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# Target IIT-JEE (Chat Room)

Since we have to compete in jee in an all India level , it is quite obvious that we want the views of others , we want to know about our competitors.

So I have created this as a Communication platform for all those preparing for IIT - JEE.

• You can talk to the ones personally by mentioning their link. And giving them the time when you will be online .

• you can ask general questions.

• you can keep your communication personal by deleting it after your work is over.

• Anyone can join this chat room and can even invite his friends . For joining just save this note with you (optional).

• You can even ask your doubts. In any chapter(Restriction :you cannot discuss solution to Brilliant questions here , but you can share the link and ask them to come there )

• I see ,we don't always get a reply to our question , but if we all be at a single chat room we would definitely get a reply

Note : This chat room is also started on slack , There we can communicate !! Give me your email ID if you want to be a part of it!

Note by Aniket Sanghi
9 months, 1 week ago

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Doubt:

A uniform rid of length L lies on a smooth horizontal table.A particle moving on the table strikes the rod perpendicularly at one end and stops. Find the distance travelled by the center of rod by the time it turns through a right angle. · 9 months, 1 week ago

Use the following equations to find $$\omega$$:

1. Conservation of linear momentum

2. Conservation of angular momentum (about a point just above the COM of the rod, in the air, so that the point taken is stationary wrt ground and there is no angular impulse)

Then use $$\theta = \omega t$$ to get the time taken by it to rotate through $$\theta$$

And finally, $$S = v t$$, where $$v$$ is the velocity of the COM of the rod after collision, to find the distance travelled · 9 months ago

Ohk got it!

Thanks a ton. · 9 months ago

RM is tough right? :( I hardly solve few fully independently. · 9 months ago

Same here :(

Noatter how hard I try, I can't do physics independently without any aid. · 9 months ago

No problem. Glad to help. · 9 months ago

What is the exam pattern of JEE 2017? · 9 months, 1 week ago

you never know jee pattern even 1 day before JEE exam (adv. obviously!) · 9 months, 1 week ago

Yes you are right. No one expected last year's pattern. · 9 months, 1 week ago

What is the exam pattern of JEE 2020? :P · 9 months, 1 week ago

What is the exam pattern of JEE 2018? · 9 months, 1 week ago

General question:

We all are usually confused whether the book we are referring is nice or not.........especially in the critical month before jee advanced.........let's here share the books we prefer along with a reason why we prefer it · 9 months, 1 week ago

Maths - cengage (lot of q to practice along with solutions)

Physics - cengage (lot of q to practice along with their solutions, nice theory )

Chemistry-

Physical- P bahadur (Everything in few pages)

Inorganic - NCERT ( Best explanation)

Organic - Cengage ( Authentic theory) · 9 months, 1 week ago

Physics- HC Verma (Most Authentic Theory and No errors at all and best theoretical Problems are framed from It Only) DC Pandey (Practice Nice questions with solutions)

Chemistry- RC Mukherjee (Physical- Has Almost all the variety of problems and important concepts)

Solomon's And fryhle (Organic- Detailed Explanantion and nice subjective problems)

Inorganic- its none of my buisness ! :P (but still i like ncert)

Maths- I dont get time to solve problems of maths from books (my coaching sheets, packages and archive are more than enough i think)

But still i refer to TMH For algebra for some mind bending problems and arihant for calculus for good explanation of concepts · 9 months, 1 week ago

@Prakhar Bindal what is the color of the cover page of soloman and fryle · 9 months ago

Green

This book

What about the red one? · 9 months ago

My teacher Suggested to use this as original solomon's has some portion out of JEE Syllabus. Also he gave us a option between Solomon and Morrison And Boyd. My friends are using Morrison and they are finding that useful. I Also saw the book and seemed nice. Also Similar to solomon morrison has a lot of portion not in our syllabus so our teacher recommended to use solomon only but if not available then he said to go for morrison and boyd

http://www.flipkart.com/organic-chemistry-english-7th/p/itmdmyjz99fnszs6 ]\ · 9 months ago

What is your position in your class and what is your confidence level in organic · 9 months ago

@Prakhar Bindal I have found a mistake in HC Verma. · 9 months ago

Can you tell where? ( My Sir told that HC Verma Is 99.9% Authentic) · 9 months ago

One is in the capacitor chapter .The other is in the SHM chapter,the question where two wheels are rotating and a rod is placed on it,the direction of rotation is given wrong (this question was copied wrongly from irodov.) · 9 months ago

can you tell, which one in capacitor is wrong, i agree with the second one , i solved it from irodov. · 4 months ago

@Prakhar Bindal Bhaiya, What about theory of Physical Chemistry? RC Mukherjee has little theory, will it be sufficient with my coaching packages and NCERT? · 9 months ago

Well I Never needed any book for theory in physical. NCERT Is nice. If you want some more theory then i would Suggest to go for OP Tandon Or P Bahadur (OP Tandon's physical is nice DONT Ever buy its organic book it would make your head go round!! ) · 9 months ago

P bahadur would be nice for theory · 9 months ago

same here but I prefer Ms Chauhan for organic · 9 months ago

Physics- HC Verma , i.e irodov (sometimes) ,arithant publication by d.b. singh (head of science centre kota) vidyamandir modules, past 37 year iit jee questions, NCERT chemistry- i'm very poor at it, i don't really care but sometimes read my modules. NCERT maths- vidyamandir modules, past 37 year papers , TMH ,NCERT higher algebra (hall and knight) i'm not that much of a studious kid :) · 4 months ago

@Aniket Sanghi @Prakhar Bindal Thank you both :D · 9 months ago

I would say,

Maths-Cengage(JEE type questions)

Physics-Resnick Halliday,Feynman(awesome concepts),HC Verma(conceptual questions),DC Pandey(JEE type),Irodov,Krotov(for high thinking)

Inorganic Chemistry-JD Lee(concepts),OP Tandon(mostly for facts)

Organic Chemistry-Solomons(concept),Himanshu Pandey(many JEE type questions)

To be honest, for physics, every book copies from Irodov,Krotov,Resnick Halliday(including HC Verma,DC Pandey) so I would suggest to solve many questions from these books even if they are difficult. · 9 months ago

How many of you give full tests of Fiitjee?

Particularly of 25th april 2016 · 9 months ago

mention some names to make them aware · 9 months ago

I don't know who all do.

Leave it · 9 months ago

Salute to the person who got the idea to Cretate this chat room . please can anyone tell the person who created this chat room . a wonderful idea . thank-you this chat room helped me a lot · 9 months ago

Thanks! I hope it will be helpful to all :) · 9 months ago

I want to clear a doubt in this question

Thanks. · 9 months ago

Is there any PDF or eBook which can help me improve my Coordinate Geometry for JEE Advanced? Since it's right around the corner and is generally where I lose marks in Maths, I'm wondering if there is any such resource or even a good question bank or something of the sort which can help me make it my strong point (most people say it's the easiest part of Maths). · 9 months ago

So, nobody is gonna add me , OK, fine by me ! · 2 months, 2 weeks ago

How do I increase my problem solving speed? · 2 months, 2 weeks ago

@Aniket Sanghi @Harsh Shrivastava @Prakhar Bindal add me to slack again plz, i miss talking to you guys and prakhar , just coz of motivational words you said to me i got 86 in chem out of 120 ad my teacher really praised me coz it was one of the highest marks anybody got there and i got 109 in physics too , my teacher said i was one of the brightest minds in the country as far as physics goes ! i am really happy and motivated ! $$\ddot smile$$ · 2 months, 2 weeks ago

Kudos! · 2 months, 2 weeks ago

Thanx motivation baba ! · 2 months, 2 weeks ago

Give me your email ID · 2 months, 2 weeks ago

Comment deleted 2 months ago

It's showing me , that sending invites failed for this email id and in the bottom written email id, I sent the invite Which one is right email? · 2 months, 2 weeks ago

Comment deleted 2 months ago

@Swapnil Das , you add him . I am not able to send him the invite · 2 months, 2 weeks ago

I'm on tab, can't send now. · 2 months, 2 weeks ago

man..... then when ?? · 2 months, 2 weeks ago

10 days. · 2 months, 2 weeks ago

what the heck ?? ca't you do something about it?? · 2 months, 2 weeks ago

@Swapnil Das you there ?? plz reply i'll have to go now ! · 2 months, 2 weeks ago

Comment deleted 2 months ago

there is a guy whose name is i form of a email id anytime i write my id his name spoils it all ! ( he gets marked !! ) · 2 months, 2 weeks ago

To me it is showing , sending invites failed ! · 2 months, 2 weeks ago

@Aniket Sanghi @shubham dhull @Prakhar Bindal Can i also join your chat room?

If yes, then please tell me how? · 2 months, 2 weeks ago

i have deleted my account there as i thought i am not doing justice to myself, watching po** every time and the spending time, chatting with people, whenever i was not doing that "thing mentioned above" . i feel pity when i think where i have fallen from a state science Olympiad topper to my current state . sorry for saying it here but i think you r my friends and i can let all my feeling with you ! :( · 2 months, 2 weeks ago

It is not too late, you can mend yourself, i have seen many people mending their ways and being back on track.May God be with you ! · 2 months, 2 weeks ago

thnx bro...... word like these give me some motivation (eve though i think the ditch in which i have fallen is too deep to come out of :( · 2 months, 2 weeks ago

Be with good,motivated company.Change yourself now!Or else regret rest of your life!

Consult your parents if needed.See you can come out of the dictch, since if you could not come out, then you might have not regretted.

But you are regretting and that's a positive sign and it means that you can recover back to your normal studies! :)

You just need to be in discipline for 1 week and then you will automatically be normal.

Its is never too late.

Be engaged in fruitful activities all day.

Thanks for reading this LONG post :P

Cheers!!

(I may sound an old teacher but i like to spread motivation, my freinds call me motivator baba :P) · 2 months, 2 weeks ago

Comment deleted 2 months ago

That's your problem, you need to be strict on yourself. · 2 months, 2 weeks ago

Tujhe maine kitni baar kaha hai ek test tera fait decide nahi kar sakta! · 2 months, 2 weeks ago

Hey Prakhar bhaiya, any last moment advice for KVPY?

Please give some tips on how to solve paper?

Thanks! · 2 months, 2 weeks ago

It gives you a feeling of proudness when someone seeks an advice for you (yes i have done something) :P.

For your question i would rather say solving chemistry and bio first (they wont consume more than 30 minutes). the two markers are also theoretical . either you know or you dont. its not a good idea to spend time on thinking biology questions if you dont know the solution.

Then i would say move to physics or maths (personal choice) . i did physics coz i knew that i was strong at maths and it will take my rank up .

I Finished physics in about 45 minutes (including 2 markers). i was left with 1 hour 45 minutes of which i devoted 1 hour 30 minutes to maths thinking twice checking each step . it was also fruitful i got a perfect score 25/25 in maths

Then in remaining 15 minutes i had a good look at the whole paper (made some intelligent guesses and 2-3 i did by tukabazi)

All the best! :) · 2 months, 2 weeks ago

Thanks. · 2 months, 2 weeks ago

i expect that you might have seen last year's paper. i honestly finished maths in 40 minutes (it was quite easy). just i checked my steps to avoid any silly errors!. · 2 months, 2 weeks ago

Plz add me too 😅 · 2 months, 2 weeks ago

I'll add you tmmrw k? · 2 months, 2 weeks ago

Anytime before JEE 2018 (LOL) · 2 months, 2 weeks ago

where ? · 2 months, 2 weeks ago

Slack iitjee channel · 2 months, 2 weeks ago

Comment deleted 2 months ago

Ye koi puchne wali baat nhi hai · 2 months, 2 weeks ago

arrre bata yaar add kar raha hai ya nahi ??? · 2 months, 2 weeks ago

Comment deleted 2 months ago

Check your Inbox · 2 months, 2 weeks ago

got nothing ! · 2 months, 2 weeks ago

Ohk . i am also not there can you add me too? · 2 months, 2 weeks ago

kk · 2 months, 2 weeks ago

My email is

prakhar.bindal@ymail.com · 2 months, 2 weeks ago

No i'll not add u :P · 2 months, 2 weeks ago

.... Says the motivation baba ;P · 2 months, 2 weeks ago

Which chat room are you talking about , the one I mentioned above? · 2 months, 2 weeks ago

Yes, when i click on join it says account disabled. · 2 months, 2 weeks ago

Give me your email · 2 months, 2 weeks ago

harshus99@gmail.com · 2 months, 2 weeks ago

Check your email · 2 months, 2 weeks ago

Thanks. · 2 months, 2 weeks ago

I am just plain regular math lover. Not much....😅 I am not preparing for the JEE, but would love to be the part of the discussion. ( I am an army cadet! )😁 · 3 months ago

Hi.😇 · 3 months ago

Welcome ( Late response I know ! :P) · 2 months, 2 weeks ago

i want to invite the most intelligent person here but i hope he comes(he is not much active here!) : @Rajbir Malik · 3 months ago

Comment deleted 3 months ago

Who is he? · 3 months ago

the most intelligent person present here in our age group ! · 3 months ago

Who is he?? an olympiad medalist? · 3 months ago

nope · 3 months ago

Comment deleted 3 months ago

Comment deleted 2 months ago

@Aniket Sanghi · 3 months, 2 weeks ago

@Aniket Sanghi · 3 months, 2 weeks ago

A good mechanics problem :

A weightless rod of length $$l$$ with a small load of mass m at the end is hinged at point as shown in the figure and occupies a strictly vertical position, touching a body of mass M. A light jerk sets the system in motion. For what mass ratio M/m will the rod form an angle $$x = 30 ^{\circ}$$ with the horizontal at the moment of the separation from the body?What will be the velocity u of the body at this moment? Friction should be neglected.

@shubham dhull @Prakhar Bindal @Aniket Sanghi · 3 months, 3 weeks ago

M/m = 4 v = (1/2)(gl/2)^0.5 · 3 months, 3 weeks ago

why don't u come over slack ? · 3 months, 3 weeks ago

Comment deleted 3 months ago

Sry I didn't knew that this prob was already posted on b'llant. · 3 months, 3 weeks ago

can u give link to prob plz · 3 months, 3 weeks ago

I can't do that ! As that would be cheating ;) · 3 months, 3 weeks ago

just the link? · 3 months, 3 weeks ago

1st tell me , why do u want that? · 3 months, 3 weeks ago

to solve it myself · 3 months, 3 weeks ago

Which Resnick Halliday is better? The one written exclusively for jee advanced or one which is not? · 9 months ago

Best is Resnick Halliday Crane ( I will not suggest Walker neither do I criticise it). · 9 months ago

Go for the original one. That'll help you for NSEP+JEE. · 9 months ago

https://www.flipkart.com/physics-volume-i-5th-english/p/itmdytmvygedvpch?pid=9788126510887&lid=LSTBOK9788126510887QNNK0T

Is this good? · 9 months ago

I have Resnik Walker Hallinday. This is different. I have an old book. So I don't know about the new one. · 9 months ago

OK so do you find it useful?

If you have few mins to spare, can you please give me a review about your book? Thanks! · 9 months ago

Yes it was useful only for theory. Good for clearing concepts. · 9 months ago

Ohk thanks! Clearing of concepts is what I need! · 9 months ago

I see that many students find themselves weak in chemistry , so, let's practice chemistry

A person who will answer the question correctly with its solution will have the right to post the next question, followed by another.and sequence would go on ............ · 9 months ago

1 st question : how many radial nodes are present in the orbital represented as : n = 5 , l = 2 , m = 0. · 9 months ago

number of radial nodes = n-l-1 = 2.

Number of angular nodes = l = 2

Total Nodes (Excluding the one at infinity) = 4

Total Nodes (Including Infinity one) = n = 5 · 9 months ago

dz2 has no nodal planes it has two nodal conical surface.. · 9 months ago

Can You Please elaborate? and can you tell from where can i learn these things about nodal planes,nodes etc? · 9 months ago

i learnt it from J.D.Lee(inorganic chem book)(i have the orange one but if you have black you can post hundreds of question which would have 0 solvers but its not for jee orange one is) but for now you may look "https://www.physicsforums.com/threads/classifying-electron-orbitals-by-nodes.621771/". · 9 months ago

So should I prefer orange or the black one for jee or is their any other (JD lee) please can you share the

@aryan goyat @Mayank Singh · 9 months ago

I've black · 9 months ago

Is that better than orange one? What's your analysis · 9 months ago

never ceen the orange · 9 months ago

if you love doing chemistry and really enjoy the inorganic part go for black i also wanted to have it but i didn't knew at that time. But it has some topics which jee does not test. · 9 months ago

I want to be confined with jee syllabus and don't want to miss anything , then which one to prefer · 9 months ago

orange one :) · 9 months ago

And what's your expected score in jee main · 9 months ago

i am in 12 now and will appear for jee in 2017. · 9 months ago

I too have orange one :) For JEE · 9 months ago

Is the black one better or the orange one?

And were you knowing aryan goyat is of our age (I thought he is 1 year ahead) · 9 months ago

it's the very basic of nodes , you can find it in the great " NCERT " textbook if you see it my bro. · 4 months ago

Right! Can you elaborate about nodal conical suface (I would like to know) · 9 months ago

i hope you know the shape of 5dz2 orbital just make 2 cones such that it does not touch the electron density. you may google for the pics. · 9 months ago

Wrong answer! · 9 months ago

But why? · 9 months ago

I think you didn't try my set ! · 9 months ago

you have asked here radial nodes which is n-l-1 may it be 5z2. · 9 months ago

What 5z2 · 9 months ago

its 5dz2 . · 9 months ago

It is definetely 5dz2 as m =0 is for dz2 · 9 months ago

A common doubt : How to prepare inorganic chemistry and from where

@Sandeep Bhardwaj · 9 months ago

What is adv. · 9 months ago

What are you asking?? Be clear · 9 months ago

I have 2 doubts. Firstly, in this Physics question question, the answer comes out as $$R^2 \sqrt{\frac{2 P \cdot g}{3T}}$$, right? Secondly, in this Maths question, is there any better way of solving it other than taking partial derivatives, solving the simultaneous equations in $$x,y$$ and plugging them in to get the answer? · 9 months ago

For the first one,the answer comes out as $$\displaystyle {R}^{2}\sqrt{\frac{Pg}{3T}}$$ because, it is a bubble and as there are two layers, while solving we have to take $$2*2\pi*R$$. · 9 months ago

Is reading NCERT for inorganic enough? · 9 months, 1 week ago

JD LEE + NCERT + Your institute's notes + Previous years papers = total JEE advanced inorganic chemistry · 9 months ago

Thanks I was doing JD LEE now. I was not sure whether that level would come. Now I shall read it more seriously. · 9 months ago

i dont think so · 9 months ago

We are told that's enough for rest our fiitjee materials fill the vacant spaces · 9 months ago

Nice · 9 months, 1 week ago

Comment deleted 9 months ago

Comment deleted 9 months ago

It would be called cheating if we post a solution to a brilliant problem here, moderators would delete it · 9 months, 1 week ago

Sorry Sir · 9 months, 1 week ago

Yes you are right. @Gauri shankar Mishra discuss the solution there itself. If you want you can tag someone you want. Please don't discuss solutions of brilliant problems here or else I shall delete them. · 9 months, 1 week ago

Sorry Sir · 9 months, 1 week ago

How is your study going? · 9 months, 1 week ago

Invitation to @Prakhar Bindal @Gauri shankar Mishra @Aditya Kumar @aryan goyat @Mayank Singh and all who are interested are welcomed · 9 months, 1 week ago

Thats a nice Initiative · 9 months, 1 week ago

Great work · 9 months, 1 week ago

@Anshul Sanghi @ANSHUL SHRIVASTAVA @Harsh Shrivastava @Ashish R. Nair @Naman jain @Hargun Singh @Jyotisman Das · 9 months, 1 week ago

@Adarsh Kumar @Kalash Verma @Nihar Mahajan · 9 months, 1 week ago

@Calvin Lin @Andrew Ellinor @Ronak Agarwal @Nishant Rai @Sandeep Bhardwaj @ Deepanshu Gupta @David Mattingly

You all are experts and our seniors, We need and expect help from you ............. · 9 months, 1 week ago

Sure. Always happy to help :) · 9 months, 1 week ago

@aryan goyat · 9 months, 1 week ago

@Harsh Shrivastava . I Think we can talk here · 3 months, 2 weeks ago

Wbu, top 50s? · 3 months, 2 weeks ago

I Got 15 in ai^2ts 1 . but it does not matter . look at your mistakes and try to improve in next · 3 months, 2 weeks ago

Of class 11 · 3 months, 2 weeks ago

Thanks for encouragement.

Our next aiits is on 17th and RMO is on 16th, also cm test on 11th and kvpy on 6th novemeber, many exams ahead :p · 3 months, 2 weeks ago

Ohh go ahead. KVPY Isn't a big deal but bio can trouble you a lot (i remember scoring about 7 marks out of 25 in aptitude test which was primarily responsible for not so good rank in KVPY) · 3 months, 2 weeks ago

Thanks. · 3 months, 2 weeks ago

A spring of mass m is pulled such that a given instant, velocity of both of its end is v in the opposite direction. Find the kinetic energy of the spring.

@Aniket Sanghi @Prakhar Bindal · 4 months ago

I will suggest you to join slack , there you will find many people online every time who will feel it their pleasure to clear yr doubts.

Its link is mentioned in this discussion start. · 4 months ago

i joined it but nothing happens at all . · 4 months ago

Thanks a ton guyz!

I hope I don't disturb you when I ask my doubts? · 4 months ago

Nahh its my free time. i am watching Taarak Mehta · 4 months ago

if it's your free time bonus: prove the result i am using. · 4 months ago

You can solve it by integration

Use the property : In spring the velocity of any element dx at a distance x from the point of non-zero velocity is proportional to x.

Now, find the kinetic energy of this element and then integrate to get net kinetic energy.

The property I told you above can easily be proved and I have proved it in one of your doubt discussion

@Harsh Shrivastava · 4 months ago

is'nt my method correct? · 4 months ago

You are Using one result to prove another. He wants the proof of the result you are preassuming to be true! · 4 months ago

You can assume that velocities to vary linearly along the length of spring. Hence consider an element at a distance x from one of the end of the spring , write its velocity as a function of x , Write its kinetic energy as 1/2dmv^2 and integrate from 0 to l to get total kinetic energy.

I Would say to remember this result as it is quite helpful in SHM Problems Involving spring with mass. But Derivation is Important too for Proper Understanding Purposes · 4 months ago

mv^2/6? · 4 months ago

Hey are free for next half hour?

I have a problem that's bugging me since evening.

A physics problem. · 4 months ago

Sorry but i am a bit busy these days (AIITS This monday + revision of class 11) . you can post here i will do as soon as i get some more time · 4 months ago

No prob :) · 4 months ago

i can help if you want ! · 4 months ago

Sure!Thanks!

I'll post the prob after 30 mins, havta go out. · 4 months ago

i think i have waited much than you said · 4 months ago

Sorry bro, net was down. · 3 months, 3 weeks ago

ok i'll be waiting uptill then · 4 months ago

Correct! Please give a hint. · 4 months ago

yes me too mv^2/6 as you must be knowing the contribution of a spring in any energy is m/3. and if we break it in 2 parts , you can do it now hope it helps. · 4 months ago

Why is the contribution m/3? · 4 months ago

because of its twists and turns, the linear contribution of mass is only m/3 , you can google if there is any proof but it would be great if you try to remember it . hope it helps ! · 4 months ago

Can someone please post a solution to this problem . please!!!! · 8 months, 2 weeks ago

try this https://brilliant.org/problems/no-story-this-time/?ref_id=1178336 · 9 months ago

Again let it get some rating :P · 9 months ago

without rating , dont we get the credit · 9 months ago

u get 100 points · 9 months ago

ok ok · 9 months ago

Hey please can anyone help me with this

The number of normals to the curve 3y^3 = 4x which passes through (0,1) is

My Approach found at slope of normal at any point , wrote its equation and passed through (0,1) . i obtained a 5 degree equation!

Also i entered that equation into wolfram alpha which showed me that only 1 real root exists. How?

@Aniket Sanghi @rohit kumar @Mayank Singh @aryan goyat @Akul Agrawal · 9 months ago

Hey guys me and aniket had a discussion about this problem . We actually arrived at the answer but the only thing that is left is that we have assumed that atleast one normal will exist in the interval x>0 and y>0 . can we prove that the atleast normal has to exist in this interval? cant it be like no normal can be drawn to the curve

@rohit kumar @Mayank Singh @aryan goyat @Akul Agrawal @Aniket Sanghi · 9 months ago

Its quite easy to make graph of $${ y }^{ 3 }=\frac { 4 }{ 3 } x$$ (I am sure you can do it orally!). And as the function is monotonic, you can easily come to the answer (try once). · 9 months ago

Bhaiya i did not got the answer by your method but thought of another way. The 5 degree equation that i was getting was strictly increasing for all real numbers and when x tends - infinity it also tended to -infinity and similar was for +infinity case. Hence it will cross the x axis only once as function is monotonically increasing.

But i want to know your method as it seems quite short . Can you please elaborate ( i have just started learning calculus)

Thanks! · 9 months ago

Prakhar I didid it by graph , I first draw the graph of the eq. Then you can see that the graph changes its concavity at x= 0 so you can easily observe that it can have only one normal at x>0 (graph is monotonically increasing) · 9 months ago

What is relation between monotonicity and normals? . why will it have only one normal for x> 0 please explain · 9 months ago

Graph

Clearly y=0 (x axis) is normal at origin. Now see how normal changes as we move left or right( it would be easy to see this as function is monotonic). (As we move right, the y- intercept of normal will keep on increasing) · 9 months ago

but x axis does not pass through (0,1) · 9 months ago

Please can you be more detailed? i realized that function is monotonically increasing as first derivative >0

@Akul Agrawal · 9 months ago

Those who love chemistry are invited to try these (BEST OF JEE - ADVANCED) · 9 months ago

Today Rajdeep Asked me a question in which we were required to compare the acidic strength of H2SO4 , HCl AND H3PO4. I Was quite easily able to tell that H3PO4 would be the weakest acid. but was struck in comparing acidic strength of H2SO4 And HCl. i searched internet and got confused as all give a different answer. can any one please help?

@aryan goyat t @Aniket Sanghi @rohit kumar @Aditya Kumar @Abhineet Nayyar · 9 months ago

i think the book you mentioned above ie solomons can help , checkout the table within it it is H2SO4 which is more stronger.(table 3.1 in 10th edition) · 9 months ago

Comment deleted 9 months ago

mines are similar to prakhar with an exception that in physics i don,t prefer books and in inorganic i stick to J.D.Lee(the best book in inorganic) · 9 months ago

I thought you were 1 year ahead! Are you in fiitjee · 9 months ago

yes fiitjee jaipur. · 9 months ago

What's your AIITS Rank history · 9 months ago

near 50s (average) · 9 months ago

Comment deleted 9 months ago

and your histroy · 9 months ago

Top 20s · 9 months ago

https://www.quora.com/Why-is-hydrochloric-acid-stronger-than-sulphuric-acid-even-though-sulphuric-acid-should-dissociate-to-produce-more-hydrogen-ions · 9 months ago

Common strong acids This is a list of strong acids with pKa < -1.74, which is stronger than the hydronium ion, from strongest to weakest. Perchloric acid HClO4 (pKa ≈ −10)[5] Hydroiodic acid HI (pKa = −9.3)[2] Hydrobromic acid HBr (pKa = −8.7)[2] Hydrochloric acid HCl (pKa = −6.3)[2] Sulfuric acid H2SO4 (first dissociation only, pKa1 ≈ −3)[6] p-Toluenesulfonic acid (pKa = −2.8) Organic soluble strong acid Methanesulfonic acid (pKa = −1.92) Liquid organic strong acid[7] Almost strong acids from wikipedia · 9 months ago

That's the problem . I Looked up Wikipedia it says HCl which even confuses me more · 9 months ago

Wikipedia is not authentic ,it can be edited! · 9 months ago

My Book (Cengage (Authentic) ) says H2SO4(pKa = -9) is stronger acid than HCl (pKa = -7)

Different source may give different results as you may know acidity also depends on the solvent.....Like H2SO4 and HCL will differentiate equally in H2O (high dielectric constant) , so you can't use H2O to compare acidity. Similarly may be diff sources are based on diff solvents. · 9 months ago

I Also Thought H2SO4 Because it is diprotic and high resonance on conjugate base let me assume it to be true as it is the same in solomons · 9 months ago

@aryan goyat · 9 months, 1 week ago

u there? · 9 months, 1 week ago

yes · 9 months, 1 week ago

I Mean to say for pure rolling bottom most point must be at rest wrt the surface it is performing pure rolling also the conditon a = R*Alpha should get satisfied . How can they both be simultaneously True? · 9 months, 1 week ago

why cannot it be see the what we mean by a=alph*R is dv/dt=R.dw/dt

dv=Rdw

adding v to both side v+dv=Rdw+v

v+dv=Rdw+wR

v(after time dt)=w(after time dt)R · 9 months, 1 week ago

Ok . My confusion is basically that during pure rolling we say that point of contact remains at rest hence force of friction should not act but we take in several problems like i gave you the previous one · 9 months, 1 week ago

then why dont you look at the object just after a time dt you find that the object is not doing pure rolling so here comes friction within a negligible time interval which even we cant measure and we would have to say that both act simultaneously. · 9 months, 1 week ago

Ok . In the Football Question We Have said that as pure rolling has started after first collision with rough ground so the bottom most point must have come to rest and hence it will be at rest when it again collides with rough ground. Hence there is no reason why friction must act. Cant we compare the two cases?(This football one and situation that i gave you). here also Once pure rolling started on horizontal surface the bottom point comes to rest hence there is no reason why friction should act · 9 months, 1 week ago

next did you find any horizontal force which is making it out of rolling in time dt. · 9 months, 1 week ago

in case of football field just after time t however long or small it may be the sphere will go on pure rolling, however it is not so here even after a small time dt the pure rolling is off. · 9 months, 1 week ago

i think i need some rest . i will talk to you tomorrow in this regard as i am feeling exhausted. thanks for taking out your precious time and having discussion in my silly concept · 9 months, 1 week ago

as much i know "no question is a silly question" · 9 months, 1 week ago

I Have Done The Following Analysis.

For Pure rolling on horizontal surface

Case.1 An external force is acting

In This case friction may or may not act. It All depends on the point of application of horizontal force.

Case 2. An External Is Not Acting

In This Case Friction Should Not act if body is continuing pure rolling. Because Friction will provide a and alpha in same direction hence a= R*Alpha can never be true.And once pure rolling started friction Friction will become zero so as the condition remains true (now a and alpha will become zero as there is no force) hence it will continue on to uniform pure rolling ( not accelerated )

External force does not includes friction

Is This analysis correct? · 9 months ago

absolutely correct. · 9 months ago

Thanks a lot @aryan goyat because of you my rolling concept became clear · 9 months ago

i told you earlier too no need of thanks. · 9 months ago

Ab to tujhe samajh me aa gaya? · 9 months ago

Yes i got it tujhe samjhana hi nahi aata :P · 9 months ago

Maybe i am not good at explaining · 9 months ago

not after first after second. · 9 months, 1 week ago

Yeah i meant first collision with rough ground · 9 months, 1 week ago

sorry i did not noticed the phrase "rough surface" . · 9 months, 1 week ago

no problem i just want your opinion on comparison in between two cases if i apply your explanation to our simple case of pure rolling on horizontal surface · 9 months, 1 week ago