an advice for you (yes i have done something) :P.

For your question i would rather say solving chemistry and bio first (they wont consume more than 30 minutes). the two markers are also theoretical . either you know or you dont. its not a good idea to spend time on thinking biology questions if you dont know the solution.

Then i would say move to physics or maths (personal choice) . i did physics coz i knew that i was strong at maths and it will take my rank up .

I Finished physics in about 45 minutes (including 2 markers). i was left with 1 hour 45 minutes of which i devoted 1 hour 30 minutes to maths thinking twice checking each step . it was also fruitful i got a perfect score 25/25 in maths

Then in remaining 15 minutes i had a good look at the whole paper (made some intelligent guesses and 2-3 i did by tukabazi)

All the best! :)

- 1 year ago

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Thanks.

- 1 year ago

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i expect that you might have seen last year's paper. i honestly finished maths in 40 minutes (it was quite easy). just i checked my steps to avoid any silly errors!.

- 1 year ago

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Plz add me too 😅

- 1 year ago

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I'll add you tmmrw k?

- 1 year ago

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Anytime before JEE 2018 (LOL)

- 1 year ago

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where ?

- 1 year ago

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Slack iitjee channel

- 1 year ago

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Comment deleted Nov 08, 2016

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Ye koi puchne wali baat nhi hai

- 1 year ago

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arrre bata yaar add kar raha hai ya nahi ???

- 1 year ago

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Comment deleted Nov 07, 2016

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Check your Inbox

- 1 year ago

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got nothing !

- 1 year ago

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Ohk . i am also not there can you add me too?

- 1 year ago

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kk

- 1 year ago

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My email is

prakhar.bindal@ymail.com

- 1 year ago

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No i'll not add u :P

- 1 year ago

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.... Says the motivation baba ;P

- 1 year ago

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Which chat room are you talking about , the one I mentioned above?

- 1 year ago

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Yes, when i click on join it says account disabled.

- 1 year ago

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Give me your email

- 1 year ago

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harshus99@gmail.com

- 1 year ago

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Check your email

- 1 year ago

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Thanks.

- 1 year ago

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I am just plain regular math lover. Not much....😅 I am not preparing for the JEE, but would love to be the part of the discussion. ( I am an army cadet! )😁

- 1 year ago

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Hi.😇

- 1 year ago

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Welcome ( Late response I know ! :P)

- 1 year ago

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i want to invite the most intelligent person here but i hope he comes(he is not much active here!) : @Rajbir Malik

- 1 year, 1 month ago

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Comment deleted Oct 21, 2016

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Who is he?

- 1 year, 1 month ago

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the most intelligent person present here in our age group !

- 1 year, 1 month ago

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Who is he?? an olympiad medalist?

- 1 year, 1 month ago

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nope

- 1 year, 1 month ago

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- 1 year, 1 month ago

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- 1 year, 1 month ago

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How many of you give full tests of Fiitjee?

Particularly of 25th april 2016

- 1 year, 6 months ago

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mention some names to make them aware

- 1 year, 6 months ago

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I don't know who all do.

Leave it

- 1 year, 6 months ago

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Which Resnick Halliday is better? The one written exclusively for jee advanced or one which is not?

- 1 year, 7 months ago

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Best is Resnick Halliday Crane ( I will not suggest Walker neither do I criticise it).

- 1 year, 7 months ago

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Go for the original one. That'll help you for NSEP+JEE.

- 1 year, 7 months ago

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https://www.flipkart.com/physics-volume-i-5th-english/p/itmdytmvygedvpch?pid=9788126510887&lid=LSTBOK9788126510887QNNK0T

Is this good?

- 1 year, 7 months ago

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I have Resnik Walker Hallinday. This is different. I have an old book. So I don't know about the new one.

- 1 year, 7 months ago

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OK so do you find it useful?

If you have few mins to spare, can you please give me a review about your book? Thanks!

- 1 year, 7 months ago

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Yes it was useful only for theory. Good for clearing concepts.

- 1 year, 7 months ago

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Ohk thanks! Clearing of concepts is what I need!

- 1 year, 7 months ago

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I see that many students find themselves weak in chemistry , so, let's practice chemistry

A person who will answer the question correctly with its solution will have the right to post the next question, followed by another.and sequence would go on ............

- 1 year, 7 months ago

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1 st question : how many radial nodes are present in the orbital represented as : n = 5 , l = 2 , m = 0.

- 1 year, 7 months ago

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number of radial nodes = n-l-1 = 2.

Number of angular nodes = l = 2

Total Nodes (Excluding the one at infinity) = 4

Total Nodes (Including Infinity one) = n = 5

- 1 year, 7 months ago

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dz2 has no nodal planes it has two nodal conical surface..

- 1 year, 7 months ago

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Can You Please elaborate? and can you tell from where can i learn these things about nodal planes,nodes etc?

- 1 year, 7 months ago

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i learnt it from J.D.Lee(inorganic chem book)(i have the orange one but if you have black you can post hundreds of question which would have 0 solvers but its not for jee orange one is) but for now you may look "https://www.physicsforums.com/threads/classifying-electron-orbitals-by-nodes.621771/".

- 1 year, 7 months ago

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So should I prefer orange or the black one for jee or is their any other (JD lee) please can you share the

- 1 year, 7 months ago

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I've black

- 1 year, 7 months ago

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Is that better than orange one? What's your analysis

- 1 year, 7 months ago

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never ceen the orange

- 1 year, 7 months ago

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if you love doing chemistry and really enjoy the inorganic part go for black i also wanted to have it but i didn't knew at that time. But it has some topics which jee does not test.

- 1 year, 7 months ago

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I want to be confined with jee syllabus and don't want to miss anything , then which one to prefer

- 1 year, 7 months ago

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orange one :)

- 1 year, 7 months ago

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And what's your expected score in jee main

- 1 year, 7 months ago

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i am in 12 now and will appear for jee in 2017.

- 1 year, 7 months ago

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I too have orange one :) For JEE

- 1 year, 7 months ago

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Is the black one better or the orange one?

And were you knowing aryan goyat is of our age (I thought he is 1 year ahead)

- 1 year, 7 months ago

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it's the very basic of nodes , you can find it in the great " NCERT " textbook if you see it my bro.

- 1 year, 2 months ago

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Right! Can you elaborate about nodal conical suface (I would like to know)

- 1 year, 7 months ago

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i hope you know the shape of 5dz2 orbital just make 2 cones such that it does not touch the electron density. you may google for the pics.

- 1 year, 7 months ago

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Wrong answer!

- 1 year, 7 months ago

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But why?

- 1 year, 7 months ago

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I think you didn't try my set !

- 1 year, 7 months ago

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you have asked here radial nodes which is n-l-1 may it be 5z2.

- 1 year, 7 months ago

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What 5z2

- 1 year, 7 months ago

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its 5dz2 .

- 1 year, 7 months ago

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It is definetely 5dz2 as m =0 is for dz2

- 1 year, 7 months ago

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A common doubt : How to prepare inorganic chemistry and from where

- 1 year, 7 months ago

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What is adv.

- 1 year, 7 months ago

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What are you asking?? Be clear

- 1 year, 7 months ago

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I have 2 doubts. Firstly, in this Physics question question, the answer comes out as $$R^2 \sqrt{\frac{2 P \cdot g}{3T}}$$, right? Secondly, in this Maths question, is there any better way of solving it other than taking partial derivatives, solving the simultaneous equations in $$x,y$$ and plugging them in to get the answer?

- 1 year, 7 months ago

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For the first one,the answer comes out as $$\displaystyle {R}^{2}\sqrt{\frac{Pg}{3T}}$$ because, it is a bubble and as there are two layers, while solving we have to take $$2*2\pi*R$$.

- 1 year, 7 months ago

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Is reading NCERT for inorganic enough?

- 1 year, 7 months ago

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JD LEE + NCERT + Your institute's notes + Previous years papers = total JEE advanced inorganic chemistry

- 1 year, 7 months ago

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Thanks I was doing JD LEE now. I was not sure whether that level would come. Now I shall read it more seriously.

- 1 year, 7 months ago

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i dont think so

- 1 year, 7 months ago

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We are told that's enough for rest our fiitjee materials fill the vacant spaces

- 1 year, 7 months ago

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Nice

- 1 year, 7 months ago

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Comment deleted Apr 19, 2016

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Comment deleted Apr 19, 2016

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It would be called cheating if we post a solution to a brilliant problem here, moderators would delete it

- 1 year, 7 months ago

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Sorry Sir

- 1 year, 7 months ago

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Yes you are right. @Gauri shankar Mishra discuss the solution there itself. If you want you can tag someone you want. Please don't discuss solutions of brilliant problems here or else I shall delete them.

- 1 year, 7 months ago

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Sorry Sir

- 1 year, 7 months ago

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How is your study going?

- 1 year, 7 months ago

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- 1 year, 7 months ago

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Invitation to @Prakhar Bindal @Gauri shankar Mishra @Aditya Kumar @aryan goyat @Mayank Singh and all who are interested are welcomed

- 1 year, 7 months ago

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Thats a nice Initiative

- 1 year, 7 months ago

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Great work

- 1 year, 7 months ago

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@Adarsh Kumar @Kalash Verma @Nihar Mahajan

- 1 year, 7 months ago

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@Calvin Lin @Andrew Ellinor @Ronak Agarwal @Nishant Rai @Sandeep Bhardwaj @ Deepanshu Gupta @David Mattingly

You all are experts and our seniors, We need and expect help from you .............

- 1 year, 7 months ago

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Sure. Always happy to help :)

- 1 year, 7 months ago

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- 1 year, 7 months ago

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Aspirants who are preparing for IIT JEE, must know about the latest information about JEE Advanced. As per the latest information JEE Advanced 2018 Exam date has been announced. The exam will be conducted on 20 May 2018. Candidates have to boost their preparation level to get good score in exam. Get more information about JEE Advanced from here - https://www.eduncle.com/jee-advanced-exam

- 1 month, 1 week ago

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@Harsh Shrivastava . I Think we can talk here

- 1 year, 1 month ago

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Very bad,126 :(

Wbu, top 50s?

- 1 year, 1 month ago

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I Got 15 in ai^2ts 1 . but it does not matter . look at your mistakes and try to improve in next

- 1 year, 1 month ago

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Of class 11

- 1 year, 1 month ago

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Thanks for encouragement.

Our next aiits is on 17th and RMO is on 16th, also cm test on 11th and kvpy on 6th novemeber, many exams ahead :p

- 1 year, 1 month ago

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Ohh go ahead. KVPY Isn't a big deal but bio can trouble you a lot (i remember scoring about 7 marks out of 25 in aptitude test which was primarily responsible for not so good rank in KVPY)

- 1 year, 1 month ago

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Thanks.

- 1 year, 1 month ago

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A spring of mass m is pulled such that a given instant, velocity of both of its end is v in the opposite direction. Find the kinetic energy of the spring.

@Aniket Sanghi @Prakhar Bindal

- 1 year, 2 months ago

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I will suggest you to join slack , there you will find many people online every time who will feel it their pleasure to clear yr doubts.

Its link is mentioned in this discussion start.

- 1 year, 2 months ago

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i joined it but nothing happens at all .

- 1 year, 2 months ago

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Thanks a ton guyz!

I hope I don't disturb you when I ask my doubts?

- 1 year, 2 months ago

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Nahh its my free time. i am watching Taarak Mehta

- 1 year, 2 months ago

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if it's your free time bonus: prove the result i am using.

- 1 year, 2 months ago

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You can solve it by integration

Use the property : In spring the velocity of any element dx at a distance x from the point of non-zero velocity is proportional to x.

Now, find the kinetic energy of this element and then integrate to get net kinetic energy.

The property I told you above can easily be proved and I have proved it in one of your doubt discussion

@Harsh Shrivastava

- 1 year, 2 months ago

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is'nt my method correct?

- 1 year, 2 months ago

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You are Using one result to prove another. He wants the proof of the result you are preassuming to be true!

- 1 year, 2 months ago

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You can assume that velocities to vary linearly along the length of spring. Hence consider an element at a distance x from one of the end of the spring , write its velocity as a function of x , Write its kinetic energy as 1/2dmv^2 and integrate from 0 to l to get total kinetic energy.

I Would say to remember this result as it is quite helpful in SHM Problems Involving spring with mass. But Derivation is Important too for Proper Understanding Purposes

- 1 year, 2 months ago

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mv^2/6?

- 1 year, 2 months ago

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Hey are free for next half hour?

I have a problem that's bugging me since evening.

A physics problem.

- 1 year, 2 months ago

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Sorry but i am a bit busy these days (AIITS This monday + revision of class 11) . you can post here i will do as soon as i get some more time

- 1 year, 2 months ago

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No prob :)

- 1 year, 2 months ago

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i can help if you want !

- 1 year, 2 months ago

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Sure!Thanks!

I'll post the prob after 30 mins, havta go out.

- 1 year, 2 months ago

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i think i have waited much than you said

- 1 year, 2 months ago

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Sorry bro, net was down.

- 1 year, 1 month ago

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ok i'll be waiting uptill then

- 1 year, 2 months ago

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Correct! Please give a hint.

- 1 year, 2 months ago

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yes me too mv^2/6 as you must be knowing the contribution of a spring in any energy is m/3. and if we break it in 2 parts , you can do it now hope it helps.

- 1 year, 2 months ago

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Why is the contribution m/3?

- 1 year, 2 months ago

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because of its twists and turns, the linear contribution of mass is only m/3 , you can google if there is any proof but it would be great if you try to remember it . hope it helps !

- 1 year, 2 months ago

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Can someone please post a solution to this problem . please!!!!

- 1 year, 6 months ago

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try this https://brilliant.org/problems/no-story-this-time/?ref_id=1178336

- 1 year, 6 months ago

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Again let it get some rating :P

- 1 year, 6 months ago

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without rating , dont we get the credit

- 1 year, 6 months ago

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u get 100 points

- 1 year, 6 months ago

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ok ok

- 1 year, 6 months ago

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Hey please can anyone help me with this

The number of normals to the curve 3y^3 = 4x which passes through (0,1) is

Answer Given = 1

My Approach found at slope of normal at any point , wrote its equation and passed through (0,1) . i obtained a 5 degree equation!

Also i entered that equation into wolfram alpha which showed me that only 1 real root exists. How?

- 1 year, 6 months ago

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Hey guys me and aniket had a discussion about this problem . We actually arrived at the answer but the only thing that is left is that we have assumed that atleast one normal will exist in the interval x>0 and y>0 . can we prove that the atleast normal has to exist in this interval? cant it be like no normal can be drawn to the curve

- 1 year, 6 months ago

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Its quite easy to make graph of $${ y }^{ 3 }=\frac { 4 }{ 3 } x$$ (I am sure you can do it orally!). And as the function is monotonic, you can easily come to the answer (try once).

- 1 year, 6 months ago

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Bhaiya i did not got the answer by your method but thought of another way. The 5 degree equation that i was getting was strictly increasing for all real numbers and when x tends - infinity it also tended to -infinity and similar was for +infinity case. Hence it will cross the x axis only once as function is monotonically increasing.

But i want to know your method as it seems quite short . Can you please elaborate ( i have just started learning calculus)

Thanks!

- 1 year, 6 months ago

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Prakhar I didid it by graph , I first draw the graph of the eq. Then you can see that the graph changes its concavity at x= 0 so you can easily observe that it can have only one normal at x>0 (graph is monotonically increasing)

- 1 year, 6 months ago

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What is relation between monotonicity and normals? . why will it have only one normal for x> 0 please explain

- 1 year, 6 months ago

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Graph

Clearly y=0 (x axis) is normal at origin. Now see how normal changes as we move left or right( it would be easy to see this as function is monotonic). (As we move right, the y- intercept of normal will keep on increasing)

- 1 year, 6 months ago

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but x axis does not pass through (0,1)

- 1 year, 6 months ago

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Please can you be more detailed? i realized that function is monotonically increasing as first derivative >0

- 1 year, 6 months ago

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Those who love chemistry are invited to try these (BEST OF JEE - ADVANCED)

- 1 year, 7 months ago

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Today Rajdeep Asked me a question in which we were required to compare the acidic strength of H2SO4 , HCl AND H3PO4. I Was quite easily able to tell that H3PO4 would be the weakest acid. but was struck in comparing acidic strength of H2SO4 And HCl. i searched internet and got confused as all give a different answer. can any one please help?

- 1 year, 7 months ago

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i think the book you mentioned above ie solomons can help , checkout the table within it it is H2SO4 which is more stronger.(table 3.1 in 10th edition)

- 1 year, 7 months ago

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Comment deleted Apr 22, 2016

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mines are similar to prakhar with an exception that in physics i don,t prefer books and in inorganic i stick to J.D.Lee(the best book in inorganic)

- 1 year, 7 months ago

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I thought you were 1 year ahead! Are you in fiitjee

- 1 year, 7 months ago

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yes fiitjee jaipur.

- 1 year, 7 months ago

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What's your AIITS Rank history

- 1 year, 7 months ago

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near 50s (average)

- 1 year, 7 months ago

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Comment deleted Apr 22, 2016

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and your histroy

- 1 year, 7 months ago

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Top 20s

- 1 year, 7 months ago

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please provide me the link of it.

- 1 year, 7 months ago

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https://www.quora.com/Why-is-hydrochloric-acid-stronger-than-sulphuric-acid-even-though-sulphuric-acid-should-dissociate-to-produce-more-hydrogen-ions

- 1 year, 7 months ago

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Common strong acids This is a list of strong acids with pKa < -1.74, which is stronger than the hydronium ion, from strongest to weakest. Perchloric acid HClO4 (pKa ≈ −10)[5] Hydroiodic acid HI (pKa = −9.3)[2] Hydrobromic acid HBr (pKa = −8.7)[2] Hydrochloric acid HCl (pKa = −6.3)[2] Sulfuric acid H2SO4 (first dissociation only, pKa1 ≈ −3)[6] p-Toluenesulfonic acid (pKa = −2.8) Organic soluble strong acid Methanesulfonic acid (pKa = −1.92) Liquid organic strong acid[7] Almost strong acids from wikipedia

- 1 year, 7 months ago

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That's the problem . I Looked up Wikipedia it says HCl which even confuses me more

- 1 year, 7 months ago

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Wikipedia is not authentic ,it can be edited!

- 1 year, 7 months ago

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My Book (Cengage (Authentic) ) says H2SO4(pKa = -9) is stronger acid than HCl (pKa = -7)

Different source may give different results as you may know acidity also depends on the solvent.....Like H2SO4 and HCL will differentiate equally in H2O (high dielectric constant) , so you can't use H2O to compare acidity. Similarly may be diff sources are based on diff solvents.

- 1 year, 7 months ago

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I Also Thought H2SO4 Because it is diprotic and high resonance on conjugate base let me assume it to be true as it is the same in solomons

- 1 year, 7 months ago

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- 1 year, 7 months ago

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u there?

- 1 year, 7 months ago

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yes

- 1 year, 7 months ago

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I Mean to say for pure rolling bottom most point must be at rest wrt the surface it is performing pure rolling also the conditon a = R*Alpha should get satisfied . How can they both be simultaneously True?

- 1 year, 7 months ago

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why cannot it be see the what we mean by a=alph*R is dv/dt=R.dw/dt

dv=Rdw

adding v to both side v+dv=Rdw+v

v+dv=Rdw+wR

v(after time dt)=w(after time dt)R

- 1 year, 7 months ago

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Ok . My confusion is basically that during pure rolling we say that point of contact remains at rest hence force of friction should not act but we take in several problems like i gave you the previous one

- 1 year, 7 months ago

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then why dont you look at the object just after a time dt you find that the object is not doing pure rolling so here comes friction within a negligible time interval which even we cant measure and we would have to say that both act simultaneously.

- 1 year, 7 months ago

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Ok . In the Football Question We Have said that as pure rolling has started after first collision with rough ground so the bottom most point must have come to rest and hence it will be at rest when it again collides with rough ground. Hence there is no reason why friction must act. Cant we compare the two cases?(This football one and situation that i gave you). here also Once pure rolling started on horizontal surface the bottom point comes to rest hence there is no reason why friction should act

- 1 year, 7 months ago

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next did you find any horizontal force which is making it out of rolling in time dt.

- 1 year, 7 months ago

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in case of football field just after time t however long or small it may be the sphere will go on pure rolling, however it is not so here even after a small time dt the pure rolling is off.

- 1 year, 7 months ago

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i think i need some rest . i will talk to you tomorrow in this regard as i am feeling exhausted. thanks for taking out your precious time and having discussion in my silly concept

- 1 year, 7 months ago

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as much i know "no question is a silly question"

- 1 year, 7 months ago

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I Have Done The Following Analysis.

For Pure rolling on horizontal surface

Case.1 An external force is acting

In This case friction may or may not act. It All depends on the point of application of horizontal force.

Case 2. An External Is Not Acting

In This Case Friction Should Not act if body is continuing pure rolling. Because Friction will provide a and alpha in same direction hence a= R*Alpha can never be true.And once pure rolling started friction Friction will become zero so as the condition remains true (now a and alpha will become zero as there is no force) hence it will continue on to uniform pure rolling ( not accelerated )

External force does not includes friction

Is This analysis correct?

- 1 year, 7 months ago

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absolutely correct.

- 1 year, 7 months ago

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