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Tension in a charged ring.

A ring is positively charge with uniform linear charge density \(\lambda\) and radius \(r\) , now a positive charge \(q_0\) is placed at the center of the ring in the same plane.

Find the total tension after \( q_0\) is placed.

Permitivity of free space is \(\epsilon _0 \).

Hint: There will be tension due to two.

Note by Kushal Patankar
2 years, 7 months ago

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yes , tanishq's answer is absolutely correct ! ( i guess so )

Brilliant Member - 1 year ago

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I guess this is the answer.. T=kQq / 2.pi.R^2 But can you solve it and show..

Dibyanshu Patnaik - 2 years, 2 months ago

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Is it correct

\(T=\frac{\lambda q_{0}}{4\pi \epsilon_{o} r}\)

Tanishq Varshney - 2 years, 7 months ago

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It is not as simple you think .. If so then I'am sure Kushal don't post it .. Since that was very easy and standard problem .. :D

Karan Shekhawat - 2 years, 7 months ago

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Total tension will be developed due to electrostatic force by \(q_0\) and the ring.

If the question was to find the increase in tension when \(q_o\) was placed then your answer is correct.

Kushal Patankar - 2 years, 7 months ago

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