A ring is positively charge with uniform linear charge density \(\lambda\) and radius \(r\) , now a positive charge \(q_0\) is placed at the center of the ring in the same plane.

Find the total tension after \( q_0\) is placed.

Permitivity of free space is \(\epsilon _0 \).

Hint: There will be tension due to two.

## Comments

Sort by:

TopNewestI guess this is the answer.. T=kQq / 2.pi.R^2 But can you solve it and show.. – Dibyanshu Patnaik · 1 year ago

Log in to reply

Is it correct

\(T=\frac{\lambda q_{0}}{4\pi \epsilon_{o} r}\) – Tanishq Varshney · 1 year, 6 months ago

Log in to reply

– Karan Shekhawat · 1 year, 6 months ago

It is not as simple you think .. If so then I'am sure Kushal don't post it .. Since that was very easy and standard problem .. :DLog in to reply

ring.If the question was to find the increase in tension when \(q_o\) was placed then your answer is correct. – Kushal Patankar · 1 year, 6 months ago

Log in to reply