Tessellate S.T.E.M.S. (2019) - Computer Science - College - Set 4 - Subjective Problem 1

Rational Transductions

A rational transducer \(M\) is a 6-tuple \((S, \Sigma, \Delta, \tau, s_0, F)\), where \(S\) is a finite set of states, \(\Sigma\) and \(\Delta\) are input and output alphabets respectively, the transition relation \(\tau\) is a finite relation between \(S \times \Sigma^*\) and \(S \times \Delta^*\), \(s_0 \in S\) is the initial state and \(F\subseteq S\) is the set of final states.

For alphabets \(\Sigma, \Delta\), a transduction is a subset of \(\Sigma^*\times\Delta^*\). If \(A\) is a transducer as above, then \(\top (A)\) denotes its generated transduction, namely the set of all pairs \((u, v)\in X^*\times Y^*\) such that \((s_0, u, f, v)\in \tau\) for some \(f \in F\).

For a transduction \(T\subseteq X^*\times Y^*\) and a language \(L\subseteq X^*\), we write \[TL=\{v\in Y^*|\exists u\in L:(u,v)\in T\}\].

Prove/disprove the following statements:

  • Composition of two rational transductions is a rational transduction.
  • Inverse of a rational transduction is a rational transduction.
  • For a regular language \(R\subseteq X^*\) and a rational transduction \(T\subseteq X^*\times Y^*\), \(TR\) is regular.

This problem is a part of Tessellate S.T.E.M.S (2019)

Note by Tessellate Stems Computer Science
4 weeks, 1 day ago

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